Last visit was: 11 Oct 2024, 08:58 It is currently 11 Oct 2024, 08:58
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
SORT BY:
Date
Tags:
Difficulty: 555-605 Level,   Word Problems,                     
Show Tags
Hide Tags
Math Expert
Joined: 02 Sep 2009
Posts: 96065
Own Kudos [?]: 667212 [85]
Given Kudos: 87603
Send PM
Most Helpful Reply
GMAT Club Legend
GMAT Club Legend
Joined: 12 Sep 2015
Posts: 6797
Own Kudos [?]: 31611 [23]
Given Kudos: 799
Location: Canada
Send PM
Retired Moderator
Joined: 10 Oct 2016
Status:Long way to go!
Posts: 1141
Own Kudos [?]: 6508 [18]
Given Kudos: 65
Location: Viet Nam
Send PM
General Discussion
Joined: 17 Feb 2016
Posts: 71
Own Kudos [?]: 156 [4]
Given Kudos: 59
Location: India
Concentration: General Management, Entrepreneurship
GMAT 1: 660 Q47 V36
GPA: 3.12
WE:Education (Internet and New Media)
Send PM
Re: The people in a line waiting to buy tickets to a show are standing one [#permalink]
4
Kudos
Let X,Y,Z be three variables such that
X: No of people standing in front of Adam
Y: No of people standing in between Adam and Beth
Z: No of people standing behind Beth
A: Adam; B: Beth

From the data
\(X+Y=18; Z=?\)

St1: \(X+A+Y+B+Z= 32\)
NS

St2:\(Y+B+Z=23\)
NS

St 1+2:A,B=1;
Three variables three equations and three unknowns so it's solvable

Hence C

Originally posted by RaguramanS on 26 Jun 2017, 08:28.
Last edited by RaguramanS on 26 Jun 2017, 09:18, edited 1 time in total.
Joined: 15 Mar 2015
Posts: 89
Own Kudos [?]: 64 [3]
Given Kudos: 7
Send PM
Re: The people in a line waiting to buy tickets to a show are standing one [#permalink]
3
Kudos
I might be missing something. But isnt the answer A?

We have three sections.

After B, between B and A and before A.

We know after B+before A is 18.

If the total is 32, as given by I, then 32-18-2=12 people should be between Adam and Beth?

Edit:
Found my misstake!

Misread the stem to ask for between a and b and not behind b. :/

Posted from my mobile device

Posted from my mobile device
Retired Moderator
Joined: 22 Aug 2013
Posts: 1180
Own Kudos [?]: 2597 [5]
Given Kudos: 459
Location: India
Send PM
Re: The people in a line waiting to buy tickets to a show are standing one [#permalink]
5
Kudos
As attached in the picture.

Answer should be C.
Attachments

IMG_20170703_125544-2.jpg
IMG_20170703_125544-2.jpg [ 54.81 KiB | Viewed 51335 times ]

Joined: 06 Jul 2016
Posts: 274
Own Kudos [?]: 386 [0]
Given Kudos: 99
Location: Singapore
Concentration: Strategy, Finance
Send PM
Re: The people in a line waiting to buy tickets to a show are standing one [#permalink]
Bunuel
The people in a line waiting to buy tickets to a show are standing one behind the other. Adam and Beth are among the people in the line, and Beth is standing behind Adam with a number of people between them. If the number of people in front of Adam plus the number of people behind Beth is 18, how many people in the line are behind Beth?

(1) There are a total of 32 people in the line.
(2) 23 people in the line are behind Adam.

----(a people ahead of adam)--- Adam---- (N people between Adam and Beth) ---- Beth -------- (b people behind beth)
a + b = 18
b = ?

1) a + adam + n + beth + b = 32
=> adam + n + beth = 14

Then, a = 9, b = 9 or a = 10, b = 8. 2 different values. Insufficient.

2) n + beth + b = 23
Total people in line = ??
Insufficient. We don't have enough information to determine the value of b.

1+2)
a + b = 18
a + adam + n + beth + b = 32
and n + beth + b = 23
=> a = 9
=> b = 9
Sufficient.

C is the answer
Target Test Prep Representative
Joined: 14 Oct 2015
Status:Founder & CEO
Affiliations: Target Test Prep
Posts: 19594
Own Kudos [?]: 23512 [2]
Given Kudos: 287
Location: United States (CA)
Send PM
Re: The people in a line waiting to buy tickets to a show are standing one [#permalink]
1
Kudos
1
Bookmarks
Expert Reply
Bunuel
The people in a line waiting to buy tickets to a show are standing one behind the other. Adam and Beth are among the people in the line, and Beth is standing behind Adam with a number of people between them. If the number of people in front of Adam plus the number of people behind Beth is 18, how many people in the line are behind Beth?

