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I also agree. Ans: C
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The car is sold for 1.1*0.9*25200
=0.99 * 25200
=(1 - 0.01) * 25200
=25200 - 252
=24948

hence C is the answer
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Answer is C

110% of original price : 1.1 * 25200 = 27720
10% discount : 27720 - (0.1 * 27720) = 24948
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nsp007
Answer is C

110% of original price : 1.1 * 25200 = 27720
10% discount : 27720 - (0.1 * 27720) = 24948

Hey always try to work with smaller numbers first.

Take the price be 100

10% increase is 110
10% discount gives 99

SO if 100 is 99

25200 would be 24948!!!

It helps a lot!!! Not so much in this question but generally always. For instance try this one....
number-system-60282.html#p701427
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AtifS
The original price of a car was $25,200. Because the car owner thought he could get more money for the car, he increased the price of the car to 110% of its original price. After a week, the car had not sold, so the owner then discount ed the price by 10%, and the car was finally sold. What price was the car sold for?
(a) $25,200
(b) $25,000
(c) $24,948
(d) $24,542
(e) $23,658

OA

First increase price by 10% and then Decrease the price by 10%

Let, First price = 100
After 10% increased, Revised Price = 110
Now, After 10% Decrease, Revised Price = 110-(10/100)*110 = 99

i.e. The resultant Price is 1% less than the first Price (100 ---turned--->99)

so $25,200 ---will Turn into---> 99% of $25,200 = (99/100)*$25200 = $24,948

Answer: option C
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AtifS
The original price of a car was $25,200. Because the car owner thought he could get more money for the car, he increased the price of the car to 110% of its original price.

Price of the car after the increase is \(25200*\frac{110}{100}\) => 2520*11

AtifS
After a week, the car had not sold, so the owner then discount ed the price by 10%, and the car was finally sold. What price was the car sold for?

Reduced price of car after the discount is - \(2520*11*\frac{90}{100}\) => 252*99 = 24948

Hence IMHO answer is (C) $24948.
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