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02 Sep 2021, 21:33
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Hi I need help with this question. specifically part (b) and (d)
x and y are two integers such that−5(x^2+y) is a positive number. Determine whether each of the following expression is positive, negative, 0, or “No unique answer”.
a)y - negative
b)x+y - negative
c)−y - positive
d)x−y - positive
e)(x^2+y)/y - positive
f)x^2 - no unique answer
g)x^2+y^2 - positive
Thank you
x and y are two integers such that−5(x^2+y) is a positive number. Determine whether each of the following expression is positive, negative, 0, or “No unique answer”.
a)y - negative
b)x+y - negative
c)−y - positive
d)x−y - positive
e)(x^2+y)/y - positive
f)x^2 - no unique answer
g)x^2+y^2 - positive
Thank you
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02 Sep 2021, 21:53
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𝒙 and 𝒚 are two integers such that−5(𝒙^2+𝒚) is a positive number. Determine whether each of the following expression is positive, negative, 0, or “No unique answer”.
a)𝒚 - negative
b)𝒙+𝒚 - negative
c)−𝒚 - positive
d)𝒙−𝒚 - positive (INCORRECT: Must be No unique answer)
x could be negative. Note, square of a negative number is always positive.Also, it could be a very very large number, "negatively". and could make x-y a negative value. Since both positive and negative values are possible, the choice would be "No unique answer".
e)(𝒙^2+𝒚)/𝒚 - positive
[color=#ff0000]f)𝒙^2 - no unique answer (INCORRECT: Must be positive)
Irrespective of whether x is positive or negative integer, x^2 is always a positive integer.
[/color]
g)𝒙^2+𝒚^2 - positive
a)𝒚 - negative
b)𝒙+𝒚 - negative
c)−𝒚 - positive
d)𝒙−𝒚 - positive (INCORRECT: Must be No unique answer)
x could be negative. Note, square of a negative number is always positive.Also, it could be a very very large number, "negatively". and could make x-y a negative value. Since both positive and negative values are possible, the choice would be "No unique answer".
e)(𝒙^2+𝒚)/𝒚 - positive
[color=#ff0000]f)𝒙^2 - no unique answer (INCORRECT: Must be positive)
Irrespective of whether x is positive or negative integer, x^2 is always a positive integer.
[/color]
g)𝒙^2+𝒚^2 - positive
