Jul 26 08:00 AM PDT  09:00 AM PDT The Competition Continues  Game of Timers is a teambased competition based on solving GMAT questions to win epic prizes! Starting July 1st, compete to win prep materials while studying for GMAT! Registration is Open! Ends July 26th Jul 27 07:00 AM PDT  09:00 AM PDT Learn reading strategies that can help even nonvoracious reader to master GMAT RC Jul 28 07:00 PM EDT  08:00 PM EDT Strategies and techniques for approaching featured GMAT topics. Sunday, July 28th at 7 PM EDT
Author 
Message 
TAGS:

Hide Tags

Intern
Joined: 18 Dec 2006
Posts: 35

T is a set of y integers, where 0 < y < 7. If the average of
[#permalink]
Show Tags
Updated on: 05 Dec 2017, 14:40
Question Stats:
57% (02:19) correct 43% (01:49) wrong based on 497 sessions
HideShow timer Statistics
T is a set of y integers, where 0 < y < 7. If the average of Set T is the positive integer x, which of the following could NOT be the median of Set T? A. 0 B. x C. –x D. (1/3)y E. (2/7)y
Official Answer and Stats are available only to registered users. Register/ Login.
Originally posted by Zaur on 04 Apr 2009, 04:50.
Last edited by alexsr on 05 Dec 2017, 14:40, edited 4 times in total.
Edited the question and added the OA




Math Expert
Joined: 02 Sep 2009
Posts: 56319

Re: T is a set of y integers, where 0 < y < 7. If the average of
[#permalink]
Show Tags
25 Sep 2010, 10:28
Kronax wrote: How C) x could be the median? Set consists of elements from 1 to 6, the average x is positive, the median is negative which is impossible due to the range from 1 to 6. Phrase "T is a set of y integers, where 0 < y < 7" doesn't mean that T consist of elements from 1 to 6, it means that number of elements in T is from 1 to 6. T is a set of y integers, where 0 < y < 7. If the average of Set T is the positive integer x, which of the following could NOT be the median of Set T? A. \(0\) > if \(T=\{0, 0, 3\}\) then \(mean=x=1\) and \(median=0\); B. \(x\) > if \(T=\{3\}\) then \(mean=x=3\) and \(median=x=3\); C. \(x\) > if \(T=\{1, 1, 5\}\) then \(mean=x=1\) and \(median=x=1\); D. \(\frac{1}{3}y\) > if \(T=\{1, 1, 1\}\) then \(mean=x=1\), \(# \ of \ elements=y=3\) and \(median=\frac{1}{3}y=1\); E. \(\frac{2}{7}y\) > now, as T is a set of integers then the median is either a middle term, so \(integer\) OR the average of two middle terms so \(\frac{integer}{2}\), but as \(y\) is an integer from 1 to 6 then \(\frac{2}{7}y\) is neither an \(integer\) nor \(\frac{integer}{2}\). So \(\frac{2}{7}y\) could not be the median. Answer: E. Hope it's clear.
_________________




SVP
Joined: 29 Aug 2007
Posts: 2240

Re: T is a set of y integers, where 0 < y < 7. If the average of
[#permalink]
Show Tags
04 Apr 2009, 22:48
Zaur wrote: T is a set of y integers, where 0 < y < 7. If the average of Set T is the positive integer x, which of the following could NOT be the median of Set T?
a) 0 b) x c) –x d) (1/3)y e) (2/7)y
thanks in advance Its E, which is neither an integer nor a multiple of 0.5. Since the set T's elements are integers, median should be either an integer or a multiple of 0.5.
_________________
Verbal: http://gmatclub.com/forum/newtotheverbalforumpleasereadthisfirst77546.html Math: http://gmatclub.com/forum/newtothemathforumpleasereadthisfirst77764.html Gmat: http://gmatclub.com/forum/everythingyouneedtoprepareforthegmatrevised77983.html
GT



Director
Joined: 01 Apr 2008
Posts: 723
Name: Ronak Amin
Schools: IIM Lucknow (IPMX)  Class of 2014

