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gmatophobia

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Updated on: 10 Apr 2023, 01:00

Originally posted by gmatophobia on 10 Apr 2023, 00:58.
Last edited by gmatophobia on 10 Apr 2023, 01:00, edited 1 time in total.

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gmatophobia

DS Question 1 - Apr 08 At a particular school, 60 male students play sports. How many male students attend the school? (1) At the school, 3/4 of the female students play sports. (2) At the school, 1/4 of the students do not play sports. Source: Other | Difficulty: Hard

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gmatophobia

PS Question 1 - Apr 08 Positive integer z leaves the remainder of 1 when divided by 3, the remainder of 3 when divided by 5 and the remainder of 5 when divided by 7. What is the smallest possible value of z? A. 101 B. 103 C. 105 D. 107 E. 208 Source: GMAT Club Tests | Difficulty: Medium

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PS Question 1 - Apr 10

A square countertop has a square tile inlay in the center, leaving an untiled strip of uniform width around the tile. If the ratio of the tiled area to the total area of the countertop is 9 to 16, which of the following could be the width, in inches, of the strip?

I. 3
II. 5
III. 6

A. I only
B. III only
C. I and II only
D. II and III only
E. I, II and III

Source: Official Guide | Difficulty: Medium

DS Question 1 - Apr 10

In the rectangular coordinate system, line k passes through the point (n, −1). Is the slope of line k greater than zero?

(1) Line k passes through the origin.
(2) Line k passes through the point (1, n + 2).

Source: Official Guide | Difficulty: Hard

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10 Apr 2023, 06:31

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Can anyone please suggest how I can improve my 700 level Combinations(Quant) solving skills? It seems like almost all the 700 level Official questions are 95% hard. They are bloody tough! I got 3 out of 8 right but not by actually solving the questions but by just using logic, and guessing so can’t count it as correct as I didn’t solve it. So I got all 8 wrong and by looking at the explanations, I don’t think I would have ever thought about those questions that way! Any suggestions on how I can improve my 700 level Combinations skills? Thanks.

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10 Apr 2023, 13:59

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gmatophobia

Could you please share the question number or the diagram(if any). I am getting a variable width of 0.5x, all answers will be true with this.

Ianstudyforgmat

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10 Apr 2023, 14:33

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gmatophobia

DS Question 1 - Apr 10 In the rectangular coordinate system, line k passes through the point (n, −1). Is the slope of line k greater than zero? (1) Line k passes through the origin. (2) Line k passes through the point (1, n + 2). Source: Official Guide | Difficulty: Hard

I need an explanation with picture for this please. I’m in urgent needs

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10 Apr 2023, 14:58

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Ianstudyforgmat

I need an explanation with picture for this please. I’m in urgent needs

I’ll try without pictures
you have 1 coordinate (n,-1)
stmt 1: gives you another coordinate (0,0); but what you have is parallel line to x axis, because still n is missing
stmt2: (1, n+2); doesn’t gives you the slope either m =y2-y1/x2-x1
1&2: you have 3 points, use slope formula-
m1=m2; you will get a quadratic eqn, solve it for n
n=-1

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10 Apr 2023, 17:12

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hey guys, can I get few kudos. I need 10 to reach next tier and avail Forum Quiz. Please look into my answers and explanations in the chat above, if you feel they are ok, kindly press the kudos. Thanks

gmatophobia

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10 Apr 2023, 22:19

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wickedvikram

Could you please share the question number or the diagram(if any). I am getting a variable width of 0.5x, all answers will be true with this.

Hi, The question posted on the chat is complete and there is no accompanying image in the published official question.
You can refer to the question here - a-square-countertop-has-a-square-tile-inlay-in-the-center-leaving-an-276050.html

gmatophobia

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Updated on: 10 Apr 2023, 22:46

Originally posted by gmatophobia on 10 Apr 2023, 22:33.
Last edited by gmatophobia on 10 Apr 2023, 22:46, edited 3 times in total.

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0Lucky0

Hey 0Lucky0

Thanks for posting your question.

The questions asked on the official exams on P&C are relatively easier than most of the questions discussed on the forum. Hence, don't get bogged down if you are getting the tough 'non-official' questions incorrect.

Having said that, you can use the principle of counting and filling space method to solve most, if not all, of the official questions. I would recommend that you try to visualize the problem as if you are performing the action. Doing so will help you solve questions with ease and you can use reasoning rather than formulas to ace the question.

