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Updated on: 13 Aug 2018, 05:20
Originally posted by creativeminddu on 19 Nov 2013, 02:56.
Last edited by nightblade354 on 13 Aug 2018, 05:20, edited 3 times in total.
Last edited by nightblade354 on 13 Aug 2018, 05:20, edited 3 times in total.
Reformatted question
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
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79% (02:00) correct
21%
(02:09)
wrong
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THIS IS A JUSTIFY QUESTION, NOT AN ASSUMPTION QUESTION. THIS WILL NOT APPEAR ON THE GMAT
Standard aluminum soft-drink cans do not vary in the amount of aluminum that they contain. Fifty percent of the aluminum contained in a certain group (M) of standard aluminum soft-drink cans was recycled from another group (L) of used, standard aluminum softdrink cans. Since all the cans in L were recycled into cans in M and since the amount of material other than aluminum in an aluminum can is negligible, it follows that M contains twice as many cans as L.
The conclusion of the argument follows logically if which one of the following is assumed?
(A) The aluminum in the cans of M cannot be recycled further.
(B) Recycled aluminum is of poorer quality than unrecycled aluminum.
(C) All of the aluminum in an aluminum can is recovered when the can is recycled.
(D) None of the soft-drink cans in group L had been made from recycled aluminum.
(E) Aluminum soft-drink cans are more easily recycled than are soft-drink cans made from other materials.
Source: LSAT
Standard aluminum soft-drink cans do not vary in the amount of aluminum that they contain. Fifty percent of the aluminum contained in a certain group (M) of standard aluminum soft-drink cans was recycled from another group (L) of used, standard aluminum softdrink cans. Since all the cans in L were recycled into cans in M and since the amount of material other than aluminum in an aluminum can is negligible, it follows that M contains twice as many cans as L.
The conclusion of the argument follows logically if which one of the following is assumed?
(A) The aluminum in the cans of M cannot be recycled further.
(B) Recycled aluminum is of poorer quality than unrecycled aluminum.
(C) All of the aluminum in an aluminum can is recovered when the can is recycled.
(D) None of the soft-drink cans in group L had been made from recycled aluminum.
(E) Aluminum soft-drink cans are more easily recycled than are soft-drink cans made from other materials.
Source: LSAT
25 Dec 2017, 11:47
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creativeminddu
"The argument is structured as follows:
Premise: 50% of the aluminum in M was recycled from another group (L) of used aluminum cans.
Premise: All the cans in L were recycled into cans in M (L M).
Premise: Aluminum cans don't contain much of anything else, other than aluminum, and don't vary in the amount of aluminum that they contain.
Conclusion: M contains twice as many cans as L (M = 2*L)
At first glance, the argument seems reasonable. Let's say there are 100 used cans (L = 100), all of which were recycled into M cans. However, only half of the aluminum in the M cans came from L: the other half must have come from somewhere else. Clearly, then, assuming that the cans don't vary in the amount of aluminum they contain, and don't contain any other materials, the M group must be twice as big as the L group (M = 200).
One piece is missing for this argument to be bullet-proof: we need to assume that there is no loss of aluminum during recycling. If there was, and the 100 L cans provided 50% of the aluminum in M, then the M group would be less than twice the size of the L group. This prephrase agrees with answer choice (C). Although this is a Justify question, answer choice (C) is both sufficient, and necessary, for the conclusion to be logically valid. In other words, answer choice (C) would have been also correct if this were an Assumption question.
Answer choice (A) is incorrect, because whether the aluminum in M can be further recycled or not has no bearing on the conclusion of the argument.
Answer choice (B) is incorrect, because the quality of the aluminum used is entirely irrelevant to this argument.
Answer choice (C) is the correct answer choice, as explained above.
Answer choice (D) is incorrect, because the source of aluminum in L has no bearing on its ability to be recycled into M.
Answer choice (E) is incorrect, because it is entirely outside the scope of the argument. How aluminum compares to other materials in terms of recycling has no bearing on this conclusion."
(https://forum.powerscore.com/lsat/viewtopic.php?t=11056)
General Discussion
05 Dec 2013, 00:53
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creativeminddu
There is a wording error in the question above. The conclusion wording should have been "it follows that M contains twice as many aluminium as in L."
Above question is an Assumption question. Here, the conclusion is talking about the aluminium content. So, we need to look at options that talk about it.
Clearly B,D and E are out of scope. We are left with A and C where, C is the clear winner.
So, the answer should be C.