Re: T is a set of y integers, where 0 < y < 7. If the average of
[#permalink]
Show Tags
05 Apr 2009, 00:13
Hi Gmat tiger, You are right that the median should be either an integer or a multiple of 0.5 ( since the number of integers can be even) But then, 1/3 is also not an integer and not a multiple of 0.5 !! Couldnt get this GMAT TIGER wrote: Zaur wrote: T is a set of y integers, where 0 < y < 7. If the average of Set T is the positive integer x, which of the following could NOT be the median of Set T?
a) 0 b) x c) –x d) (1/3)y e) (2/7)y
thanks in advance Its E, which is neither an integer nor a multiple of 0.5. Since the set T's elements are integers, median should be either an integer or a multiple of 0.5.



SVP
Joined: 29 Aug 2007
Posts: 2240

Re: T is a set of y integers, where 0 < y < 7. If the average of
[#permalink]
Show Tags
05 Apr 2009, 06:39
Economist wrote: Hi Gmat tiger, You are right that the median should be either an integer or a multiple of 0.5 ( since the number of integers can be even) But then, 1/3 is also not an integer and not a multiple of 0.5 !! Couldnt get this GMAT TIGER wrote: Zaur wrote: T is a set of y integers, where 0 < y < 7. If the average of Set T is the positive integer x, which of the following could NOT be the median of Set T?
a) 0 b) x c) –x d) (1/3)y e) (2/7)y
thanks in advance Its E, which is neither an integer nor a multiple of 0.5. Since the set T's elements are integers, median should be either an integer or a multiple of 0.5. y could be 2, 3, 4, 5, or 6. If y = either 3 or 6, y/3 is an integer.
_________________
Verbal: http://gmatclub.com/forum/newtotheverbalforumpleasereadthisfirst77546.html Math: http://gmatclub.com/forum/newtothemathforumpleasereadthisfirst77764.html Gmat: http://gmatclub.com/forum/everythingyouneedtoprepareforthegmatrevised77983.html
GT



Manager
Joined: 03 Feb 2010
Posts: 58

Re: T is a set of y integers, where 0 < y < 7. If the average of
[#permalink]
Show Tags
30 Apr 2010, 12:40
Can someone break down all the choices as to why they can be median?



Manager
Joined: 18 Mar 2010
Posts: 77
Location: United States

Re: T is a set of y integers, where 0 < y < 7. If the average of
[#permalink]
Show Tags
30 Apr 2010, 23:29
ksharma12 wrote: Can someone break down all the choices as to why they can be median? Rather than think about whether or not they can be the median, think about whether or not they could be an integer or a multiple of 0.5. a) 0 integerb) x could be an integer, all we know is that it's the averagec) –x same as bd) (1/3)y could be an integer if y=3 or y=6e) (2/7)y cannot be an integer or multiple of 0.5, as y is 1,2,3,4,5 or 6. Sufficient enough to answer the question



Intern
Joined: 27 Aug 2010
Posts: 20

Re: T is a set of y integers, where 0 < y < 7. If the average of
[#permalink]
Show Tags
25 Sep 2010, 09:47
How C) x could be the median? Set consists of elements from 1 to 6, the average x is positive, the median is negative which is impossible due to the range from 1 to 6.



Intern
Joined: 11 Jul 2012
Posts: 40

Re: T is a set of y integers, where 0 < y < 7. If the average of
[#permalink]
Show Tags
17 Oct 2012, 03:04
It's not always the case that E holds true. If T contains only one element, let's say 3. The mean is 3. The median OUGHT to be 3, never 3. So C is right. Can anyone help me out?



Director
Joined: 22 Mar 2011
Posts: 598
WE: Science (Education)

Re: T is a set of y integers, where 0 < y < 7. If the average of
[#permalink]
Show Tags
17 Oct 2012, 05:02
Ousmane wrote: It's not always the case that E holds true. If T contains only one element, let's say 3. The mean is 3. The median OUGHT to be 3, never 3. So C is right. Can anyone help me out? The question is "which of the following could NOT be the median of Set T?" It means we have to find the option for which the given number can NEVER be the median of Set T. So, \(3\) cannot be the median in your example, but there are many other cases when it can be. Set T contains integers, so negative numbers are not excluded. \(2/7y\) can never be an integer when \(0<y<7\), while the median MUST be an integer, doesn't matter what is \(y\) and what are the numbers in the set.
_________________
PhD in Applied Mathematics Love GMAT Quant questions and running.



