It is currently 17 Oct 2017, 15:56

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

There are 5 cars to be displayed in 5 parking spaces with

Author Message
Director
Joined: 29 Aug 2005
Posts: 855

Kudos [?]: 487 [0], given: 7

There are 5 cars to be displayed in 5 parking spaces with [#permalink]

Show Tags

09 Nov 2008, 08:17
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

There are 5 cars to be displayed in 5 parking spaces with all the cars facing the same direction.
Of the 5 cars, 3 are red, 1 is blue, and 1 is yellow. If the cars are identical except for color, how
many different display arrangements of the 5 cars are possible?
A. 20
B. 25
C. 40
D. 60
E. 125

Kudos [?]: 487 [0], given: 7

SVP
Joined: 30 Apr 2008
Posts: 1868

Kudos [?]: 615 [1], given: 32

Location: Oklahoma City
Schools: Hard Knocks
Re: GMAT Set 30 - 31 [#permalink]

Show Tags

09 Nov 2008, 08:27
1
KUDOS
This is a permutations/combinations question.

First, disregarding the color, there can be 5! (5! = 120) arrangements. But we have to take into account the many ways the 3 red cards can be arranged among themselves that will not alter the actual color sequence of the arrangement. This is 3! (3! = 6) So that is 120 / 6 = 20

botirvoy wrote:
There are 5 cars to be displayed in 5 parking spaces with all the cars facing the same direction.
Of the 5 cars, 3 are red, 1 is blue, and 1 is yellow. If the cars are identical except for color, how
many different display arrangements of the 5 cars are possible?
A. 20
B. 25
C. 40
D. 60
E. 125

_________________

------------------------------------
J Allen Morris
**I'm pretty sure I'm right, but then again, I'm just a guy with his head up his a\$\$.

GMAT Club Premium Membership - big benefits and savings

Kudos [?]: 615 [1], given: 32

SVP
Joined: 29 Aug 2007
Posts: 2472

Kudos [?]: 842 [0], given: 19

Re: GMAT Set 30 - 31 [#permalink]

Show Tags

09 Nov 2008, 09:29
jallenmorris wrote:
This is a permutations/combinations question.

First, disregarding the color, there can be 5! (5! = 120) arrangements. But we have to take into account the many ways the 3 red cards can be arranged among themselves that will not alter the actual color sequence of the arrangement. This is 3! (3! = 6) So that is 120 / 6 = 20

botirvoy wrote:
There are 5 cars to be displayed in 5 parking spaces with all the cars facing the same direction.
Of the 5 cars, 3 are red, 1 is blue, and 1 is yellow. If the cars are identical except for color, how
many different display arrangements of the 5 cars are possible?
A. 20
B. 25
C. 40
D. 60
E. 125

Nice one.

= 5!/3!
= 20
_________________

Gmat: http://gmatclub.com/forum/everything-you-need-to-prepare-for-the-gmat-revised-77983.html

GT

Kudos [?]: 842 [0], given: 19

Re: GMAT Set 30 - 31   [#permalink] 09 Nov 2008, 09:29
Display posts from previous: Sort by