Hi Turkish,

This question is based on a few Number Properties (and you probably already know what they are, you're just not used to thinking about then when dealing with a large group of numbers).

To start, we're told that a group of 99 CONSECUTIVE integers has a sum of 9999. This tells us a couple of things:

1) The AVERAGE of the group will be the "middle" number (meaning the 50th number) in the sequence.

2) The AVERAGE IS 9999/99 = 101

We're asked for the LARGEST number in the sequence. Since we know.....

the 50th number is 101.....

and there are 49 consecutive numbers "below it" and 49 consecutive numbers "above it"...

The LARGEST number must be 101 + 49 = 150

Final Answer:

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Rich

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