Tanks A and B are each in the shape of a right circular cylinder. The

Question

Tanks A and B are each in the shape of a right circular cylinder. The interior of Tank A has a height of 10 meters and a circumference of 8 meters, and the interior of tank B has a height of 8 meters and a circumference of 10 meters. The capacity of tank A is what percent of the capacity of tank B?

(A) 75%
(B) 80%
(C) 100%
(D) 120%
(E) 125%

PS94530.02

(A) 75%
(B) 80%
(C) 100%
(D) 120%
(E) 125%

PS94530.02

KarishmaB · Accepted Answer

Heights of tank1 and tank2 are in the ratio 10:8 = 5 / 4
Circumference (which means radius too) is in the ratio 8 : 10 = 4 / 5

Volumes will be in the ratio r^2*h so ratio will be  \frac{5*4^2 }{ 4*5^2} = \frac{4}{5} 
So Capacity of tank A is 4/5*100 = 80% of capacity of tank B.

TestPrepUnlimited · Answer

For the question we are looking for a  ratio , is it possible to use ratios only to find ratios. The formula for the volume of a cylinder is  V = \pi * r^2 * h  . Focus on the variables in the formula, we only need to compare their radius squared and height. The ratio of radii is 8:10. The ratio of heights is 10:8. Then the ratio of the volumes is  (\frac{8}{10})^2 * \frac{10}{8} = 8/10 = 80%

Ans: B

GMATWhizTeam · Answer

Solution 
 • Let us assume that the radii of tank A and tank B are   r_1   and  r_2   respectively.
• Now,  2*π*r_1 = 8  and  2*π*r_2 = 10 
• Dividing circumference of tank, A by that of tank B we have:
 o  \frac{2*π*r_1}{2*π*r_2 }= \frac{8 }{ 10}  
  Or,  \frac{r_1}{r_2} = \frac{4}{5} …………Eq.(i)   
• Now, volume of tank A  = π*r_1^2*height= π*r_1*10  
• And volume of tank B  = π*r_2^2*height = π*r_2*8 
• Hence, Required percentage  = \frac{π*r_1^2*10}{ π*r_2^2*8} *100⟹(\frac{r_1}{r_2}) ^2 * \frac{5}{4}*100   
Substituting the value of  \frac{r_1}{r_2}  from Eq. (1) into the above equation, we get:
Required percentage  = \frac{16}{25}*\frac{5}{4}*100 = 80  %
Thus, the correct answer is   Option B .

SameerGupta2001 · Answer

for tank A,
h=10m
circumference=pi(2)r=8
 r=4/pi
volume of tank=pi(r^2)h
 =pi*16/pi^2*10=32/pi m^3

for tank B,
h=8m
circumference=pi(2)r=10
 r=5/pi
volume of tank=pi(r^2)h
 =pi*5/pi^2*8=40/pi m^3

The capacity of tank A is what percent of the capacity of tank B=(32/pi)/(40/pi)*100=80%
Answer is 80%

yashikaaggarwal · Answer

IOC is B 80%
Circumference of cylinder A = 2πr=8
R=4/π
Volume/capacity of tank A = πr^2h
π*4/π*4/π*10 = 160/π ------(1)

Circumference of cylinder B = 2πr=10
R=6/π
Volume/capacity of tank A = πr^2h
π*5/π*5/π*18 = 200/π ------(2)

Let Tank A capacity is X Percentage of tank B
200/π*X/100=160/π
16000/200=80
X=80%

IOC is 80% (B)

Posted from my mobile device

Archit3110 · Answer

for tank a ; 
h= 10 ; 
2 * pi *r = 8
pi * r= 4 & r = 4/pi
for tank b
h= 8
2*pi*r = 10
pi*r = 5 an r = 5/pi
area of tank a /area of tank b = 4*4/pi * 10 / 8 * 5/pi * 5
we get 80 %
OPTION B

Nipunh1991 · Answer

Capacity of Tank A as a percent of the capacity of tank B = Capacity (Volume) of Tank A / Capacity (Volume) of Tank B *100
 
Since both are right circular cylinder (Volume = pi . r^2. h)

We have the height for both tanks however we need to figure out the radius of each of these. In order to find out the radius we will need to use the information of circumference.

Length of Circumference for Tank A = 2 . Pi. R
8 = 2. Pi. R
R= 4/Pi

Similarly Length of Circumference for Tank B = 2 . Pi. R
10 = 2 Pi R
R = 5 / Pi

Now Volume of Tank A / Vol of Tank B =  (Pi (4/pi)^2. 10 )/ (Pi (5/pi)^2 .8)

After Cancelling out it comes out to

4/5 = 80%

ScottTargetTestPrep · Answer

Recall that the circumference of a circle with radius r is C = 2πr. The volume of a cylinder with height h and radius r is V = πr^2*h. Since the height of tank A is 10 and the radius is 8/(2π) = 4/π, the volume of tank A is π(4/π)^2*10 = π(16/π^2)*10 = 160/π. Likewise, since the height of tank B is 8 and the radius is 10/(2π) = 5/π, the volume of tank B is π(5/π)^2*8 = π(25/π^2)*8 = 200/π.