Manager
Joined: 23 Jun 2009
Posts: 176
Location: Brazil
GMAT 1: 470 Q30 V20 GMAT 2: 620 Q42 V33

Re: T is a set of y integers, where 0 < y < 7. If the average of
[#permalink]
Show Tags
11 Nov 2016, 06:51
My visual contribution to the community
Attachments
Foto.png [ 790.07 KiB  Viewed 9747 times ]



Director
Joined: 26 Oct 2016
Posts: 626
Location: United States
Concentration: Marketing, International Business
GPA: 4
WE: Education (Education)

Re: T is a set of y integers, where 0 < y < 7. If the average of
[#permalink]
Show Tags
10 Dec 2016, 12:27
Median of the set has to be either an integer or an integer when multiplied by 2. Since 0 < y < 7, E doesn't satisfy either condition. Hence, E has to be the answer.
_________________
Thanks & Regards, Anaira Mitch



Senior SC Moderator
Joined: 14 Nov 2016
Posts: 1329
Location: Malaysia

Re: T is a set of y integers, where 0 < y < 7. If the average of
[#permalink]
Show Tags
23 Jan 2017, 16:19
Bunuel wrote: Kronax wrote: How C) x could be the median? Set consists of elements from 1 to 6, the average x is positive, the median is negative which is impossible due to the range from 1 to 6. Phrase "T is a set of y integers, where 0 < y < 7" doesn't mean that T consist of elements from 1 to 6, it means that number of elements in T is from 1 to 6. T is a set of y integers, where 0 < y < 7. If the average of Set T is the positive integer x, which of the following could NOT be the median of Set T? A. \(0\) > if \(T=\{0, 0, 3\}\) then \(mean=x=1\) and \(median=0\); B. \(x\) > if \(T=\{3\}\) then \(mean=x=3\) and \(median=x=3\); C. \(x\) > if \(T=\{1, 1, 5\}\) then \(mean=x=1\) and \(median=x=1\); D. \(\frac{1}{3}y\) > if \(T=\{1, 1, 1\}\) then \(mean=x=1\), \(# \ of \ elements=y=3\) and \(median=\frac{1}{3}y=1\); E. \(\frac{2}{7}y\) > now, as T is a set of integers then the median is either a middle term, so \(integer\) OR the average of two middle terms so \(\frac{integer}{2}\), but as \(y\) is an integer from 1 to 6 then \(\frac{2}{7}y\) is neither an \(integer\) nor \(\frac{integer}{2}\). So \(\frac{2}{7}y\) could not be the median. Answer: E. Hope it's clear. Dear Bunuel, Since Set T range from 1 to 6, why the sample of T from part C was T={1, 1, 5}?
_________________
"Be challenged at EVERY MOMENT."“Strength doesn’t come from what you can do. It comes from overcoming the things you once thought you couldn’t.”"Each stage of the journey is crucial to attaining new heights of knowledge."Rules for posting in verbal forum  Please DO NOT post short answer in your post! Advanced Search : https://gmatclub.com/forum/advancedsearch/



