Bunuel
The product of the sum of 3 consecutive prime numbers and the greatest integer less than the least of the prime numbers is 30. What is the largest of the 3 prime numbers?
A. 2
B. 3
C. 5
D. 7
E. 11
(1) The question is pretty easy as 30 is a very small number and with just two hit and trials the answer could be found.
Least sum = 2+3+5 = 10
So, product = 10*(2-1) = 10
Next set = 3+5+7 = 15
So, product = 15*(3-1) = 30, the right answer is 7.
(2) But say the number was something greater, we could still work upon them.
The factors of 30 are 2,3,5,6,10,15,30.
One of these factors is the integer less than least prime number. 2, 6, 10 and 30 give a prime number when 1 is added to it.
Least sum = 2+3+5 = 10
Thus, the integer must be less than or equal to 30/10 or 3.
Only 2 fits in amongst the factors.
So, the least prime number is 3 and the product is (3+5+7) * 2 or 30.
Answer 7