Therefore, the volume of tank A is (160/π) / (200/π) x 100 = 160/200 x 100 = 80 percent of that of tank B.

Answer: B

unraveled · Answer

Let's just deal in ratios.
Ratio of radius of Tank A to that of Tank B,  \frac{r_A}{r_B}  = Ratio of circumference of Tank A to that of Tank B =  \frac{8}{10} = \frac{4}{5}  
Ratio of height of Tank A to that of Tank B,  \frac{h_A}{h_B}  =  \frac{10}{8} = \frac{5}{4}

Ratio of capacity of Tank A to that of Tank B =  \frac{π*r_A^2*h_A}{π*r_B^2*h_B} = (\frac{r_A}{r_B})^2*\frac{h_A}{h_B} = \frac{4}{5}*\frac{4}{5}*\frac{5}{4} = \frac{4}{5}

Answer B.

Gmat20201 · Answer

Soln:

Tank A - H=10 and C= 8
Tank B- h=8 and c = 10

Vol of cylinder =Pi * r^2 h

We need to know Capacity of Tank A=x % of Capacity of Tank B

So x/100 =Capacity of Tank A/Capacity of Tank B
= Pi* R^2*H/ Pi * r^2* h
= R^2*H/ r^2 *h

Basically to find x we need ratio of radius and ht of Tank A and Tank B

C/c=2Pi* R/ 2Pi*r=8/10

R/r=8/10

H/h=10/8

Putting ratio of radius and ht in ratio of capacity formula derived above

x/100=R^2*H/ r^2 *h
=8*8*10/ 10*10*8

x/100 = 80/100

Therefore x =80%

And Choice B

Hope it helps

CrackverbalGMAT · Answer

] SOLUTION: A NEW OG 2021 QUESTION Volume of Tank A (VA) = pi * (R1)^2 * H1 Volume of Tank B (VB) = pi * (R2)^2 * H2 Circumference (A)=8 => 2*pi* R1 =8=> R1 = 8/2*pi and similarly R2 = 10/2*pi Substitute these values in VA/VB to have VA/VB = (R1)^2 * H1/ (R2^2 * H2) = 8^2 * 10 / (10)^ 2 * 8 = 8/10 => VA/VB =8/10 = >VA is 80% of VB (OPTION B) Hope this helps

Devmitra Sen (Math)

MHIKER · Answer

Is the formula of circumference of a cylinder 2πr, probably not. then how can we say 2πr=8?

DeeBee54 · Answer

Isn't curved / lateral surface area of a cylinder 2(pie)(r)(h)?

GMATinsight · Answer

Answer: Option B

Video solution by  GMATinsight

https://www.youtube.com/watch?v=in_yuGK0xfE

Surya0369 · Answer

i also did the same mistake 
i took circumference as 2(pi)rh

760Abhi · Answer

Hi Experts,  Bunuel   chetan2u

Although my answer was correct for this question but I want to understand one thing, which probably everybody in this question thread has written wrong.

Don't you guys think that Circumference of cylinder is == 2 * 2*pi*r

I understand there will be no impact in the answer but I just want to know whether my thought process is correct or not.

Thanks for your time and reply.

chetan2u · Answer

Circumference of any tank etc of negligible thickness will be  2*\pi r

But if you have a thick material, then you will have inner and outer circumference. Both will be different but not 2*  2*\pi r

760Abhi · Answer

Hi  chetan2u

Thanks for your reply.

If it's a tank then I am assuming it to be in a cylindrical shape (Let's suppose negligible thickness) and then we have two circles i.e. (at the bottom & at the top) Hence Total circumference will be == circumference of top + circumference of bottom == 2* 2*pi*r

I am not able to find a logic gap in my reasoning, please help.

bumpbot · Answer

Automated notice from GMAT Club BumpBot: 

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

 This post was generated automatically.

Tanks A and B are each in the shape of a right circular cylinder. The

Prep Toolkit

Top 5 GMAT Debrief Videos

615 to 715 in 15 Days (Ria's Strategies)

More than Quant/Verbal Abilities: Speed vs. Accuracy

745 with Only Self-Prep and GMAT Club

From 555 to 765: 210-point Improvement

Perfect 805 Score Debrief by Julia

My Rewards

GMAT Problem Solving (PS) Questions

Tanks A and B are each in the shape of a right circular cylinder. The

Prep Toolkit

615 to 715 in 15 Days (Ria's Strategies)

More than Quant/Verbal Abilities: Speed vs. Accuracy

745 with Only Self-Prep and GMAT Club

From 555 to 765: 210-point Improvement

Perfect 805 Score Debrief by Julia

My Rewards