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Bunuel
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Statement 1: x+y=5
From question stem, we know that the leftmost tick is 1 and intervals are equal in size. There are 5 equal intervals from 1 to y, so:

(y-1) / 5 = x-1

Simplifying the above equation gives 5x-y=4 so we have two simultaneous equations: x+y=5 and 5x-y=4 that can be solved to find x. Sufficient

Statement 2: x = y/5 can be simplified to 5x-y=0. Again, we know that the leftmost tick is 1 and intervals are equal in size. There are 5 equal intervals from 1 to y, so:

(y-1) / 5 = x-1

Simplifying the above equation gives 5x-y=4. Now we have two equations 5x-y=0 and 5x-y=4 that can't be solved for x. Insufficient

Answer: A
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Hi Bunuel

I have question.
Let d - equal space, then \(x = 1 + d\), \(y = 1 + 5d\) , to find x, we need to find the value of d

Statement 1 : \(x + y = 5\)
=> \(1 + d + 1 + 5d = 5\)
=> \(d = 0.5\) => sufficient to find x

Statement 2: \(x = y/5\) => not sure about the validity of this statement
=> \(1 + d = (1 + 5d)/5\) => 5 + 5d = 1 + 5d => is not valid
=> had the left most tickmark been 0, then x = y/5 is valid

am i missing something?

Thanks



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