lhduong221
The students in a literature class have been assigned to read pages 85 through 206 of a novel. At exactly two of those pages (the
earlier page and the l
ater page), the total number of pages remaining to complete the assignment, not including the page currently being read, is equal to the value expressed by the last two digits of the number on that page. For example, the value expressed by the last two digits of 107 is 7.
Select for
Earlier page the number on the earlier page and for
Later page the number on the later page. Make only two selections, one in each column.

An apt question to use the options.
Thu option plus the last two digits should give you 206.
153+53 = 206 = 203+03
But say, you got in a PS and it asked how many such numbers existIt cannot be a 2-digit number, becuas ethen you are looking at double the number and the maximum possible sum would be 99+99 = 198
Any 3-digit number, abc, can be written as 100a+10b+c, so 206 = 100a+10b+c+(10b+c) = 100a+20b+2c ...... 103 = 50a+10b+c..(c would always be 3)
If a=1, then 103=50+10b+c ..... 53 = 10b+c....As b and c are digits, b=5 and c=3.....NUmber = 153
If a=2, then 103=100+10b+c ..... 03 = 10b+c....As b and c are digits, b=0 and c=3.....Number = 203
Thus two possibilities as a = 3 will give us sum>300.
Earlier = 153 and Later = 203
Attachment:
GMAT-Club-Forum-kw4r7a2z.png [ 78.39 KiB | Viewed 3236 times ]