Here are a couple of great articles by Bunuel and Other experts on P&C that you may want to give read -

combinatorics-made-easy-206266.html
learn-structured-approach-to-identify-permutation-combination-questi-263129.html
3-deadly-mistakes-in-permutation-and-combination-263721.html

Set of P&C practice questions by Narren-
practice-questions-of-combinations-and-probability-150387.html

Feel free to reach out with any additional questions.

gmatophobia

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gmatophobia

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DS Question 1 - Apr 11

If p, q and r are integers, and pq + r is an odd integer, is p an even integer?

(1) pq + pr is an even integer.
(2) p + qr is an odd integer.

Source: Expert’s Global | Difficulty: Hard

PS Question 1 - Apr 11

How many positive integers less than 10,000 are such that the product of their digits is 30?

A. 12
B. 24
C. 36
D. 38
E. 50

Source: GMAT Club Tests | Difficulty: Hard

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10 Apr 2023, 22:55

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gmatophobia

Hey 0Lucky0 Thanks for posting your question. The questions asked on the official exams on P&C are relatively easier than most of the questions discussed on the forum. Hence, don’t get bogged down if you are getting the tough ’non-official’ questions incorrect. Having said that, you can use the principle of counting and filling space method to solve most, if not all, of the official questions. I would recommend that you try to visualize the problem as if you are performing the action. Doing so will help you solve questions with ease and you can use reasoning rather than formulas to ace the question. Here are a couple of great articles by Bunuel and Other experts on P&C that you may want to give read - combinatorics-made-easy-206266.html learn-structured-approach-to-identify-permutation-combination-questi-263129.html 3-deadly-mistakes-in-permutation-and-combination-263721.html Set of P&C practice questions by Narren- practice-questions-of-combinations-and-probability-150387.html Feel free to reach out with any additional questions.

Thanks.

But the thing is, I am only solving the Official questions and haven’t touched any non-official questions yet.

So I guess I am in for a tough ride.

Well, I agree that counting and filling space works but it takes too much time. If I end up spending 5 minutes just on 1 question then I wouldn’t have time for remaining questions. That’s why I wanted to improve my Combinations skills on tough questions somehow. I don’t really have any issues with medium level combinations questions, it’s just the tough ones where there are graphs and diagrams or some other crazy stuff. ie, mixing other skills/concepts into combinations questions. Those are what make my head spin.

But, after having thought about this, I think it’s because I haven’t yet mastered those other skills maybe? So that’s why I guess. Not sure.

gmatophobia

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11 Apr 2023, 00:09

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0Lucky0

Thanks.

But the thing is, I am only solving the Official questions and haven’t touched any non-official questions yet.

So I guess I am in for a tough ride.

But, after having thought about this, I think it’s because I haven’t yet mastered those other skills maybe? So that’s why I guess. Not sure.

You can share the question on this group so that someone can help you with the reasoning or their thought process.

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Updated on: 11 Apr 2023, 01:29

Originally posted by mysterymanrog on 11 Apr 2023, 01:22.
Last edited by mysterymanrog on 11 Apr 2023, 01:29, edited 1 time in total.

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gmatophobia

PS Question 1 - Apr 11 How many positive integers less than 10,000 are such that the product of their digits is 30? A. 12 B. 24 C. 36 D. 38 E. 50 Source: GMAT Club Tests | Difficulty: Hard

Ways to create 30:
30*1
15*2
6*5
2*3*5
Now, there is no overlap between the ways to create 30 - so this makes the question easier.
Also note it is the product of their digits - so there cannot be a 0, otherwise it is 0. This excludes 30*1 from the list.
The above also tells us that the numbers may not have any 0s in between them. So something like 1520 is not possible.
that leaves:
ways to arrange 2,3,5=3!=6
ways to arrange 6*5=2!=2
ways to arrange 1,5,2=3!=6
Also consider adding a few 1s:
ways to arrange 1,1,5,2=4!/2!=24/2=12
ways to arrange 1,6,5=3!=6
ways to arrange 1,2,3,5=4!=24
and also
1,1,6,5=4!/2!-12.
For a sum of: 6+2+6+12+6+24+12=68

the logic is correct but I am doing something wrong

gmatophobia

Easy way to do this:
Eliminate A since it would give remainder 2 when divided by 3 rather than remainder 1.
Eliminate C since that divides evenly into 5.
Eliminate D for the same reasons as A - R2 when divided by 3 rather than R1.
That leaves B and E.
E divided by 5 gives a remainder of 3 when divided by 5, and when divided by 7 it is 5. E matches all the rules.
B: 103/7 gives remainder 5, and 103/5 gives remainder 3.

Since we are looking for the smallest value and both B and E work, it must be B.

