Jizzy
chetan2u
MBADream786
The number of positive integral solutions of the equation a+b+c+d+e = 30 is?
A.25173
B.23517
C.25731
D.23751
E.23518
So 30 has to be distributed amongst 5 sets a,b,c,d and e. As we are looking at positive integral solution, let us give 1 each to all 5.
Remaining now =30-5=25
So let us now add 4 partItions so that we can distribute these in 5 sets and then choose these 4 partitions
=> (25+4)C4=29*28*27*26/4!=29*7*9*13=23751
D
chetan2u is there any way by which we could bypass the tedious calculation and choose an answer choice thereby saving time?
I did the unit digit calculation and got stuck between Option C and D
Curious to know how you would approach it
You are correct with units digit.
The other could have been to check the divisors.
Here 9 is a divisor, so the sum of digits should be divisible by 9. However, as luck would have it, the digits are exactly the same in C and D. The remaining factors 7, 13, 29 etc do not have a trick attached to it.
So, only way is to see division by 7.
25731=21000+4731=21000+4200+531=21000+4200+490+41....41 is not divisible by 7
23751=21000+2751=21000+2800-49....each term is divisible by 7