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17 Jul 2015, 01:25
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
75% (02:21) correct
25%
(02:23)
wrong
based on 233
sessions
History
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Not Attempted Yet
The two lines y = x and x = -4 intersect on the coordinate plane. If z represents the area of the figure formed by the intersecting lines and the x-axis, what is the side length of a cube whose surface area is equal to 6z?
A. 16
B. 8√2
C. 8
D. 2√2
E. (√2)/3
Kudos for a correct solution.
A. 16
B. 8√2
C. 8
D. 2√2
E. (√2)/3
Kudos for a correct solution.
ENGRTOMBA2018
Joined: 20 Mar 2014
Last visit: 01 Dec 2021
Posts: 2,325
Given Kudos: 816
Concentration: Finance, Strategy
Schools: Kellogg '18 (M)
GMAT 1: 750 Q49 V44
GPA: 3.7
WE:Engineering (Aerospace and Defense)
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17 Jul 2015, 02:51
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Bunuel
The area enclosed by the 2 lines and the x-axis is a right triangle with coordinates (0,0), (-4,0) and (-4,-4). Thus z = 0.5*4*4 = 8 ---> 6z = 48 ----> Surface area of a cube with side l = 6l^2
Thus 6l^2 = 48 ---> l =\(2\sqrt{2}\) , D is the correct answer.
17 Jul 2015, 10:36
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Bunuel
Line y = x, is a line passing through Ist and IInd Quadrant via origin. And Line x = -4 is a vertical line.
The area intersecting these two lines is a triangle with base = 4 and height = 4. Hence the area, z = 1/2 * 4 * 4 = 8
Given, Surface area of Cube = 6 * side^2 = 6z ==> side^2 = 8
side = 2\sqrt{2}
Option D
