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The figure above represents a square plot measuring x feet o

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New post Updated on: 26 Sep 2013, 03:55
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The figure above represents a square plot measuring x feet on a side. The plot consists of a rectangular garden, 48 square feet in area, surrounded by a walkway that is 3 feet wide on two opposite sides and 2 feet wide on the other two sides. What is the value of X?

a) 8
b) 10
C) 12
d) 16
e) 18

Originally posted by fozzzy on 26 Sep 2013, 03:52.
Last edited by Bunuel on 26 Sep 2013, 03:55, edited 1 time in total.
Edited the question.
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Re: The figure above represents a square plot measuring x feet o  [#permalink]

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New post 26 Sep 2013, 03:56
3
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fozzzy wrote:
Image
The figure above represents a square plot measuring x feet on a side. The plot consists of a rectangular garden, 48 square feet in area, surrounded by a walkway that is 3 feet wide on two opposite sides and 2 feet wide on the other two sides. What is the value of X?

a) 8
b) 10
C) 12
d) 16
e) 18


The length of the rectangular garden would be \(x-2*2\) and the width would be \(x-2*3\) --> \(area=(x-4)(x-6)=48\) --> \(x^2-10x-24=0\) --> \(x=12\) or \(x=-2\) (not a valid solution).

Answer: C.
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Re: The figure above represents a square plot measuring x feet o  [#permalink]

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New post 16 Apr 2014, 00:13
HI Bunnel,

If I will resolve the equation

x^2-10x-24=0 as x^2-4x-6x-24 = 0

then I will get x as 6,4

so value of x can be 6+3+3 or 6+2+2

12 or 10. both are present in the answer.
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Re: The figure above represents a square plot measuring x feet o  [#permalink]

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New post 16 Apr 2014, 01:07
1
PathFinder007 wrote:
HI Bunnel,

If I will resolve the equation

x^2-10x-24=0 as x^2-4x-6x-24 = 0

then I will get x as 6,4

so value of x can be 6+3+3 or 6+2+2

12 or 10. both are present in the answer.



Hi,

x^2-10x-24=0 can not be resolved as x^2-4x-6x-24 = 0 because multilpying your roots -4 and -6 will give 24, whereas the actual product in the equation is -24.

Hence the correct way to resolve this equation is this : x^2 -12x + 2x - 24 = 0
=> x(x-12) + 2 (x-12)=0 => (x + 2) (x - 12) = 0.

This gives 12 and -2 as the roots of the equation. Since the length can not be negative, the correct answer is 12.

Hope this helps.
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Re: The figure above represents a square plot measuring x feet o  [#permalink]

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New post 31 Jul 2015, 08:10
1
fozzzy wrote:
Attachment:
image.jpg
The figure above represents a square plot measuring x feet on a side. The plot consists of a rectangular garden, 48 square feet in area, surrounded by a walkway that is 3 feet wide on two opposite sides and 2 feet wide on the other two sides. What is the value of X?

a) 8
b) 10
C) 12
d) 16
e) 18


the area of rectangular is 48 sqft, so the length and width could be 8 and 6
6 ft + 2*3 ft = 8 ft + 2*2 ft = 12 ft
ans c) 12 feet
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Re: The figure above represents a square plot measuring x feet o  [#permalink]

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New post 16 Apr 2016, 07:27
Bunuel wrote:
fozzzy wrote:
Image
The figure above represents a square plot measuring x feet on a side. The plot consists of a rectangular garden, 48 square feet in area, surrounded by a walkway that is 3 feet wide on two opposite sides and 2 feet wide on the other two sides. What is the value of X?

a) 8
b) 10
C) 12
d) 16
e) 18


The length of the rectangular garden would be \(x-2*2\) and the width would be \(x-2*3\) --> \(area=(x-4)(x-6)=48\) --> \(x^2-10x-24=0\) --> \(x=12\) or \(x=-2\) (not a valid solution).

Answer: C.