Math Expert
Joined: 02 Sep 2009
Posts: 56319

Re: T is a set of y integers, where 0 < y < 7. If the average of
[#permalink]
Show Tags
24 Jan 2017, 01:16
ziyuenlau wrote: Bunuel wrote: Kronax wrote: How C) x could be the median? Set consists of elements from 1 to 6, the average x is positive, the median is negative which is impossible due to the range from 1 to 6. Phrase "T is a set of y integers, where 0 < y < 7" doesn't mean that T consist of elements from 1 to 6, it means that number of elements in T is from 1 to 6. T is a set of y integers, where 0 < y < 7. If the average of Set T is the positive integer x, which of the following could NOT be the median of Set T? A. \(0\) > if \(T=\{0, 0, 3\}\) then \(mean=x=1\) and \(median=0\); B. \(x\) > if \(T=\{3\}\) then \(mean=x=3\) and \(median=x=3\); C. \(x\) > if \(T=\{1, 1, 5\}\) then \(mean=x=1\) and \(median=x=1\); D. \(\frac{1}{3}y\) > if \(T=\{1, 1, 1\}\) then \(mean=x=1\), \(# \ of \ elements=y=3\) and \(median=\frac{1}{3}y=1\); E. \(\frac{2}{7}y\) > now, as T is a set of integers then the median is either a middle term, so \(integer\) OR the average of two middle terms so \(\frac{integer}{2}\), but as \(y\) is an integer from 1 to 6 then \(\frac{2}{7}y\) is neither an \(integer\) nor \(\frac{integer}{2}\). So \(\frac{2}{7}y\) could not be the median. Answer: E. Hope it's clear. Dear Bunuel, Since Set T range from 1 to 6, why the sample of T from part C was T={1, 1, 5}? You are asking the same question: Phrase "T is a set of y integers, where 0 < y < 7" does NOT mean that T consist of elements from 1 to 6, it means that the number of elements (the number of terms) in T is from 1 to 6.
_________________



Current Student
Joined: 04 Aug 2015
Posts: 76
Location: India
Concentration: Leadership, Technology
GPA: 3.39

Re: T is a set of y integers, where 0 < y < 7. If the average of
[#permalink]
Show Tags
24 Jan 2017, 09:05
T is a set of y integers, where 0 < y < 7. If the average of Set T is the positive integer x, which of the following could NOT be the median of Set T?
A. 0 {1, 0, 4} mean(x)=1; median=0. Possible. B. x {1, 1, 1} mean(x)=1; median=1. Possible. C. –x {0, 1, 4} mean(x)=1; median=1. Possible. D. (1/3)y Let y be 3. Therefore, median=1 {1, 1, 1} mean(x)=1. Possible E. (2/7)y The median can either be an integer or multiple of 1/2. Not possible.



Retired Moderator
Joined: 17 Jun 2016
Posts: 503
Location: India
GMAT 1: 720 Q49 V39 GMAT 2: 710 Q50 V37
GPA: 3.65
WE: Engineering (Energy and Utilities)

Re: T is a set of y integers, where 0 < y < 7. If the average of
[#permalink]
Show Tags
08 May 2017, 02:53
Median can be 1. An Integer (if the median is one of the numbers in the set T) 2. A decimal of the form m.5 – where m is any number  (if the median is not one of the number in the set T and hence it is (3rd Term + 4th Term)/2) So from the above option : A. 0 possible as obvious B. x possible as obvious C. –x possible as obvious D. (1/3)y possible with y = 3 or 6 E. (2/7)y Not possible as (1/7)y is not an integer since Y cannot be 7 and also 1/7 is NOT equal to a decimal of the form m.5. So ans is E
_________________



EMPOWERgmat Instructor
Status: GMAT Assassin/CoFounder
Affiliations: EMPOWERgmat
Joined: 19 Dec 2014
Posts: 14609
Location: United States (CA)

Re: T is a set of y integers, where 0 < y < 7. If the average of
[#permalink]
Show Tags
16 Jan 2018, 13:11
Hi All, For this question, you can TEST VALUES to eliminate the 4 answers that COULD be the median of Set T. We're told that Set T consists of Y integers (where 0 < Y < 7) and that the AVERAGE = X = a POSITIVE INTEGER. We're asked which of the answers could NOT be the median. Answer A: 0... If Set T is {0,0,3} then the average = 1 and the median = 0. Eliminate A. Answer B: X... If Set T is {1,1,1} then the average = 1 and the median = 1 = X. Eliminate B. Answer C: X... If Set T is {1,1,5} then the average = 1 and the median = 1 = X. Eliminate C. Answer D: Y/3... If Set T is {1,1,1} then the average = 1 and the median = 1 = Y/3. Eliminate D. There's only one answer left... Final Answer: GMAT assassins aren't born, they're made, Rich
_________________
760+: Learn What GMAT Assassins Do to Score at the Highest Levels Contact Rich at: Rich.C@empowergmat.com*****Select EMPOWERgmat Courses now include ALL 6 Official GMAC CATs!*****
Rich Cohen
CoFounder & GMAT Assassin
Special Offer: Save $75 + GMAT Club Tests Free
Official GMAT Exam Packs + 70 Pt. Improvement Guarantee www.empowergmat.com/



