It is currently 21 Oct 2017, 18:27

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

T is a set of y integers, where 0 < y < 7. If the average of

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

3 KUDOS received
Intern
Intern
avatar
Joined: 18 Dec 2006
Posts: 39

Kudos [?]: 23 [3], given: 0

T is a set of y integers, where 0 < y < 7. If the average of [#permalink]

Show Tags

New post 04 Apr 2009, 04:50
3
This post received
KUDOS
21
This post was
BOOKMARKED
00:00
A
B
C
D
E

Difficulty:

  65% (hard)

Question Stats:

55% (01:24) correct 45% (00:57) wrong based on 552 sessions

HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

T is a set of y integers, where 0 < y < 7. If the average of Set T is the positive integer x, which of the following could NOT be the median of Set T?

A. 0
B. x
C. –x
D. (1/3)y
E. (2/7)y
[Reveal] Spoiler: OA

Last edited by Bunuel on 14 Mar 2016, 06:55, edited 3 times in total.
Edited the question and added the OA

Kudos [?]: 23 [3], given: 0

SVP
SVP
User avatar
Joined: 29 Aug 2007
Posts: 2472

Kudos [?]: 843 [0], given: 19

Re: T is a set of y integers, where 0 < y < 7. If the average of [#permalink]

Show Tags

New post 04 Apr 2009, 22:48
Zaur wrote:
T is a set of y integers, where 0 < y < 7. If the average of Set T is the positive integer x, which of the following could NOT be the median of Set T?

a) 0
b) x
c) –x
d) (1/3)y
e) (2/7)y

thanks in advance


Its E, which is neither an integer nor a multiple of 0.5. Since the set T's elements are integers, median should be either an integer or a multiple of 0.5.
_________________

Verbal: http://gmatclub.com/forum/new-to-the-verbal-forum-please-read-this-first-77546.html
Math: http://gmatclub.com/forum/new-to-the-math-forum-please-read-this-first-77764.html
Gmat: http://gmatclub.com/forum/everything-you-need-to-prepare-for-the-gmat-revised-77983.html


GT

Kudos [?]: 843 [0], given: 19

Director
Director
User avatar
Joined: 01 Apr 2008
Posts: 873

Kudos [?]: 844 [0], given: 18

Name: Ronak Amin
Schools: IIM Lucknow (IPMX) - Class of 2014
Re: T is a set of y integers, where 0 < y < 7. If the average of [#permalink]

Show Tags

New post 05 Apr 2009, 00:13
Hi Gmat tiger,
You are right that the median should be either an integer or a multiple of 0.5 ( since the number of integers can be even)
But then, 1/3 is also not an integer and not a multiple of 0.5 !! Couldnt get this :(

GMAT TIGER wrote:
Zaur wrote:
T is a set of y integers, where 0 < y < 7. If the average of Set T is the positive integer x, which of the following could NOT be the median of Set T?

a) 0
b) x
c) –x
d) (1/3)y
e) (2/7)y

thanks in advance


Its E, which is neither an integer nor a multiple of 0.5. Since the set T's elements are integers, median should be either an integer or a multiple of 0.5.

Kudos [?]: 844 [0], given: 18

SVP
SVP
User avatar
Joined: 29 Aug 2007
Posts: 2472

Kudos [?]: 843 [0], given: 19

Re: T is a set of y integers, where 0 < y < 7. If the average of [#permalink]

Show Tags

New post 05 Apr 2009, 06:39
Economist wrote:
Hi Gmat tiger,
You are right that the median should be either an integer or a multiple of 0.5 ( since the number of integers can be even)
But then, 1/3 is also not an integer and not a multiple of 0.5 !! Couldnt get this :(

GMAT TIGER wrote:
Zaur wrote:
T is a set of y integers, where 0 < y < 7. If the average of Set T is the positive integer x, which of the following could NOT be the median of Set T?

a) 0
b) x
c) –x
d) (1/3)y
e) (2/7)y

thanks in advance


Its E, which is neither an integer nor a multiple of 0.5. Since the set T's elements are integers, median should be either an integer or a multiple of 0.5.


y could be 2, 3, 4, 5, or 6. If y = either 3 or 6, y/3 is an integer.
_________________

Verbal: http://gmatclub.com/forum/new-to-the-verbal-forum-please-read-this-first-77546.html
Math: http://gmatclub.com/forum/new-to-the-math-forum-please-read-this-first-77764.html
Gmat: http://gmatclub.com/forum/everything-you-need-to-prepare-for-the-gmat-revised-77983.html


GT

Kudos [?]: 843 [0], given: 19

Manager
Manager
avatar
Joined: 11 Sep 2009
Posts: 96

Kudos [?]: 33 [0], given: 0

Re: T is a set of y integers, where 0 < y < 7. If the average of [#permalink]

Show Tags

New post 24 Oct 2009, 21:19
E too

Y/3 is possible if Y = 3 or 6

2Y/7 does not meet the criteria - the remainder must be 0 or 0.5

Kudos [?]: 33 [0], given: 0

Manager
Manager
avatar
Joined: 03 Feb 2010
Posts: 68

Kudos [?]: 149 [0], given: 4

Re: T is a set of y integers, where 0 < y < 7. If the average of [#permalink]

Show Tags

New post 30 Apr 2010, 12:40
Can someone break down all the choices as to why they can be median?

