Ekland
Stacy and Heather are 20 miles apart and walk towards each other along the same route. Stacy walks at constant rate that is 1 mile per hour faster than heather's constant rate of 5 miles/hour. If Heather starts her journey 24 minutes after Stacy, how far from the original destination has Heather walked when the two meet?
A)7 mile
B)8 mile
C)9 mile
D)10 mile
E) 12 mile
Deconstructing the QuestionTotal Distance = 20 miles.
Heather's Speed (\(R_h\)) = 5 mph.
Stacy's Speed (\(R_s\)) = 5 + 1 = 6 mph.
Time Lag: Heather starts 24 minutes after Stacy.
Step 1: Handle the Head StartConvert 24 minutes to hours: \(\frac{24}{60} = 0.4\) hours.
Distance Stacy covers alone: \(D_{start} = R_s \times t = 6 \times 0.4 = 2.4\) miles.
Remaining Distance between them when Heather starts:
\(D_{rem} = 20 - 2.4 = 17.6\) miles.
Step 2: Calculate Meeting TimeSince they are moving towards each other, add their speeds.
Relative Speed = \(6 + 5 = 11\) mph.
Time to meet (\(t\)) = \(\frac{Distance}{Relative Speed} = \frac{17.6}{11} = 1.6\) hours.
Step 3: Calculate Heather's DistanceHeather walked for exactly 1.6 hours.
Distance = \(Rate \times Time\)
Distance = \(5 \times 1.6 = 8\) miles.
Answer: B