Intern
Joined: 20 Dec 2018
Posts: 49

Re: T is a set of y integers, where 0 < y < 7. If the average of
[#permalink]
Show Tags
21 Dec 2018, 22:15
The set contains 16 elements. A. Consider a set {0, 0 ,6}. Here, mean = 2 and median = 0. B. Consider a set { x }. Here, mean = x and median = x C. Consider a set {1, 1, 5}. Here mean(x) = 1 and median = 1= x D.Consider a set {1, 1, 1}. Here mean = 1, y = 3 and median = 1 = y/3. E. T is a set of y integers where 0 < y < 7. All the elements in the set should be integers. So, the median also needs to be an integer. Now, if 2y/7 become the median it also needs to be an integer which is not possible for any possible value of y i.e. 1,2,3,4,5 or 6. Hence, 2y/7 can’t be the median.



Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 9453
Location: Pune, India

Re: T is a set of y integers, where 0 < y < 7. If the average of
[#permalink]
Show Tags
21 Dec 2018, 22:35
Zaur wrote: T is a set of y integers, where 0 < y < 7. If the average of Set T is the positive integer x, which of the following could NOT be the median of Set T?
A. 0 B. x C. –x D. (1/3)y E. (2/7)y Average of two integers will always be either an integer (if both are odd or both are even) or Integer/2 in lowest form (if one is odd and the other is even). The average can never be integer/7 in lowest terms. Since y is between 0 and 7 exclusive, y is not divisible by 7 and hence, (2/7)y will be (integer/7) in lowest terms. Median of a set of odd number of integers will be one of the integers. Median of a set of even number of integers will be the average of middle two integers. Hence, median cannot be of the form (2/7)y. Answer (E)
_________________
Karishma Veritas Prep GMAT Instructor
Learn more about how Veritas Prep can help you achieve a great GMAT score by checking out their GMAT Prep Options >



Target Test Prep Representative
Status: Founder & CEO
Affiliations: Target Test Prep
Joined: 14 Oct 2015
Posts: 6967
Location: United States (CA)

Re: T is a set of y integers, where 0 < y < 7. If the average of
[#permalink]
Show Tags
02 Mar 2019, 09:19
Zaur wrote: T is a set of y integers, where 0 < y < 7. If the average of Set T is the positive integer x, which of the following could NOT be the median of Set T?
A. 0 B. x C. –x D. (1/3)y E. (2/7)y Let’s analyze each answer choices using actual examples. A. 0 Let x = 1 and y = 3, then T = {1, 0, 4} has a median of 0. B. x Let x = 1 and y = 3, then T = {1, 1, 3} has a median of 1, which is x. C. x Let x = 1 and y = 3, then T = {2, 1, 6} has a median of 1, which is x. D. (1/3)y Let x = 1 and y = 3, then T = {1, 1, 3} has a median of 1, which is (1/3)y. Since we are looking for the one that could NOT be the median of Set T, then the correct answer must be E. Indeed, the median of a set of y integers is either an integer (if y is odd) or an integer divided by 2 (if y is even). For no integer value of y between 0 and 7 will the median be in the form (2/7)y. Answer: E
_________________
5star rated online GMAT quant self study course See why Target Test Prep is the top rated GMAT quant course on GMAT Club. Read Our Reviews If you find one of my posts helpful, please take a moment to click on the "Kudos" button.




Re: T is a set of y integers, where 0 < y < 7. If the average of
[#permalink]
02 Mar 2019, 09:19



Go to page
1 2
Next
[ 23 posts ]