Kudos [?]: 149 [0], given: 4

Manager
Manager
avatar
Joined: 18 Mar 2010
Posts: 87

Kudos [?]: 73 [0], given: 5

Location: United States
Re: T is a set of y integers, where 0 < y < 7. If the average of [#permalink]

Show Tags

New post 30 Apr 2010, 23:29
1
This post was
BOOKMARKED
ksharma12 wrote:
Can someone break down all the choices as to why they can be median?


Rather than think about whether or not they can be the median, think about whether or not they could be an integer or a multiple of 0.5.

a) 0 integer
b) x could be an integer, all we know is that it's the average
c) –x same as b
d) (1/3)y could be an integer if y=3 or y=6
e) (2/7)y cannot be an integer or multiple of 0.5, as y is 1,2,3,4,5 or 6. Sufficient enough to answer the question

Kudos [?]: 73 [0], given: 5

Intern
Intern
avatar
Joined: 27 Aug 2010
Posts: 23

Kudos [?]: 20 [0], given: 2

Re: T is a set of y integers, where 0 < y < 7. If the average of [#permalink]

Show Tags

New post 25 Sep 2010, 09:47
How C) -x could be the median?
Set consists of elements from 1 to 6, the average x is positive, the median is negative which is impossible due to the range from 1 to 6.

Kudos [?]: 20 [0], given: 2

Expert Post
11 KUDOS received
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 41892

Kudos [?]: 129173 [11], given: 12194

Re: T is a set of y integers, where 0 < y < 7. If the average of [#permalink]

Show Tags

New post 25 Sep 2010, 10:28
11
This post received
KUDOS
Expert's post
9
This post was
BOOKMARKED
Kronax wrote:
How C) -x could be the median?
Set consists of elements from 1 to 6, the average x is positive, the median is negative which is impossible due to the range from 1 to 6.


Phrase "T is a set of y integers, where 0 < y < 7" doesn't mean that T consist of elements from 1 to 6, it means that number of elements in T is from 1 to 6.

T is a set of y integers, where 0 < y < 7. If the average of Set T is the positive integer x, which of the following could NOT be the median of Set T?

A. \(0\) --> if \(T=\{0, 0, 3\}\) then \(mean=x=1\) and \(median=0\);

B. \(x\) --> if \(T=\{3\}\) then \(mean=x=3\) and \(median=x=3\);

C. \(-x\) --> if \(T=\{-1, -1, 5\}\) then \(mean=x=1\) and \(median=-x=-1\);

D. \(\frac{1}{3}y\) --> if \(T=\{1, 1, 1\}\) then \(mean=x=1\), \(# \ of \ elements=y=3\) and \(median=\frac{1}{3}y=1\);

E. \(\frac{2}{7}y\) --> now, as T is a set of integers then the median is either a middle term, so \(integer\) OR the average of two middle terms so \(\frac{integer}{2}\), but as \(y\) is an integer from 1 to 6 then \(\frac{2}{7}y\) is neither an \(integer\) nor \(\frac{integer}{2}\). So \(\frac{2}{7}y\) could not be the median.

Answer: E.

Hope it's clear.
_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

Kudos [?]: 129173 [11], given: 12194

Intern
Intern
avatar
Joined: 27 Aug 2010
Posts: 23

Kudos [?]: 20 [0], given: 2

Re: T is a set of y integers, where 0 < y < 7. If the average of [#permalink]

Show Tags

New post 25 Sep 2010, 23:23
Thank you Bunuel, now its clear!

Kudos [?]: 20 [0], given: 2

Intern
Intern
avatar
Joined: 11 Jul 2012
Posts: 43

Kudos [?]: 7 [0], given: 0

Re: T is a set of y integers, where 0 < y < 7. If the average of [#permalink]

Show Tags

New post 17 Oct 2012, 03:04
It's not always the case that E holds true.
If T contains only one element, let's say 3. The mean is 3. The median OUGHT to be 3, never -3. So C is right.
Can anyone help me out?