(1) There are a total of 32 people in the line.
(2) 23 people in the line are behind Adam.

We need to determine the number of people in the line who are behind Beth, given that Beth is standing behind Adam and the number of people in front of Adam plus the number of people behind Beth is 18. If we know the number of people who are in front of Adam and the number of people who are strictly between Adam and Beth, then we can determine the number of people who are behind Beth.

Statement One Alone:

There are a total of 32 people in the line.

Since there are a total of 32 people in the line, subtracting Adam, Beth, and the 18 people who are either in front of Adam or behind Beth, we know that there are 12 people between Adam and Beth. However, since we don’t know the exact number of people who are in front of Adam, we can’t determine the number of people who are behind Beth. Statement one alone is not sufficient.

Statement Two Alone:

23 people in the line are behind Adam.

We are given that 23 people in the line are behind Adam. However, since we don’t know the number of people who are between Adam and Beth, we can’t determine the number of people who are behind Beth. Statement two alone is not sufficient.

Statements One and Two Together:

From the two statements, we know that there are a total of 32 people in the line and that 23 people in the line are behind Adam. Thus, there must be 32 - 23 - 1 = 8 people who are in front of Adam (note the number 1 is for Adam). From statement one, we also know that 12 people are between Adam and Beth. Thus, there are 32 - 8 - 12 - 2 = 10 people behind Beth (note the number 2 is for Adam and Beth).

Answer: C
Joined: 07 May 2015
Posts: 77
Own Kudos [?]: 126 [0]
Given Kudos: 152
Location: India
Schools: Darden '21
GPA: 4
Send PM
Re: The people in a line waiting to buy tickets to a show are standing one [#permalink]
Bunuel
The people in a line waiting to buy tickets to a show are standing one behind the other. Adam and Beth are among the people in the line, and Beth is standing behind Adam with a number of people between them. If the number of people in front of Adam plus the number of people behind Beth is 18, how many people in the line are behind Beth?

(1) There are a total of 32 people in the line.
(2) 23 people in the line are behind Adam.

Queue: [X]+A+[Y]+B+[Z]
[X]+[Z]=18
Find [Z]=?

(1) [X]+A+[Y]+B+[Z] = 32
[Y] = 12

(2) [Y]+B+[Z] = 23
[Y]+[Z] = 22

(1)+(2)
[Y]=12 & [Y]+[Z]=22
[Z]=10 (sufficient)
Joined: 28 Jan 2019
Posts: 17
Own Kudos [?]: 5 [0]
Given Kudos: 2
GMAT 1: 730 Q47 V42
Send PM
Re: The people in a line waiting to buy tickets to a show are standing one [#permalink]
Let us visualize the stem this way.

———B——————A—— 

We know there are people behind adam, between beth and adam, and in front of adam. We do not know how many.

People behind beth = x
People between beth and adam = y
People in front of adam = z

Z+X=18

What is X?

1) X+Y+Z +beth + adam = 32 or X+Y+Z = 30.
Z+X = 18
Y+18=30
Y=12
Insuff.

2) B+X+Y=23
X+Y= 22
Insuff.

Combined we have:
X+Y=22
Y=12
X=10
Joined: 30 Jan 2020
Posts: 166
Own Kudos [?]: 81 [0]
Given Kudos: 528
Location: India
WE:Accounting (Accounting)
Send PM
Re: The people in a line waiting to buy tickets to a show are standing one [#permalink]
Bunuel
The people in a line waiting to buy tickets to a show are standing one behind the other. Adam and Beth are among the people in the line, and Beth is standing behind Adam with a number of people between them. If the number of people in front of Adam plus the number of people behind Beth is 18, how many people in the line are behind Beth?

(1) There are a total of 32 people in the line.
(2) 23 people in the line are behind Adam.


(1) Total number of people are 32.
Not much can be inferred from that , we can infer that there are 12 people in between A and B. Number of people number of people in front of Adam plus the number of people behind Beth cannot be inferred correctly. I could be 13+5 or 9+9, etc.

(2) 23 people behind A will mean, B+22 are behind A.

(1&2) Now we know people behind A=23, people in front of A=32-23=9. Therefore people behind B can found, which is 9.

Answer: C
Joined: 22 Feb 2020
Posts: 12
Own Kudos [?]: 1 [0]
Given Kudos: 53
Send PM
Re: The people in a line waiting to buy tickets to a show are standing one [#permalink]
Bunuel
The people in a line waiting to buy tickets to a show are standing one behind the other. Adam and Beth are among the people in the line, and Beth is standing behind Adam with a number of people between them. If the number of people in front of Adam plus the number of people behind Beth is 18, how many people in the line are behind Beth?

(1) There are a total of 32 people in the line.
(2) 23 people in the line are behind Adam.

