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Standard aluminum soft-drink cans do not vary

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Standard aluminum soft-drink cans do not vary  [#permalink]

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New post Updated on: 13 Aug 2018, 05:20
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  25% (medium)

Question Stats:

78% (01:40) correct 22% (01:58) wrong based on 584 sessions

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THIS IS A JUSTIFY QUESTION, NOT AN ASSUMPTION QUESTION. THIS WILL NOT APPEAR ON THE GMAT

Standard aluminum soft-drink cans do not vary in the amount of aluminum that they contain. Fifty percent of the aluminum contained in a certain group (M) of standard aluminum soft-drink cans was recycled from another group (L) of used, standard aluminum softdrink cans. Since all the cans in L were recycled into cans in M and since the amount of material other than aluminum in an aluminum can is negligible, it follows that M contains twice as many cans as L.

The conclusion of the argument follows logically if which one of the following is assumed?

(A) The aluminum in the cans of M cannot be recycled further.
(B) Recycled aluminum is of poorer quality than unrecycled aluminum.
(C) All of the aluminum in an aluminum can is recovered when the can is recycled.
(D) None of the soft-drink cans in group L had been made from recycled aluminum.
(E) Aluminum soft-drink cans are more easily recycled than are soft-drink cans made from other materials.

Source: LSAT

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Originally posted by creativeminddu on 19 Nov 2013, 02:56.
Last edited by nightblade354 on 13 Aug 2018, 05:20, edited 3 times in total.
Reformatted question
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Re: Standard aluminum soft-drink cans do not vary  [#permalink]

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New post 05 Dec 2013, 00:53
creativeminddu wrote:
Standard aluminum soft-drink cans do not vary in the amount of aluminum that they contain. Fifty percent of the aluminum contained in a certain group (M) of standard aluminum soft-drink cans was recycled from another group (L) of used, standard aluminum softdrink cans. Since all the cans in L were recycled into cans in M and since the amount of material other than aluminum in an aluminum can is negligible, it follows that M contains twice as many cans as L.
The conclusion of the argument follows logically if which one of the following is assumed?
(A) The aluminum in the cans of M cannot be recycled further.
(B) Recycled aluminum is of poorer quality than unrecycled aluminum.
(C) All of the aluminum in an aluminum can is recovered when the can is recycled.
(D) None of the soft-drink cans in group L had been made from recycled aluminum.
(E) Aluminum soft-drink cans are more easily recycled than are soft-drink cans made from
other materials.


There is a wording error in the question above. The conclusion wording should have been "it follows that M contains twice as many aluminium as in L."

Above question is an Assumption question. Here, the conclusion is talking about the aluminium content. So, we need to look at options that talk about it.
Clearly B,D and E are out of scope. We are left with A and C where, C is the clear winner.
So, the answer should be C.
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Re: Standard aluminum soft-drink cans do not vary  [#permalink]

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New post 05 Dec 2013, 01:13
creativeminddu wrote:
Standard aluminum soft-drink cans do not vary in the amount of aluminum that they contain. Fifty percent of the aluminum contained in a certain group (M) of standard aluminum soft-drink cans was recycled from another group (L) of used, standard aluminum softdrink cans. Since all the cans in L were recycled into cans in M and since the amount of material other than aluminum in an aluminum can is negligible, it follows that M contains twice as many cans as L


1. Standard cans do not vary in amount of Aluminium

2. 50% aluminium in M is recycled from L

3. All Cans of L are recycled to form M ----------> Amt of other material is less ---------- > M contains 200% Aluminium as L




The conclusion of the argument follows logically if which one of the following is assumed? - So this is basically an assumption question.

(A) The aluminium in the cans of M cannot be recycled further.

Nowehere it is mentioned that it can't be recycled further , OUT OF SCOPE.

(B) Recycled aluminum is of poorer quality than unrecycled aluminum.

OUT OF SCOPE - Its clearly mentioned that Cans of M are made from Recycled Cans of L

(C) All of the aluminum in an aluminum can is recovered when the can is recycled.

True , Aluminium can be recovered from Cans of L and it is used for making Cans of M. However the Underlined part seems too much may be 80% of Aluminium can be recovered.

Let's keep it aside and check the other options.

(D) None of the soft-drink cans in group L had been made from recycled aluminum.

Over emphasises , the situation might be that recycled aluminium of Can L is used for its own use as well as for Cans M. The sentence assumes too much and changes the direction of the logic presented in the passage.

(E) Aluminum soft-drink cans are more easily recycled than are soft-drink cans made from other materials.

OUT OF SCOPE - We have information only about aluminium cans ...



Among the given answer choices (C) is the best , so the answer is (C)
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Re: Standard aluminum soft-drink cans do not vary  [#permalink]

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New post 22 Sep 2017, 09:43
this is a common in gmat, test takers should learn this. That is, the group is twice, or 3 times as many as the other group.

Another way is to Uuse POE, only C is left.
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Re: Standard aluminum soft-drink cans do not vary  [#permalink]

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New post 25 Dec 2017, 11:47
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creativeminddu wrote:
Standard aluminum soft-drink cans do not vary in the amount of aluminum that they contain. Fifty percent of the aluminum contained in a certain group (M) of standard aluminum soft-drink cans was recycled from another group (L) of used, standard aluminum softdrink cans. Since all the cans in L were recycled into cans in M and since the amount of material other than aluminum in an aluminum can is negligible, it follows that M contains twice as many cans as L.

The conclusion of the argument follows logically if which one of the following is assumed?

