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balamoon
The difference between simple interest and compound interest of a certain sum of money at 20% per annum for 2 years is $48. Then the sum is

(A) $600
(B) $1000
(C) $1200
(D) $1500
(E) $2000

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balamoon
The difference between simple interest and compound interest of a certain sum of money at 20% per annum for 2 years is $48. Then the sum is

(A) $600
(B) $1000
(C) $1200
(D) $1500
(E) $2000

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Be lazy and plug in. Start in the middle with AC C:

Compound Interest (Simple Interest)
Year 1 = 1440 (1440)
Year 2 = 1728 (1680)

Whoops, that's already the answer since 1728 - 1680 = 48
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balamoon
The difference between simple interest and compound interest of a certain sum of money at 20% per annum for 2 years is $48. Then the sum is

(A) $600
(B) $1000
(C) $1200
(D) $1500
(E) $2000

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Please note that CI is greater than SI (if counted for >1 year) & equal for same year
So the difference given in stem must be CI-SI=48.
Let x be amount invested then
SI=2x/5
CI =x(1+20/100)^(2)-x------->(36x/25)-x------->11x/25
Difference=11x/25-2x/5-------->x/25
As given x/25=48
x=25*48
x=1200
Ans c
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balamoon
The difference between simple interest and compound interest of a certain sum of money at 20% per annum for 2 years is $48. Then the sum is

(A) $600
(B) $1000
(C) $1200
(D) $1500
(E) $2000

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Although there are various nice solutions already posted, I would like solve this issue as :

Lets assume the sum is 100.
SI at 20% per annum for 2 years = 100 * .2 *2= 40

CI Then SI at 20% per annum for 2 years = \(100( 1+.2)^2 - 100\) = \(100 (1.2)^2 -100\) = \(100*1.44-100\) = \(144-100\) = 44

4 is the difference when amt is 100
or 1 is the difference when amt is \frac{100}{4}
Hence, 48 is the difference when amount is = \(\frac{100}{4} *48\)=\(100*12\)= 1200 Hence C
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Simple is 20%+20%=40% and compound is 1.2^2 = 1.44 so the difference is 4%. Thus 4%x=48 --> x=1200
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If you are familiar with the concept of SI and CI, we know that since the Principal amount for both cases is the same with same rate of interest, the interest earned after Year 1 for both cases i.e. Simple interest and Compound Interest will be the same. (Incase you are unfamiliar with the concept, you must read the theory shared by Bunuel.)
I calculated backwards,
Year 1 interest*20/100=48 =>Year 1 interest = 240
Since we know the interest earned after year 1 => Principal*20/100=240 => Principal=1200
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Bunuel
balamoon
The difference between simple interest and compound interest of a certain sum of money at 20% per annum for 2 years is $48. Then the sum is

(A) $600
(B) $1000
(C) $1200
(D) $1500
(E) $2000

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can anyone please tell complete formulas of SI and CI with explanation of concepts. I am facing trouble in these questions, thanks in advance.

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Bunuel
balamoon
The difference between simple interest and compound interest of a certain sum of money at 20% per annum for 2 years is $48. Then the sum is

(A) $600
(B) $1000
(C) $1200
(D) $1500
(E) $2000

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can anyone please tell complete formulas of SI and CI with explanation of concepts. I am facing trouble in these questions, thanks in advance.

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4. Percents and Iterest



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the question is not clear - is it asking for sum of money or sum of CI and SI?
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balamoon
The difference between simple interest and compound interest of a certain sum of money at 20% per annum for 2 years is $48. Then the sum is

(A) $600
(B) $1000
(C) $1200
(D) $1500
(E) $2000
CI for 2 years is 20 + (20% of 20 + 20) = 44
SI for 2 years is 40

Diff is 4

Now, Principal will be 48/4*100 = 1200, Answer will be (C)
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Despite other good answers, this also is direct;

Simple Interest:
SI = p * R * T

which translates to SI = P * 0.2 * 2
= 0.4P ...................(1)

Compound Interest:
CI = [P(1 + R)**T] - P
translates to :- CI = P[1+0.2]**2 - P
= 1.44P - P
= O.44P .......................(2)

Difference between CI - SI = $48
** knowing that compound interest is greater than simple interest.
therefore:
0.44p - 0.4p = $48
0.04p = $48

p = $48/0.04
p = $4800/4

p = $1200

Hence Ans C
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