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# Stacy and Heather are 20 miles apart and walk towards each other along

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Re: Stacy and Heather are 20 miles apart and walk towards each other along [#permalink]
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After 24 mins, Stacy travel 24/60*6=2.4m -> 6*t+5*t=20-2.4=17.6 -> t=17.6/11 -> Distance = 17.6/11*5=8
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Stacy and Heather are 20 miles apart and walk towards each other along [#permalink]
Nez wrote:
Stacy and Heather are 20 miles apart and walk towards each other along the same route. Stacy walks at constant rate that is 1 mile per hour faster than heather's constant rate of 5 miles/hour. If Heather starts her journey 24 minutes after Stacy, how far from the original destination has Heather walked when the two meet?

A)7 mile
B)8 mile
C)9 mile
D)10 mile
E) 12 mile

A lot of ways to solve this problem have already been discussed. The following is my way of solving it:

Stacy
Time Speed distance
X+24 1/10(miles/min) 20-y

Heather
Time Speed distance
X 1/12(miles/min) y

Thus,

Two equations formed by Speed = Distance/time
Y=8 miles.
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Re: Stacy and Heather are 20 miles apart and walk towards each other along [#permalink]
After 24 min, stancy travels 2.4

Now, distance becomes 17.6

Thus,

D=17.6/11 *5=8 m
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Re: Stacy and Heather are 20 miles apart and walk towards each other along [#permalink]
1
Kudos
Since Stacey already covered a distance which is (6 mile/hr * 24 min) = 2.4 mile
The remaining distance is (20 - 2.4) = 17.6 mile which will be covered in 17.6 / 11(6+5) = 1.6 hr
And, in that 1.6 hr H will cover 1.6 * 5 = 8 miles.
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Re: Stacy and Heather are 20 miles apart and walk towards each other along [#permalink]
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Re: Stacy and Heather are 20 miles apart and walk towards each other along [#permalink]
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