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# The table shows partial results of a survey in which consumers were as

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Math Expert
Joined: 02 Sep 2009
Posts: 49271
The table shows partial results of a survey in which consumers were as  [#permalink]

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25 Jun 2018, 05:11
10
00:00

Difficulty:

45% (medium)

Question Stats:

59% (01:18) correct 41% (01:27) wrong based on 289 sessions

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The table shows partial results of a survey in which consumers were asked to indicate which one of six promotional techniques most influenced their decision to buy a new food product. Of those consumers who indicated one of the four techniques listed, what fraction indicated either coupons or store displays?

A. 2/7

B. 1/3

C. 2/5

D. 4/9

E. 1/2

NEW question from GMAT® Official Guide 2019

(PS10307)

Attachment:

PS10307_f011.jpg [ 31.44 KiB | Viewed 2046 times ]

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Re: The table shows partial results of a survey in which consumers were as  [#permalink]

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25 Jun 2018, 05:19

Solution

Given:
• The table shows partial results of a survey in which consumers were asked to indicate which one of six promotional techniques most influenced their decision to buy a new food product

To find:
• Out of those consumers who indicated one of the four techniques listed, what fraction indicated either coupons or store displays

Approach and Working:
If we assume the total number of consumers who responded is 100, then we can write:
• Total consumers responded to the four mentioned techniques = (35 + 22 + 18 + 15) = 90
• Total consumers responded to either coupons or store displays = (22 + 18) = 40
• Therefore, the required fraction = $$\frac{40}{90} = \frac{4}{9}$$

Hence, the correct answer is option D.

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Re: The table shows partial results of a survey in which consumers were as  [#permalink]

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25 Jun 2018, 08:14
Top Contributor
Bunuel wrote:

The table shows partial results of a survey in which consumers were asked to indicate which one of six promotional techniques most influenced their decision to buy a new food product. Of those consumers who indicated one of the four techniques listed, what fraction indicated either coupons or store displays?

A. 2/7

B. 1/3

C. 2/5

D. 4/9

E. 1/2
Attachment:
PS10307_f011.jpg

Since we aren't told the number of people involved in the survey, let's make things easier on ourselves and assign a "nice" value to the number of people involved in the survey.
Let's say there were 100 people in the survey.

When we apply this to our table, we see that 35 people chose TV ads, 22 people chose coupons, 18 people chose store displays, and 15 people chose samples.

35 + 22 + 18 + 15 = 90
So, the table shows the results for 90 consumers

What fraction indicated either coupons or store displays?
Among the 90 consumers surveyed, 22 chose coupons, and 18 chose store displays
22 + 18 = 40
Fraction = 40/90
= 4/9

Cheers,
Brent
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Posts: 2835
Re: The table shows partial results of a survey in which consumers were as  [#permalink]

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26 Jun 2018, 18:01
Bunuel wrote:

The table shows partial results of a survey in which consumers were asked to indicate which one of six promotional techniques most influenced their decision to buy a new food product. Of those consumers who indicated one of the four techniques listed, what fraction indicated either coupons or store displays?

A. 2/7

B. 1/3

C. 2/5

D. 4/9

E. 1/2

Notice that you are instructed to use the incomplete table; the percentages add up to only 90%. So first, you will add the percentages for “Coupons” and “Store Displays,” but then you must divide by the total of 90% to get the final answer, as shown here:

(22 + 18)/(35 + 22 + 18 + 15) = 40/90 = 4/9

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Re: The table shows partial results of a survey in which consumers were as &nbs [#permalink] 26 Jun 2018, 18:01
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