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It seems I am missing something here.
Is there any other quick way to solve this? I am sure, I will kill some valuable time calculating the root using the quad equation formulae. IMO, its not safe to assume that just using A and B we would find the right solution. Sometimes GMAT tricks us by giving 2 valid answers in option C.
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Bunuel
There are X watermelons of 10 Kg each, and Y Watermelons of R Kg each. The average weight of a watermelon is 12 Kg. What is the value of R?

(1) There are five heavier watermelons more than lighter watermelons.
(2) The weight of the heavier watermelons in Kg is equal to their number

Hi Bunuel

Doesn't Statement B mean that Y*R = Y or Am I missing something here. Please advise.
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Bunuel
There are X watermelons of 10 Kg each, and Y Watermelons of R Kg each. The average weight of a watermelon is 12 Kg. What is the value of R?

(1) There are five heavier watermelons more than lighter watermelons.
(2) The weight of the heavier watermelons in Kg is equal to their number

Hi Bunuel

Doesn't Statement B mean that Y*R = Y or Am I missing something here. Please advise.

Intending meaning is that y = r, but I agree the wording is not prices here.
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Bunuel
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Bunuel
There are X watermelons of 10 Kg each, and Y Watermelons of R Kg each. The average weight of a watermelon is 12 Kg. What is the value of R?

(1) There are five heavier watermelons more than lighter watermelons.
(2) The weight of the heavier watermelons in Kg is equal to their number

Hi Bunuel

Doesn't Statement B mean that Y*R = Y or Am I missing something here. Please advise.

Intending meaning is that y = r, but I agree the wording is not prices here.

Thanks Bunuel.

But doesn't it change the answer in this case. As, \(Y*R = Y\) --> \(Y(R-1)\) = 0 as Y can't be 0, R = 1. Please advise.
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But doesn't it change the answer in this case. As, \(Y*R = Y\) --> \(Y(R-1)\) = 0 as Y can't be 0, R = 1. Please advise.

Ignore this question.

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