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11 Apr 2023, 02:44

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mysterymanrog

Ways to create 30: 30*1 15*2 6*5 2*3*5 Now, there is no overlap between the ways to create 30 - so this makes the question easier. Also note it is the product of their digits - so there cannot be a 0, otherwise it is 0. This excludes 30*1 from the list. The above also tells us that the numbers may not have any 0s in between them. So something like 1520 is not possible. that leaves: ways to arrange 2,3,5=3!=6 ways to arrange 6*5=2!=2 ways to arrange 1,5,2=3!=6 Also consider adding a few 1s: ways to arrange 1,1,5,2=4!/2!=24/2=12 ways to arrange 1,6,5=3!=6 ways to arrange 1,2,3,5=4!=24 and also 1,1,6,5=4!/2!-12. For a sum of: 6+2+6+12+6+24+12=68

say 2,3,5 and 1,2,3,5 combos will mean the same thing as we are anyway multiplying the digits to make product as 30, so one of the digit has to be "1" in either case

also, i see you are taking 1,1,5,2 as one of the combinations. but note that this will not give the product of all digits as 30

if we remove these cases then final answer should be 68-6-12 = 50

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Updated on: 11 Apr 2023, 03:01

Originally posted by AbhinavKumar on 11 Apr 2023, 02:56.
Last edited by AbhinavKumar on 11 Apr 2023, 03:01, edited 1 time in total.

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mysterymanrog

the logic is correct but I am doing something wrong

so your 1,2,3,5 and 2,3,5 are overlapping (because even if not mentioning "1" we ought one of the digit as "1")

also 1,1,5,2 and 1,5,2 are overlapping as well as not a valid case

but since I now realized

that you meant 1,2,3,5 and 2,3,5 are four-digit and three-digit numbers separately, then we only ought to remove 1,1,5,2 and 1,5,2 cases ie. a total of 12+6 cases from 68

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Updated on: 11 Apr 2023, 04:59

Originally posted by wickedvikram on 11 Apr 2023, 04:44.
Last edited by wickedvikram on 11 Apr 2023, 04:59, edited 3 times in total.

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gmatophobia

A
Q Stem: Pq+r is odd
P/&Q - Even, R -Odd OR
P&Q - Odd, R -Even
Stmt 1: P(Q+R) is Even
Combine with Q stem
P - Even, R - Odd. OR
P- Odd, Q&R - Even or Q&R - Odd; Both contradict Q stem

gmatophobia

PS Question 1 - Apr 11 How many positive integers less than 10,000 are such that the product of their digits is 30? A. 12 B. 24 C. 36 D. 38 E. 50 Source: GMAT Club Tests | Difficulty: Hard

factors possible (5,6) & (2,3,5)
1 digit - Not Possible
2 digits - (5,6) = 2!
3 digits - (2,3,5) = 3!
(1,5,6) = 3!
4 digits - (1,2,3,5) = 4!
(1,1,5,6)=4!/2!
Total=50

mysterymanrog

Ways to create 30: 30*1 15*2 6*5 2*3*5 Now, there is no overlap between the ways to create 30 - so this makes the question easier. Also note it is the product of their digits - so there cannot be a 0, otherwise it is 0. This excludes 30*1 from the list. The above also tells us that the numbers may not have any 0s in between them. So something like 1520 is not possible. that leaves: ways to arrange 2,3,5=3!=6 ways to arrange 6*5=2!=2 ways to arrange 1,5,2=3!=6 Also consider adding a few 1s: ways to arrange 1,1,5,2=4!/2!=24/2=12 ways to arrange 1,6,5=3!=6 ways to arrange 1,2,3,5=4!=24 and also 1,1,6,5=4!/2!-12. For a sum of: 6+2+6+12+6+24+12=68

you can’t have (1,2,5) or (1,1,2,5)
I think you misread the question. product is supposed to be 30

wickedvikram

A Q Stem: Pq+r is odd P/&Q - Even, R -Odd OR P&Q - Odd, R -Even Stmt 1: P(Q+R) is Even Combine with Q stem P - Even, R - Odd. OR P- Odd, Q&R - Even or Q&R - Odd; Both contradict Q stem

Forgot stmt 2

:
here, when P is odd, at least one out of Q, R needs to be Even. this is possible without contradicting q stem
also, p can be even with both Q&R odd without contradiction

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11 Apr 2023, 06:05

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mysterymanrog

the logic is correct but I am doing something wrong

I would do this by segregating the three digit and four digit numbers. I believe you’re double counting cases. Well tried !

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Updated on: 12 Apr 2023, 00:08

Originally posted by gmatophobia on 12 Apr 2023, 00:04.
Last edited by gmatophobia on 12 Apr 2023, 00:08, edited 1 time in total.