(A) The aluminum in the cans of M cannot be recycled further.
(B) Recycled aluminum is of poorer quality than unrecycled aluminum.
(C) All of the aluminum in an aluminum can is recovered when the can is recycled.
(D) None of the soft-drink cans in group L had been made from recycled aluminum.
(E) Aluminum soft-drink cans are more easily recycled than are soft-drink cans made from other materials.

Source: LSAT


"The argument is structured as follows:

Premise: 50% of the aluminum in M was recycled from another group (L) of used aluminum cans.
Premise: All the cans in L were recycled into cans in M (L M).
Premise: Aluminum cans don't contain much of anything else, other than aluminum, and don't vary in the amount of aluminum that they contain.

Conclusion: M contains twice as many cans as L (M = 2*L)

At first glance, the argument seems reasonable. Let's say there are 100 used cans (L = 100), all of which were recycled into M cans. However, only half of the aluminum in the M cans came from L: the other half must have come from somewhere else. Clearly, then, assuming that the cans don't vary in the amount of aluminum they contain, and don't contain any other materials, the M group must be twice as big as the L group (M = 200).

One piece is missing for this argument to be bullet-proof: we need to assume that there is no loss of aluminum during recycling. If there was, and the 100 L cans provided 50% of the aluminum in M, then the M group would be less than twice the size of the L group. This prephrase agrees with answer choice (C). Although this is a Justify question, answer choice (C) is both sufficient, and necessary, for the conclusion to be logically valid. In other words, answer choice (C) would have been also correct if this were an Assumption question.

Answer choice (A) is incorrect, because whether the aluminum in M can be further recycled or not has no bearing on the conclusion of the argument.

Answer choice (B) is incorrect, because the quality of the aluminum used is entirely irrelevant to this argument.

Answer choice (C) is the correct answer choice, as explained above.

Answer choice (D) is incorrect, because the source of aluminum in L has no bearing on its ability to be recycled into M.

Answer choice (E) is incorrect, because it is entirely outside the scope of the argument. How aluminum compares to other materials in terms of recycling has no bearing on this conclusion."
(https://forum.powerscore.com/lsat/viewtopic.php?t=11056)
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Re: Standard aluminum soft-drink cans do not vary  [#permalink]

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New post 13 Aug 2018, 00:11
generis GMATNinja KarishmaB nightblade354 GMATNinjaTwo

Can you advise on using negation for C/ D?

Quote:
The conclusion of the argument follows logically if which one of the following is assumed?

This is an assumption question.

Quote:
Standard aluminum soft-drink cans do not vary in the amount of aluminum that they contain. Fifty percent of the aluminum contained in a certain group (M) of standard aluminum soft-drink cans was recycled from another group (L) of used, standard aluminum softdrink cans. Since all the cans in L were recycled into cans in M and since the amount of material other than aluminum in an aluminium can is negligible, it follows that M contains twice as many cans as L.

Start with the conclusion: M = 2 L
Why:
M formed from L
M = L , elements other than aluminium are negligible in L and M.

Quote:
(C) All of the aluminum in an aluminum can is recovered when the can is recycled.

Negation: Some of aluminum in an aluminum can is recovered when the can is recycled.
I first discarded this since I thought I wanted to compare L and M in my answer choice.
Is not this choice only talking about M ?

Quote:
(D) None of the soft-drink cans in group L had been made from recycled aluminum.

Negation: Some of the soft-drink cans in group L had been made from recycled aluminum.
Hmm the only reason I can see to discard this is some. Since some does not destroy the
conclusion as much as most (remember an assumption must break the conclusion), hence this choice
is incorrect. I do think the source of aluminium in L is of relevant context in the argument.
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Re: Standard aluminum soft-drink cans do not vary  [#permalink]

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New post 13 Aug 2018, 05:21
adkikani wrote:
generis GMATNinja KarishmaB nightblade354 GMATNinjaTwo

Can you advise on using negation for C/ D?

Quote:
The conclusion of the argument follows logically if which one of the following is assumed?

This is an assumption question.

Quote:
Standard aluminum soft-drink cans do not vary in the amount of aluminum that they contain. Fifty percent of the aluminum contained in a certain group (M) of standard aluminum soft-drink cans was recycled from another group (L) of used, standard aluminum softdrink cans. Since all the cans in L were recycled into cans in M and since the amount of material other than aluminum in an aluminium can is negligible, it follows that M contains twice as many cans as L.

Start with the conclusion: M = 2 L
Why:
M formed from L
M = L , elements other than aluminium are negligible in L and M.

Quote:
(C) All of the aluminum in an aluminum can is recovered when the can is recycled.

Negation: Some of aluminum in an aluminum can is recovered when the can is recycled.
I first discarded this since I thought I wanted to compare L and M in my answer choice.
Is not this choice only talking about M ?

Quote:
(D) None of the soft-drink cans in group L had been made from recycled aluminum.

Negation: Some of the soft-drink cans in group L had been made from recycled aluminum.
Hmm the only reason I can see to discard this is some. Since some does not destroy the
conclusion as much as most (remember an assumption must break the conclusion), hence this choice
is incorrect. I do think the source of aluminium in L is of relevant context in the argument.


adkikani,

This is a justify question, not an assumption question. Negation will not work on this type of question. This type of question appears exclusively on the LSAT.

please see here for an explanation: https://forum.powerscore.com/lsat/viewtopic.php?t=11056
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Re: Standard aluminum soft-drink cans do not vary &nbs [#permalink] 13 Aug 2018, 05:21
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