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Total numbers from 1 to 100, inclusive = 100
Divisible by 2 = (100-2/2)+1 = 50
Divisible by 3 (but excluding multiples of 6 being the LCM of 2,3) = (99-3/6)+1 = 17
Divisible by 5 (but not divisible by either 2 or 3) = 25, 35, 55, 65, 85,95 = 7

Total divisible by either 2 or 3 or 5 = 74
Total not divisible = 100-74 = 26

Answer - A
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Bunuel
The number of positive integers not greater than 100, which are not divisible by 2, 3 or 5 is

(A) 26
(B) 27
(C) 31
(D) 32
(E) 33



Solution:

The integers satisfy the condition are 1, primes excluding 2, 3 and 5, and all the composite numbers whose smallest prime factor is at least 7.

The number of primes less than 100 is 25; so, excluding 2, 3, and 5, there are 22 primes satisfying the condition.

The composite numbers less than 100 with the smallest prime factor at least 7 are 7^2 = 49, 7 x 11 = 77 and 7 x 13 = 91.

Therefore, including the number 1, there are 1 + 22 + 3 = 26 such numbers.

Answer: A
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Total number of positive integers not greater than 100= 100

Not divisible by 2, 3, or 5 = Total - Divisible by 2,3, or 5


Total number of positive integers not greater than 100 divisible by 2: 50
Total number of positive integers not greater than 100 divisible by 3: 33
Total number of positive integers not greater than 100 divisible by 5: 20

Total number of positive integers not greater than 100 divisible by 2 and 3 both: 16 [LCM of 2 and 3 is 6]
Total number of positive integers not greater than 100 divisible by 2 and 5 both: 10 [LCM of 2 and 5 is 10]
Total number of positive integers not greater than 100 divisible by 3 and 5 both: 6 [LCM of 3 and 5 is 15]

Total number of positive integers not greater than 100 divisible by 2, 3, and 5: 3 [LCM of 2,3, and 5 is 30]

Total number divisible by 2, 3, or 5 = 50 + 33 + 20 - 16 - 10 - 6 + 3 = 74

Therefore, not divisible by 2, 3, or 5 = 100 - 74 = 26

Answer A
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interesting approach, but how do we know that we are not missing any number that is no a prime number.
flash007
There are a total of 25 prime numbers between 1 to 100.
Out of these primes, we remove 2,3 & 5 so we are left with 22 numbers.

There are 3 multiples (7*7,7*11,7*13) of 7 which are less than 100 and not divisible by 2,3 or 5.
also, 1 is not divisible by 2,3, or 5 and is less than 100.

Therefore answer=22+3+1=26
IMO A
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