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gmatophobia

PS Question 1 - Apr 11 How many positive integers less than 10,000 are such that the product of their digits is 30? A. 12 B. 24 C. 36 D. 38 E. 50 Source: GMAT Club Tests | Difficulty: Hard

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DS Question 1 - Apr 12

A bookstore bought 24 books, each at an equal price. Each of the first 20 books was sold at the same price and each of the remaining 4 books was sold at a 50% higher price. Was the profit on the sale of 24 books greater than $240?

(A) The profit on each of the 20 books was $10.

(B) If the selling price had been $4 more per book for all 24 books, the overall profit would have been $376.

Source: GMATWhiz | Difficulty: Hard

PS Question 1 - Apr 12

The median of 5 numbers is 50, and their range is 40. If the median of the 3 smallest numbers is 40, which of the following could be the range of the 3 largest numbers?

I. 0
II. 20
III. 40

A. I only
B. II only
C. I & II only
D.I & III only
E. I, II & III

Source: Math Revolution | Difficulty: Medium

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Updated on: 12 Apr 2023, 00:41

Originally posted by AbhinavKumar on 12 Apr 2023, 00:35.
Last edited by AbhinavKumar on 12 Apr 2023, 00:41, edited 1 time in total.

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gmatophobia

either B or D. lets go with D

gmatophobia

PS Question 1 - Apr 12 The median of 5 numbers is 50, and their range is 40. If the median of the 3 smallest numbers is 40, which of the following could be the range of the 3 largest numbers? I. 0 II. 20 III. 40 A. I only B. II only C. I & II only D.I & III only E. I, II & III Source: Math Revolution | Difficulty: Medium

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Updated on: 12 Apr 2023, 00:44

Originally posted by wickedvikram on 12 Apr 2023, 00:41.
Last edited by wickedvikram on 12 Apr 2023, 00:44, edited 1 time in total.

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wickedvikram

let CP be x and SP be y for each book
for 24, 24x & 20y+4*3y/2=26y
26y-24x>240
stmt1: y-x =10
24(y-x)=240
hence 2y+240 is greater than 240
stmt2: 20(y+4)+4*3/2*(y+4)=26y+104
26y+104-24x=376
26y-24x=272

wickedvikram

10, 40, 50, 50, 50 : Range 0
30, 40, 50, 50, 70 : Range 20
range 40 is not possible since 2nd element is smaller than 3rd element and range of 5 elements 50

***range of 5 elements 40

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Updated on: 13 Apr 2023, 00:48

Originally posted by blackswan33 on 13 Apr 2023, 00:46.
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wickedvikram

let CP be x and SP be y for each book for 24, 24x & 20y+4*3y/2=26y 26y-24x>240 stmt1: y-x =10 24(y-x)=240 hence 2y+240 is greater than 240 stmt2: 20(y+4)+4*3/2*(y+4)=26y+104 26y+104-24x=376 26y-24x=272

hey could you please explain why you put 24 (y-x) instead of 20 (y-x) as the statement suggests that the profit on each of the 20 books was 20.

hey could you please explain why you put 24 (y-x) instead of 20 (y-x) as the statement suggests that the profit on each of the 20 books was *10*, sorry

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Updated on: 13 Apr 2023, 02:55

Originally posted by wickedvikram on 13 Apr 2023, 02:51.
Last edited by wickedvikram on 13 Apr 2023, 02:55, edited 1 time in total.

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blackswan33

hey could you please explain why you put 24 (y-x) instead of 20 (y-x) as the statement suggests that the profit on each of the 20 books was *10*, sorry

I solved the total SP for 20 & 4 books together
i.e. 20(books) y(SP for 20)+4(books)*3y/2(SP for 4)=26y
I need, 26y-24x > 240
statement 1 only gives me y-x,
26y-24x= 2y+24y-24x=2y+24*10=2y+240
since y (SP) can’t be less than 10 (profit amount), I am getting a number above 260

Also, when the CP is same for all 24 books and SP is at a profit of $10 for 20 books. Profit of remaining 4 books will be higher as SP 1.5 times

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Emory powers growth—professionally and personally. Built on a foundation of interdisciplinary learning, leadership development, and career readiness, our top-20 MBA program delivers a high return on investment with top-5 career outcomes.

Tuck at Dartmouth

Step Inside the Tuck Experience: Discover Tuck Events This Fall
Current Tuck MBA students and Discover Tuck co-chairs share advice for prospective students and reflect on why they chose Tuck for their MBA.

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615 to 715 in 15 Days (Ria's Strategies)

More than Quant/Verbal Abilities: Speed vs. Accuracy

745 with Only Self-Prep and GMAT Club

From 555 to 765: 210-point Improvement

Perfect 805 Score Debrief by Julia

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