Kudos [?]: 7 [0], given: 0

Director
Director
User avatar
Joined: 22 Mar 2011
Posts: 610

Kudos [?]: 1059 [0], given: 43

WE: Science (Education)
Re: T is a set of y integers, where 0 < y < 7. If the average of [#permalink]

Show Tags

New post 17 Oct 2012, 05:02
Ousmane wrote:
It's not always the case that E holds true.
If T contains only one element, let's say 3. The mean is 3. The median OUGHT to be 3, never -3. So C is right.
Can anyone help me out?


The question is "which of the following could NOT be the median of Set T?"
It means we have to find the option for which the given number can NEVER be the median of Set T.

So, \(-3\) cannot be the median in your example, but there are many other cases when it can be.
Set T contains integers, so negative numbers are not excluded.

\(2/7y\) can never be an integer when \(0<y<7\), while the median MUST be an integer, doesn't matter what is \(y\) and what are the numbers in the set.
_________________

PhD in Applied Mathematics
Love GMAT Quant questions and running.

Kudos [?]: 1059 [0], given: 43

Expert Post
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 41892

Kudos [?]: 129173 [0], given: 12194

Re: T is a set of y integers, where 0 < y < 7. If the average of [#permalink]

Show Tags

New post 23 Jul 2013, 01:55

Kudos [?]: 129173 [0], given: 12194

GMAT Club Legend
GMAT Club Legend
User avatar
Joined: 09 Sep 2013
Posts: 16587

Kudos [?]: 273 [0], given: 0

Premium Member
Re: T is a set of y integers, where 0 < y < 7. If the average of [#permalink]

Show Tags

New post 17 Aug 2014, 11:54
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

GMAT Books | GMAT Club Tests | Best Prices on GMAT Courses | GMAT Mobile App | Math Resources | Verbal Resources

Kudos [?]: 273 [0], given: 0

GMAT Club Legend
GMAT Club Legend
User avatar
Joined: 09 Sep 2013
Posts: 16587

Kudos [?]: 273 [0], given: 0

Premium Member
Re: T is a set of y integers, where 0 < y < 7. If the average of [#permalink]

Show Tags

New post 24 Nov 2015, 02:55
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

GMAT Books | GMAT Club Tests | Best Prices on GMAT Courses | GMAT Mobile App | Math Resources | Verbal Resources

Kudos [?]: 273 [0], given: 0

Manager
Manager
User avatar
B
Joined: 23 Jun 2009
Posts: 201

Kudos [?]: 101 [0], given: 138

Location: Brazil
GMAT 1: 470 Q30 V20
GMAT 2: 620 Q42 V33
GMAT ToolKit User Premium Member
Re: T is a set of y integers, where 0 < y < 7. If the average of [#permalink]

Show Tags

New post 11 Nov 2016, 06:51
My visual contribution to the community
Attachments

Foto.png
Foto.png [ 790.07 KiB | Viewed 3017 times ]

Kudos [?]: 101 [0], given: 138

Director
Director
User avatar
G
Joined: 26 Oct 2016
Posts: 693

Kudos [?]: 180 [0], given: 855

Location: United States
Concentration: Marketing, International Business
Schools: HBS '19
GMAT 1: 770 Q51 V44
GPA: 4
WE: Education (Education)
Re: T is a set of y integers, where 0 < y < 7. If the average of [#permalink]

Show Tags

New post 10 Dec 2016, 12:27
Median of the set has to be either an integer or an
integer when multiplied by 2. Since 0 < y < 7, E doesn't satisfy
either condition. Hence, E has to be the answer.
_________________

Thanks & Regards,
Anaira Mitch

Kudos [?]: 180 [0], given: 855

VP
VP
User avatar
D
Joined: 14 Nov 2016
Posts: 1174

Kudos [?]: 1183 [0], given: 415

Location: Malaysia
GMAT ToolKit User Premium Member CAT Tests
T is a set of y integers, where 0 < y < 7. If the average of [#permalink]

Show Tags

New post 23 Jan 2017, 16:19
Bunuel wrote:
Kronax wrote:
How C) -x could be the median?
Set consists of elements from 1 to 6, the average x is positive, the median is negative which is impossible due to the range from 1 to 6.


Phrase "T is a set of y integers, where 0 < y < 7" doesn't mean that T consist of elements from 1 to 6, it means that number of elements in T is from 1 to 6.

T is a set of y integers, where 0 < y < 7. If the average of Set T is the positive integer x, which of the following could NOT be the median of Set T?

