Bunuel
Three boys and four men can complete a job together in 8 days. If the work rate of each woman is twice that of a boy and two-thirds that of a man, how many days will it take for six women to complete the same job?
A. 5 5/9 days
B. 6 days
C. 10 days
D. 12 days
E. 15 days
Units of work done by 1 boy = \(b\)
Units of work done by 1 men = \(m\)
Work done per day by 3 boys and 4 men = \(3b + 4m\) units
Work done by 3 boys and 4 men in 8 days = Total Work = \(8*(3b + 4m) = 24b + 32m\) units
Assume that each woman does \(w\) units of work each day.
"...work rate of each woman is twice that of a boy..."\(w = 2b\)
\(b = \frac{w}{2}\)
"...two-thirds that of a man..."\(w = \frac{2}{3}m\)
\(m = \frac{3}{2}w\)
We can use the values to find the total units of work in terms of \('w'\)
\(8*(3b + 4m) = 24b + 32m = 24*(\frac{w}{2}) + 32*(\frac{3}{2}w) = 60w\)
Work done by \(6\) women per day = \(6w\)
Number of days = \(\frac{60w}{6w} = 10\)
Option C