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# The finesse of a gold bar is the weight of the gold present in the bar

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Re: The finesse of a gold bar is the weight of the gold present in the bar [#permalink]
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Weight of gold in 1st and 2nd = x
Since finesse is equal for both
Weight of gold in 3rd bar = y

Total weight of each is =w

Now if they are melted and turned into one bar, resulting finesse is

2x+y/3w = 0.96
2x/w + y/w = 0.96*3
2x/w + y/w = 2.88

Now putting the above options in the equation,so

2*.98+0.92=2.88
So finesse of first and second is 0.98

Finesse of third is 0.92

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Re: The finesse of a gold bar is the weight of the gold present in the bar [#permalink]
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Total 0.96*3 = 2.88 (total finness)
2X+Y = 2.88

Prethinking:
Option1: 2 numbers closure above 0.96 and 3rd one far below 0.96 OR
option2: 2 numbers very near below 0.96 and 3rd one should be much higher than 0.96)

As per all options given higher than 0.96 is very close so it maybe possible than 2 numbers are higher than 0.96 so i chose first nearby option value above 0.96 for X i.e. 0.98 for X

Try Y= 0.98 then Y comes out to be 0.92

A quick check on our answer:
Try X = 0.99 then Y should be 0.90 - not available( Prethinking: option1)
Try Y = 0.98 then X should be 0.95*2 - not available( Prethinking: option2)
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Re: The finesse of a gold bar is the weight of the gold present in the bar [#permalink]
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This one can be solved pretty quickly using the alligation method. Here is how it can be done:

The average finesse is 0.96. So the value of individual finesse of the two blocks has to be either higher than the average or lower than the average.

The same can be said about the value of finesse of the 3rd bar as well.

Now as there are two gold bars with equal finesse, we can deduce that their impact on the average shall be twice the impact of the 3rd bar. So, the 3rd bar shall be twice as far from the average finesse value as the finesse value of the two bars.

Thus, we are left with only two choices:

Either the finesse of two bars is 0.98 or 0.94 and that of 3rd bar is then 0.92 or 1.00 respectively.

The answer choices are pretty clear:

We have no 1.00. Thus, 0.94 for two bars and 1.00 for 3rd bar is out.

We are left with only one situation:

The finesse value for two bars is 0.98 and that of third bar is 0.92.

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The finesse of a gold bar is the weight of the gold present in the bar [#permalink]
KarishmaB chetan2u GMATinsight , Would you like to discuss this question ?­ I derived the equation but could not figure out the value.
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The finesse of a gold bar is the weight of the gold present in the bar [#permalink]
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­Third bar                           First two bars
1                                      2
[y]------------------96---------[x]
2a                  a

x > 96
From the answer choices, x is either 98 or 99

If x = 99 => a = 3 => y = 96 - 2a = 90 => not an answer choice
If x = 98 => a = 2 => y = 96 - 2a = 92 => Ok

First two bars: x = 0.98
Third bar: y = 0.92­
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Re: The finesse of a gold bar is the weight of the gold present in the bar [#permalink]
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parkhydel wrote:
The finesse of a gold bar is the weight of the gold present in the bar divided by the total weight of the bar. A jeweler has three gold bars. The three bars have identical weights, and the first two bars have identical finesse. If all three bars were melted and combined into one bar, the finesse of the resulting bar would be 0.96.

Select a finesse of the First two bars and a finesse of the Third bar that are jointly consistent with the given information. Make only two selections, one in each column.­

ID: 100426

Simply imagine the scale of weighted averages.

­All 3 bars have equal weight. First two bars have same finesse. It simply means that the weight given to the finesse of the first 2 bars is twice the weight given to the finesse of the third bar. So the average finesse of .96 will be at a distance of 1:2 from the finesse of first two bars to the finesse of the third bar.

Hence 0.98 could be the finesse of first two bars and .92 the finesses of the third bar.
0.98 - - 0.96 - - - - 0.92
Their distance from the average will be in the ratio 1:2.