The Ultra 700i is a new racecar. The ultra consumes gasoline at a rate

Question

The Ultra 700i is a new racecar. The ultra consumes gasoline at a rate of P kilometers per liter (P km/L) when its steady state driving speed is at Q kilometers per hour (Q km/h).

In terms of the variables P and Q, select the expression that represents the number of liters of gasoline used in 1 hour of driving at steady state speed, and select the expression that represents the number of liters of gasoline used in a 40 km drive at steady state speed Q. Make only two selections, one in each column.

APram · Accepted Answer

This is a common question on unitary method:

Speed = Q km/h
Gasoline usage (mileage) = P km/L

In 1 hour, car will travel Q km
So no of litres used = Q/P

In P km, gasoline usage is 1L
In 1km, gasoline usage is 1/P L
In 40km, gasoline usage is 40/P L

Kindly give kudos if you liked the explanation!😊

miniB21 · Answer

IT WOULD BE Q/P instead

poojaarora1818 · Answer

Solution:

Given

1. The ultra consumes gasoline at a rate of P kilometers per liter (P \frac{ km}{L} ).

2. Speed when it is at steady state is Q kilometers per hour (Q \frac{ km}{h} ).

Part 1: The number of liters of gasoline used in 1 hour of driving at steady state speed is  \frac{q}{p}

When the speed at steady state is q kilometers per hour and it consumes gasoline at P kilometers per liter, then in an hour it should be  \frac{Q}{P} ( applying unitary method)

Part 2: The number of liters of gasoline used in a 40 km drive at steady state speed Q is  \frac{40}{p} .

Consumes P kilometers per liter, then in 40 kilometers is  \frac{40}{P.}

Bismuth83 · Answer

1. Let's rewrite the two rates P and Q.  P = \frac{Distance}{Liters}  and  Q = \frac{Distance}{Hours} .

2. The first statement is when Hours = 1 and Liters needs to be found. We can rewrite Liters using the equations above,  P = \frac{Distance}{Liters} \rightarrow Liters = \frac{Distance}{P} = \frac{Q * Hours}{P} = \frac{Q}{P} .

3. The second statement is when Distance = 10 and Liters needs to be found. Using the first equation above, Liters can be rewritten with Distance,  P = \frac{Distance}{Liters} \rightarrow Liters = \frac{40}{P} .

4. Our answer will be:   D1 -  \frac{Q}{P}  and D2 -  \frac{40}{P}   .

Liters of gasoline in 1 hour	Liters of gasoline in 40 KM	Statements
		40P
		\(\frac{40}{P}\)
		\(\frac{P}{40}\)
		\(\frac{P}{Q}\)
		\(\frac{Q}{P}\)
		\(\frac{40}{Q}\)

The Ultra 700i is a new racecar. The ultra consumes gasoline at a rate

Prep Toolkit

Top 5 GMAT Debrief Videos

615 to 715 in 15 Days (Ria's Strategies)

More than Quant/Verbal Abilities: Speed vs. Accuracy

745 with Only Self-Prep and GMAT Club

From 555 to 765: 210-point Improvement

Perfect 805 Score Debrief by Julia

My Rewards

GMAT Two-part Analysis (TPA) Questions

The Ultra 700i is a new racecar. The ultra consumes gasoline at a rate

Prep Toolkit

615 to 715 in 15 Days (Ria's Strategies)

More than Quant/Verbal Abilities: Speed vs. Accuracy

745 with Only Self-Prep and GMAT Club

From 555 to 765: 210-point Improvement

Perfect 805 Score Debrief by Julia

My Rewards