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# Some part of the 50% solution of acid was replaced with the

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Intern
Joined: 27 Sep 2008
Posts: 14
Some part of the 50% solution of acid was replaced with the [#permalink]

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03 Oct 2008, 23:17
1
Some part of the 50% solution of acid was replaced with the equal amount of 30% solution of acid. As a result, 40% solution of acid was obtained. What part of the original solution was replaced?

* $$\frac{1}{5}$$
* $$\frac{1}{4}$$
* $$\frac{1}{2}$$
* $$\frac{3}{4}$$
* $$\frac{4}{5}$$

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Manager
Joined: 27 Sep 2008
Posts: 76
Re: Math Problem on Solutions [#permalink]

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03 Oct 2008, 23:27

the answer is (C) - 1/2

Intern
Joined: 27 Sep 2008
Posts: 14
Re: Math Problem on Solutions [#permalink]

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04 Oct 2008, 02:57
1
would someone please give an explanation to the answer for the problem. Thanks
Manager
Joined: 27 Sep 2008
Posts: 76
Re: Math Problem on Solutions [#permalink]

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04 Oct 2008, 03:00
1
ast wrote:
would someone please give an explanation to the answer for the problem. Thanks

In the old solution you had two parts of the 50% solution (out of possible two) - in the new solution the you have only one part out of two - meaning you replaced 50% of the solution or 1/2.

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If you would like to discuss this question please re-post it in the respective forum. Thank you!

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Re: Math Problem on Solutions   [#permalink] 04 Oct 2008, 03:00
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# Some part of the 50% solution of acid was replaced with the

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