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The leftmost tick mark is 1, and successive tick marks shown on the

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The leftmost tick mark is 1, and successive tick marks shown on the  [#permalink]

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New post 09 Oct 2017, 23:47
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A
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Difficulty:

  75% (hard)

Question Stats:

40% (01:02) correct 60% (01:14) wrong based on 52 sessions

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The leftmost tick mark is 1, and successive tick marks shown on the number line above are equally spaced. If x and y are the numbers designating the end points of intervals as shown, what is the value of x?

(1) x + y = 5
(2) x = y/5


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image005.gif
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Re: The leftmost tick mark is 1, and successive tick marks shown on the  [#permalink]

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New post 10 Oct 2017, 03:38
Bunuel wrote:
Image
The leftmost tick mark is 1, and successive tick marks shown on the number line above are equally spaced. If x and y are the numbers designating the end points of intervals as shown, what is the value of x?

(1) x + y = 5
(2) x = y/5


Attachment:
image005.gif


Question: What is the value of x = ?

Statement 1: x + y = 5

As we can see that ever gap has the value = x-1

value of y = 1+ 5 gaps = 1 + 5*(x-1)

so x+y = x+1 + 5*(x-1) = 5

SUFFICIENT


Statement 2: x = y/5

value of y = 1+ 5 gaps = 1 + 5*(x-1) = 5x


SUFFICIENT


Answer: Option D
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Re: The leftmost tick mark is 1, and successive tick marks shown on the  [#permalink]

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New post 13 Oct 2017, 21:38
1
X=1gap and y=5gaps

St1: x+y=5
So, 6 gaps=5
Hence, each gap=x=5/6
Sufficient.

St2:x=y/5
No real numbers given.
Just the ratio of x/y=1/5
Insufficient.

Hence, Ans A

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Re: The leftmost tick mark is 1, and successive tick marks shown on the  [#permalink]

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New post 28 Oct 2017, 09:45
Statement 1: x+y=5
From question stem, we know that the leftmost tick is 1 and intervals are equal in size. There are 5 equal intervals from 1 to y, so:

(y-1) / 5 = x-1

Simplifying the above equation gives 5x-y=4 so we have two simultaneous equations: x+y=5 and 5x-y=4 that can be solved to find x. Sufficient

Statement 2: x = y/5 can be simplified to 5x-y=0. Again, we know that the leftmost tick is 1 and intervals are equal in size. There are 5 equal intervals from 1 to y, so:

(y-1) / 5 = x-1

Simplifying the above equation gives 5x-y=4. Now we have two equations 5x-y=0 and 5x-y=4 that can't be solved for x. Insufficient

Answer: A
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The leftmost tick mark is 1, and successive tick marks shown on the  [#permalink]

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New post 21 Dec 2017, 11:36
Hi Bunuel

I have question.
Let d - equal space, then \(x = 1 + d\), \(y = 1 + 5d\) , to find x, we need to find the value of d

Statement 1 : \(x + y = 5\)
=> \(1 + d + 1 + 5d = 5\)
=> \(d = 0.5\) => sufficient to find x

Statement 2: \(x = y/5\) => not sure about the validity of this statement
=> \(1 + d = (1 + 5d)/5\) => 5 + 5d = 1 + 5d => is not valid
=> had the left most tickmark been 0, then x = y/5 is valid

am i missing something?

Thanks

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The leftmost tick mark is 1, and successive tick marks shown on the &nbs [#permalink] 21 Dec 2017, 11:36
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