|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
27 Oct 2019, 01:15
Kudos
Bookmarks
Hi ArvindCrackVerbal How should one approach a question like this? Although I feel confident when it comes to set questions, this one got me scratching my head.
On a certain transatlantic crossing, 20 percent of a ship's passengers held round-trip tickets and also took their cars aboard the ship. If 60 percent of the passengers with round-trip tickets did not take their cars aboard the ship, what percent of the ship's passengers held round-trip tickets?
(A) 33 1/3%
(B) 40%
(C) 50%
(D) 60%
(E) 66 2/3%
Thank You,
Dablu
On a certain transatlantic crossing, 20 percent of a ship's passengers held round-trip tickets and also took their cars aboard the ship. If 60 percent of the passengers with round-trip tickets did not take their cars aboard the ship, what percent of the ship's passengers held round-trip tickets?
(A) 33 1/3%
(B) 40%
(C) 50%
(D) 60%
(E) 66 2/3%
Thank You,
Dablu
27 Oct 2019, 04:56
Kudos
Bookmarks
Hi,
This question has already been discussed in below:
https://gmatclub.com/forum/on-a-certain ... ml#p482300
This question has already been discussed in below:
https://gmatclub.com/forum/on-a-certain ... ml#p482300
gurudabl
22 Nov 2019, 02:45
Kudos
Bookmarks
Hello Dablu,
In questions like these, you need to spend time on understanding what could be the reference value on which the percentage values could be applied. I want you to know that percentage values themselves do not mean anything unless you apply them on a reference value.
In this question, I'd take the reference value as the number of people who had round tickets. Since 60% is \(\frac{3}{5}\), I would take 50 as the total number of people who bought round tickets. This means that 30 of them did not take their cars aboard the ship. This leaves us with 20 who HAD round tickets and TOOK their cars aboard the ship.
But the question says that 20% of the total passengers HAD round tickets and TOOK their cars aboard the ship. This means the 20 in the paragraph above represents 20% of the total passengers.
Hence, total passengers = 100.
Passengers with round tickets = 30 + 20 = 50.
Required percentage = \(\frac{50}{100}\) = \(\frac{1}{2}\) = 50%.
The correct answer option is C.
Hope that helps!
In questions like these, you need to spend time on understanding what could be the reference value on which the percentage values could be applied. I want you to know that percentage values themselves do not mean anything unless you apply them on a reference value.
In this question, I'd take the reference value as the number of people who had round tickets. Since 60% is \(\frac{3}{5}\), I would take 50 as the total number of people who bought round tickets. This means that 30 of them did not take their cars aboard the ship. This leaves us with 20 who HAD round tickets and TOOK their cars aboard the ship.
But the question says that 20% of the total passengers HAD round tickets and TOOK their cars aboard the ship. This means the 20 in the paragraph above represents 20% of the total passengers.
Hence, total passengers = 100.
Passengers with round tickets = 30 + 20 = 50.
Required percentage = \(\frac{50}{100}\) = \(\frac{1}{2}\) = 50%.
The correct answer option is C.
Hope that helps!
