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The interesting thing here is the base i.e. 100 is also changing as the no. of managers change. Either plug values or use the formula (99-x)/(100-x) = 98/100 Where x = no. of managers leaving.

There are 100 employees in a room. 99% are managers. How many managers must leave the room to bring down the percentage of manager to 98%?

(A) 1 (B) 2 (C) 50 (D) 49 (E) 97

The interesting thing here is the base i.e. 100 is also changing as the no. of managers change. Either plug values or use the formula (99-x)/(100-x) = 98/100 Where x = no. of managers leaving.

Another approach:

We have 99 managers and 1 director. That 1 director to compose 2% of the total number of people, there must be 50 people in the room, hence 50 managers must leave.

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17 Jun 2015, 02:01

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Re: There are 100 employees in a room. 99% are managers. How man [#permalink]

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30 Oct 2015, 06:57

try plugging in the numbers, it doesn't take that much time as writing the equation if 1 manager leaves, we have 98 managers 99 people. 98/99 - is not 98% if 2 managers leave, we have 97/98 - this is not 98 if 50 managers leave, we have 49 managers, and 50 people, that is 49/50, multiply by 2-> 98/100 or 98%. C.

The interesting thing here is the base i.e. 100 is also changing as the no. of managers change. Either plug values or use the formula (99-x)/(100-x) = 98/100 Where x = no. of managers leaving.

as number of managers changing...other employees remain same so number of other employees before and after removal of managers are same 1% of 100=2%of(100-x) where x=no. of managers removed out of total 100 employees. 1=2/100(100-x) x=50 ans C

Re: There are 100 employees in a room. 99% are managers. How man [#permalink]

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30 Jul 2017, 23:00

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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There are 100 employees in a room. 99% are managers. How many managers must leave the room to bring down the percentage of manager to 98%?

(A) 1 (B) 2 (C) 50 (D) 49 (E) 97

Since there are 100 employees in a room and 99% are managers, there are 99 managers. We can let n = the number of managers to take out and create following equation:

(99 - n)/(100 - n) = 98/100

100(99 - n) = 98(100 - n)

9900 - 100n = 9800 - 98n

100 = 2n

n = 50

Answer: C
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