Hi Bunuel, how did you take the length as x-2*2 and breadth as x-2*3 ? I'm not able to figure out the reasoning behind this logic.
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Re: The figure above represents a square plot measuring x feet o  [#permalink]

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New post 16 Apr 2016, 10:19
RaghavSingla wrote:
Bunuel wrote:
fozzzy wrote:
Image
The figure above represents a square plot measuring x feet on a side. The plot consists of a rectangular garden, 48 square feet in area, surrounded by a walkway that is 3 feet wide on two opposite sides and 2 feet wide on the other two sides. What is the value of X?

a) 8
b) 10
C) 12
d) 16
e) 18


The length of the rectangular garden would be \(x-2*2\) and the width would be \(x-2*3\) --> \(area=(x-4)(x-6)=48\) --> \(x^2-10x-24=0\) --> \(x=12\) or \(x=-2\) (not a valid solution).

Answer: C.














Hi Bunuel, how did you take the length as x-2*2 and breadth as x-2*3 ? I'm not able to figure out the reasoning behind this logic.


Check below:

Image

The length= x - 2 -2 = x - 2*2
The width = x - 3 - 3 = x - 2*3

Attachment:
Untitled.png
Untitled.png [ 11.16 KiB | Viewed 2468 times ]

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Re: The figure above represents a square plot measuring x feet o  [#permalink]

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New post 17 Apr 2016, 04:42
square root of 48 is approx. 6.9. Add 6 to that (2*3feet) and you get approximately 12.9... ?
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The figure above represents a square plot measuring x feet o  [#permalink]

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New post 12 Jul 2017, 19:18
fozzzy wrote:
Attachment:
image.jpg
The figure above represents a square plot measuring x feet on a side. The plot consists of a rectangular garden, 48 square feet in area, surrounded by a walkway that is 3 feet wide on two opposite sides and 2 feet wide on the other two sides. What is the value of X?

a) 8
b) 10
C) 12
d) 16
e) 18

Work from the answer choices. I'll pretend I started with E.

If x = 18, the length of the rectangle must be 18 - 2 - 2 (for each part of the walkway) = 14

OR 18 - 3 - 3 = 12 is the length of the rectangle.

Work with 12; it's a factor of 48, the area of the rectangle.

If rectangle length = 12, width is 48/12 = 4.

But that's the side that has 2-foot wide walkways.

Adding both 2-foot walkway parts to the width of the rectangle should yield 18.

4 + 2 + 2 = 8. Not possible. The outside shape is a square. Sides must be equal. 18 and 8 aren't equal.

No need to test rectangle length or width of 14. If 18 were the answer, because the outside is a square, it would yield 18 after taking walkway into account no matter which measure of rectangle side were used.

Try C, x = 12. If so, length of rectangle is 12 - 2 - 2 = 8. (Or 12 - 3 - 3 = 6.)

Work with L=8. If so, rectangle width must be 48/8 = 6.

When calculating rectangle length = 8, we accounted for the two 2-foot wide walkway parts.

So to rectangle width of 6, add the two 3-foot parts of the walkway: 3 + 3 = 6.

6 + 6 = 12, which is the number we need to make the sides be equal.

Answer C (which I chose to test first - got lucky)
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New post 25 Feb 2019, 09:34
Algebra:
Area small rectangle: l*w = 48
Area big square: x² = (l+6)(w+4), since it's a square, l+6 = w+4 --> l+2 = w
Now we can solve the first equation:
l*(l+2) = 48
l²+2l-48 = 0
(l+8)(l-6) = 0
l = 6, -8
Thus, w = 8
Area is l+6 or w+4, so 6+6 or 8+4 = 12

Testing answers:
Choose middle answer C), if x = 12 then 2 sides of rectangle are 12-6=6 & 12-4=8
Area is l*w = 48, testing 8*6 = 48, so this is our answer.
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Re: The figure above represents a square plot measuring x feet o  [#permalink]

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New post 02 Mar 2019, 09:14
fozzzy wrote:
Attachment:
image.jpg
The figure above represents a square plot measuring x feet on a side. The plot consists of a rectangular garden, 48 square feet in area, surrounded by a walkway that is 3 feet wide on two opposite sides and 2 feet wide on the other two sides. What is the value of X?

a) 8
b) 10
C) 12
d) 16
e) 18


One side of the garden is x - 3 - 3 = x - 6, and the other side is x - 2 - 2 = x - 4. Therefore, we have:

(x - 6)(x - 4) = 48

x^2 - 10x + 24 = 48

x^2 - 10x - 24 = 0

(x - 12)(x + 2) = 0

x = 12 or x = -2

Since x can’t be negative, x = 12.

Answer: C
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Re: The figure above represents a square plot measuring x feet o   [#permalink] 02 Mar 2019, 09:14
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