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# The leftmost tick mark is 1, and successive tick marks shown on the

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Math Expert
Joined: 02 Sep 2009
Posts: 43891
The leftmost tick mark is 1, and successive tick marks shown on the [#permalink]

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09 Oct 2017, 23:47
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Difficulty:

75% (hard)

Question Stats:

41% (01:02) correct 59% (01:13) wrong based on 51 sessions

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The leftmost tick mark is 1, and successive tick marks shown on the number line above are equally spaced. If x and y are the numbers designating the end points of intervals as shown, what is the value of x?

(1) x + y = 5
(2) x = y/5

[Reveal] Spoiler:
Attachment:

image005.gif [ 949 Bytes | Viewed 609 times ]
[Reveal] Spoiler: OA

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Joined: 08 Jul 2010
Posts: 1955
Location: India
GMAT: INSIGHT
WE: Education (Education)
Re: The leftmost tick mark is 1, and successive tick marks shown on the [#permalink]

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10 Oct 2017, 03:38
Bunuel wrote:

The leftmost tick mark is 1, and successive tick marks shown on the number line above are equally spaced. If x and y are the numbers designating the end points of intervals as shown, what is the value of x?

(1) x + y = 5
(2) x = y/5

[Reveal] Spoiler:
Attachment:
image005.gif

Question: What is the value of x = ?

Statement 1: x + y = 5

As we can see that ever gap has the value = x-1

value of y = 1+ 5 gaps = 1 + 5*(x-1)

so x+y = x+1 + 5*(x-1) = 5

SUFFICIENT

Statement 2: x = y/5

value of y = 1+ 5 gaps = 1 + 5*(x-1) = 5x

SUFFICIENT

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Manager
Joined: 01 Feb 2017
Posts: 79
Re: The leftmost tick mark is 1, and successive tick marks shown on the [#permalink]

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13 Oct 2017, 21:38
1
KUDOS
X=1gap and y=5gaps

St1: x+y=5
So, 6 gaps=5
Hence, each gap=x=5/6
Sufficient.

St2:x=y/5
No real numbers given.
Just the ratio of x/y=1/5
Insufficient.

Hence, Ans A

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Intern
Joined: 24 Oct 2016
Posts: 25
Re: The leftmost tick mark is 1, and successive tick marks shown on the [#permalink]

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28 Oct 2017, 09:45
Statement 1: x+y=5
From question stem, we know that the leftmost tick is 1 and intervals are equal in size. There are 5 equal intervals from 1 to y, so:

(y-1) / 5 = x-1

Simplifying the above equation gives 5x-y=4 so we have two simultaneous equations: x+y=5 and 5x-y=4 that can be solved to find x. Sufficient

Statement 2: x = y/5 can be simplified to 5x-y=0. Again, we know that the leftmost tick is 1 and intervals are equal in size. There are 5 equal intervals from 1 to y, so:

(y-1) / 5 = x-1

Simplifying the above equation gives 5x-y=4. Now we have two equations 5x-y=0 and 5x-y=4 that can't be solved for x. Insufficient

Senior Manager
Joined: 02 Apr 2014
Posts: 411
The leftmost tick mark is 1, and successive tick marks shown on the [#permalink]

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21 Dec 2017, 11:36
Hi Bunuel

I have question.
Let d - equal space, then $$x = 1 + d$$, $$y = 1 + 5d$$ , to find x, we need to find the value of d

Statement 1 : $$x + y = 5$$
=> $$1 + d + 1 + 5d = 5$$
=> $$d = 0.5$$ => sufficient to find x

Statement 2: $$x = y/5$$ => not sure about the validity of this statement
=> $$1 + d = (1 + 5d)/5$$ => 5 + 5d = 1 + 5d => is not valid
=> had the left most tickmark been 0, then x = y/5 is valid

am i missing something?

Thanks
The leftmost tick mark is 1, and successive tick marks shown on the   [#permalink] 21 Dec 2017, 11:36
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# The leftmost tick mark is 1, and successive tick marks shown on the

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