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The figure above shows four pieces of tile that have been glued togeth

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The figure above shows four pieces of tile that have been glued togeth  [#permalink]

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New post 11 Dec 2014, 07:21
00:00
A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

78% (01:06) correct 22% (01:03) wrong based on 97 sessions

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Tough and Tricky questions: Geometry.



Image
The figure above shows four pieces of tile that have been glued together to form a square tile ABCD. Is PR=QS?

(1) BQ = CR = DS = AP
(2) The perimeter of ABCD is 16.


Kudos for a correct solution.

Attachment:
2014-12-11_1820.png
2014-12-11_1820.png [ 4.3 KiB | Viewed 2217 times ]

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Re: The figure above shows four pieces of tile that have been glued togeth  [#permalink]

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New post 11 Dec 2014, 09:40
1
In the Figure, From option A if we consider BQ=CR=DS=AP and project their mirror images on the opposite sides, then we would obtain four isosclese Right angled triangles at the four vertices. Now, further, for PR and QS , their perpendicular lengths are equal , and since we have projected the given four lengths on their opposite sides, therefore the BASES of the two triangles are also equal (the triangles which are formed by taking PR and OS as their hypotenuse and whose base is obtained by drawing a perpendicular side from the top vertex on the opposite side) .

Hence , since base and perpendicular lengths of the two triangles are equal, so that the sides PR and QS are equal in length taking Statement A as true.

And Statement B is clearly insufficient. :) option A is the appropriate choice.
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Re: The figure above shows four pieces of tile that have been glued togeth  [#permalink]

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New post 12 Dec 2014, 01:03
statement 1 : BQ = CR = DS = AP

since ABCD is square, and BD=CR=DS=AP, then CQ=DR=AS=PB.
Not sufficient to answer whether PR=QS

statement 2 : The perimeter of ABCD is 16.

Doesn't help to answer whether PR=QS

1+2 combined, still not sufficient.

Ans = E
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Re: The figure above shows four pieces of tile that have been glued togeth  [#permalink]

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New post 26 Dec 2014, 09:39
Bunuel wrote:

Tough and Tricky questions: Geometry.



Image
The figure above shows four pieces of tile that have been glued together to form a square tile ABCD. Is PR=QS?

(1) BQ = CR = DS = AP
(2) The perimeter of ABCD is 16.


Kudos for a correct solution.

Attachment:
2014-12-11_1820.png


The correct answer is A.
_________________

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Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


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Re: The figure above shows four pieces of tile that have been glued togeth  [#permalink]

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New post 27 Dec 2014, 01:42
Bunuel wrote:
Bunuel wrote:

Tough and Tricky questions: Geometry.



Image
The figure above shows four pieces of tile that have been glued together to form a square tile ABCD. Is PR=QS?

(1) BQ = CR = DS = AP
(2) The perimeter of ABCD is 16.


Kudos for a correct solution.

Attachment:
2014-12-11_1820.png


The correct answer is A.



Bunuel Can you please give OE for this question?


Thanks
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The figure above shows four pieces of tile that have been glued togeth  [#permalink]

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New post 01 Aug 2017, 04:16
Really tricky question,

Initially marked answer E, as got all sides of quadrilateral formed inside equal but have no detail about diagonals.

But after read that correct option is A, came up with below solution. Seems it was an easy one.

Easy and simple steps, but to explain, i have written everything in detail.

Attached the hand drawn image.

Solution:
Given Final image is a square. SO all sides are equal

Taking point 1:
BQ=CR=DS=AP = a (suppose)
let remaining portion of side = b
So total square side =a+b

Draw perpendicular from Q on AD => QE . So QE = side of square= a+b

same way Draw perpendicular from P on CD => PF . So PF = side of square= a+b

Now, as its square, all vertices are 90 degree. As BE perpendicular on AD => BQ=AE =a and BA=QE= a+b
As AD= a+b and now AE=a and given SD=a there fore ES = a+b -a -a = b-a

So right triangle triangle QES has 1 side QE=a+b and 2nd side ES=b-a. So we can find hypotenuse QS .................(1)

Same way PFR makes a right triangle with 1 side PF= a+b and 2nd side RF= b-a. So we can find hypotenuse PR ...................(2)

By above 2 equations (1) and (2),

both triangles have same sides so hypotenuse length will be same

There for PR = QS

So option 1 is sufficient.


Taking point 2:

Given side of square =16. Doesn't give us any information

So option 2 not sufficient


Answer = A


Hope above explanation makes sense.
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The figure above shows four pieces of tile that have been glued togeth &nbs [#permalink] 01 Aug 2017, 04:16
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