Here's how I did it.

There is an N variables rule, which says to solve for n variables, you need n distinct equations.
Exceptions:
1. When there is a combination of variables and you can substitute for that, you do not need as many equations to solve.
2. If the variables cancel out – you do not need as many equations.
3. If the equations are identical – you cannot solve.

Let people in front Adam be X, between Adam and Beth Y, and behind Beth Z.

We are given x+z=18 (this is our equation number 1)
(1) x+y+z=32 (the equation number 2)
(2) z=23 (the equation number 3)

So we have 3 equations and 3 variables so the correct answer is C.
Joined: 17 Feb 2017
Posts: 79
Own Kudos [?]: 41 [0]
Given Kudos: 629
Location: India
GMAT 1: 680 Q48 V35
GPA: 4
WE:Consulting (Consulting)
Send PM
Re: The people in a line waiting to buy tickets to a show are standing one [#permalink]
I've solved it slightly differently for those with a similar thought process.
Let the order be as below -
X (People before Adam)....A (Adam)....Z (People between Adam and beth)....B (Beth).....Y(People after Beth)
We know that, X+Y = 18. We need to find Y.

Statement 1
X+A+Z+B+Y=32
Equating X+Y we get => A+Z+B=14
This is not sufficient to answer

Statement 2
Z+B+Y=23
This is not sufficient

Combining
Subtracting equation in Statement 1 from 2 =>
Z+B+Y-Z-B-A=23-14 =>
Y-A=9
A is actually Adam and the count for Adam is obviously 1 since he is one person.
=>Y=9+1=> Y (people after Beth) =10

Hope this helps.
Tutor
Joined: 17 Jul 2019
Posts: 1299
Own Kudos [?]: 1808 [3]
Given Kudos: 66
Location: Canada
GMAT 1: 780 Q51 V45
GMAT 2: 780 Q50 V47
GMAT 3: 770 Q50 V45
Send PM
Re: The people in a line waiting to buy tickets to a show are standing one [#permalink]
3
Kudos
Expert Reply
Video solution from Quant Reasoning:
Subscribe for more: https://www.youtube.com/QuantReasoning? ... irmation=1
Joined: 14 Jul 2010
Status:No dream is too large, no dreamer is too small
Posts: 953
Own Kudos [?]: 5124 [2]
Given Kudos: 690
Concentration: Accounting
Send PM
The people in a line waiting to buy tickets to a show are standing one [#permalink]
2
Kudos
Top Contributor
Bunuel
The people in a line waiting to buy tickets to a show are standing one behind the other. Adam and Beth are among the people in the line, and Beth is standing behind Adam with a number of people between them. If the number of people in front of Adam plus the number of people behind Beth is 18, how many people in the line are behind Beth?

(1) There are a total of 32 people in the line.
(2) 23 people in the line are behind Adam.

\(-----x----Beth---y---Adam---z----\)

Let,
\(x\) people behind Beth
\(y\) people in front of Beth and behind Adam
\(z\) people in front of Adam

Given that, \(x+z=18\)

(1) \(x+y+z + 2=32\) ( The two are Beth and Adam)

\(⇒ x+y+z=30\)

\(⇒ y=30-(x+z)=30-18=12\); Insufficient

(2) \(x+y+1=23\)

\(⇒ x+y=22\); Insufficient.

Considering Both:

\(⇒ x+y=22\)

\(⇒ x+12=22\)

\(∴ x=10;\) Sufficient.

The answer is \(C\)[/quote]
GMAT Club Legend
GMAT Club Legend
Joined: 08 Jul 2010
Status:GMAT/GRE Tutor l Admission Consultant l On-Demand Course creator
Posts: 6059
Own Kudos [?]: 14284 [3]
Given Kudos: 125
Location: India
GMAT: QUANT+DI EXPERT
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
WE:Education (Education)
Send PM
The people in a line waiting to buy tickets to a show are standing one [#permalink]
2
Kudos
1
Bookmarks
Expert Reply
Bunuel
The people in a line waiting to buy tickets to a show are standing one behind the other. Adam and Beth are among the people in the line, and Beth is standing behind Adam with a number of people between them. If the number of people in front of Adam plus the number of people behind Beth is 18, how many people in the line are behind Beth?

(1) There are a total of 32 people in the line.
(2) 23 people in the line are behind Adam.

Answer: Option C

Video solution by GMATinsight

­
User avatar
Non-Human User
Joined: 09 Sep 2013
Posts: 35195
Own Kudos [?]: 891 [0]
Given Kudos: 0
Send PM
Re: The people in a line waiting to buy tickets to a show are standing one [#permalink]
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
GMAT Club Bot
Re: The people in a line waiting to buy tickets to a show are standing one [#permalink]
Moderator:
Math Expert
96065 posts