A. \(0\) --> if \(T=\{0, 0, 3\}\) then \(mean=x=1\) and \(median=0\);

B. \(x\) --> if \(T=\{3\}\) then \(mean=x=3\) and \(median=x=3\);

C. \(-x\) --> if \(T=\{-1, -1, 5\}\) then \(mean=x=1\) and \(median=-x=-1\);

D. \(\frac{1}{3}y\) --> if \(T=\{1, 1, 1\}\) then \(mean=x=1\), \(# \ of \ elements=y=3\) and \(median=\frac{1}{3}y=1\);

E. \(\frac{2}{7}y\) --> now, as T is a set of integers then the median is either a middle term, so \(integer\) OR the average of two middle terms so \(\frac{integer}{2}\), but as \(y\) is an integer from 1 to 6 then \(\frac{2}{7}y\) is neither an \(integer\) nor \(\frac{integer}{2}\). So \(\frac{2}{7}y\) could not be the median.

Answer: E.

Hope it's clear.


Dear Bunuel,

Since Set T range from 1 to 6, why the sample of T from part C was T={-1, -1, 5}?
_________________

"Be challenged at EVERY MOMENT."

“Strength doesn’t come from what you can do. It comes from overcoming the things you once thought you couldn’t.”

"Each stage of the journey is crucial to attaining new heights of knowledge."

Rules for posting in verbal forum | Please DO NOT post short answer in your post!

Kudos [?]: 1183 [0], given: 415

Expert Post
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 41892

Kudos [?]: 129173 [0], given: 12194

Re: T is a set of y integers, where 0 < y < 7. If the average of [#permalink]

Show Tags

New post 24 Jan 2017, 01:16
Expert's post
1
This post was
BOOKMARKED
ziyuenlau wrote:
Bunuel wrote:
Kronax wrote:
How C) -x could be the median?
Set consists of elements from 1 to 6, the average x is positive, the median is negative which is impossible due to the range from 1 to 6.


Phrase "T is a set of y integers, where 0 < y < 7" doesn't mean that T consist of elements from 1 to 6, it means that number of elements in T is from 1 to 6.

T is a set of y integers, where 0 < y < 7. If the average of Set T is the positive integer x, which of the following could NOT be the median of Set T?

A. \(0\) --> if \(T=\{0, 0, 3\}\) then \(mean=x=1\) and \(median=0\);

B. \(x\) --> if \(T=\{3\}\) then \(mean=x=3\) and \(median=x=3\);

C. \(-x\) --> if \(T=\{-1, -1, 5\}\) then \(mean=x=1\) and \(median=-x=-1\);

D. \(\frac{1}{3}y\) --> if \(T=\{1, 1, 1\}\) then \(mean=x=1\), \(# \ of \ elements=y=3\) and \(median=\frac{1}{3}y=1\);

E. \(\frac{2}{7}y\) --> now, as T is a set of integers then the median is either a middle term, so \(integer\) OR the average of two middle terms so \(\frac{integer}{2}\), but as \(y\) is an integer from 1 to 6 then \(\frac{2}{7}y\) is neither an \(integer\) nor \(\frac{integer}{2}\). So \(\frac{2}{7}y\) could not be the median.

Answer: E.

Hope it's clear.


Dear Bunuel,

Since Set T range from 1 to 6, why the sample of T from part C was T={-1, -1, 5}?


You are asking the same question: Phrase "T is a set of y integers, where 0 < y < 7" does NOT mean that T consist of elements from 1 to 6, it means that the number of elements (the number of terms) in T is from 1 to 6.
_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

Kudos [?]: 129173 [0], given: 12194

Manager
Manager
avatar
B
Joined: 04 Aug 2015
Posts: 86

Kudos [?]: 16 [0], given: 31

Location: India
Concentration: Leadership, Technology
GMAT 1: 620 Q50 V25
GPA: 3.39
Re: T is a set of y integers, where 0 < y < 7. If the average of [#permalink]

Show Tags

New post 24 Jan 2017, 09:05
T is a set of y integers, where 0 < y < 7. If the average of Set T is the positive integer x, which of the following could NOT be the median of Set T?

A. 0 {-1, 0, 4} mean(x)=1; median=0. Possible.
B. x {1, 1, 1} mean(x)=1; median=1. Possible.
C. –x {0, -1, 4} mean(x)=1; median=-1. Possible.
D. (1/3)y Let y be 3. Therefore, median=1 {1, 1, 1} mean(x)=1. Possible
E. (2/7)y The median can either be an integer or multiple of 1/2. Not possible.

Kudos [?]: 16 [0], given: 31

Re: T is a set of y integers, where 0 < y < 7. If the average of   [#permalink] 24 Jan 2017, 09:05

Go to page    1   2    Next  [ 21 posts ] 

Display posts from previous: Sort by

T is a set of y integers, where 0 < y < 7. If the average of

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.