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megafan
Decreasing the original price of an item by 25% and then decreasing the new price by z% is equivalent to decreasing the original price by

(A) \(0.25(1 + \frac{3z}{100})\)

(B) \(0.25(1 + \frac{z}{100})\)

(C) \(0.25(1 - \frac{3z}{100})\)

(D) \(0.75(1 - \frac{z}{100})\)

(E) \(0.75(1 + \frac{3z}{100})\)

Source: Gmat Hacks 1800

Similar question to practice from OG: increasing-the-original-price-of-an-article-by-15-percent-127086.html

Hope it helps.
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Let z=50%

so equivalent change must be 62.5% .So answer is A
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megafan
Decreasing the original price of an item by 25% and then decreasing the new price by z% is equivalent to decreasing the original price by

(A) \(0.25(1 + \frac{3z}{100})\)

(B) \(0.25(1 + \frac{z}{100})\)

(C) \(0.25(1 - \frac{3z}{100})\)

(D) \(0.75(1 - \frac{z}{100})\)

(E) \(0.75(1 + \frac{3z}{100})\)

Source: Gmat Hacks 1800

Similar question to practice from OG: increasing-the-original-price-of-an-article-by-15-percent-127086.html

Hope it helps.


An easy approach is to assume a convenient value for z.

1. Let it be 20%
2. The value is first reduced by 25%. So it becomes 75%
3. The above value is then reduced by 20%. So it becomes 60%
4. So the equivalent reduction is 40%

Choice A gives the same equivalent percentage i.e., 0.25(1 + 3*20/100) = 0.25 (1+0.6) = 0.4 = 40%.

If you want to confirm and have the time, you can test for 1 more value of z.
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For two successive increase/decrease , say a% and b%
the total effective increase/decrease will be a+b+ab/100

So here the total decrease will be = -25 -z +25z/100 (for price decrease the sign will be -ve)
= -[25 + 75z/100]
= -[.25+ .75z/100] % (converting to Percentage decrease)
= - .25[1+3z/100] % (-ve sign implies decrease in price)


So the total percentage decrease is .25[1+3z/100] ----- option A
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Simple!

If A is decreased by x% =>
outcome = A (1 - (x/100) ).

use this approach to solve this.

You will end at option A.
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Decreasing the original price of an item by 25% and then decreasing the new price by z% is equivalent to decreasing the original price by

(A) 0.25(1+3z/100)

(B) 0.25(1+z/100)

(C) 0.25(1−3z/100)

(D) 0.75(1−z/100)

(E) 0.75(1+3z/100)

Done by POE. So 75 +z/100(75) = 75 [1 + z/100] approx 1/3rd and a little more

So only A fits 0.25 *3z/100 +1 as closest to 1/3rd plus one. Rest do not add up.

Kudos if the answer was useful :)
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megafan
Decreasing the original price of an item by 25% and then decreasing the new price by z% is equivalent to decreasing the original price by

(A) \(0.25(1 + \frac{3z}{100})\)

(B) \(0.25(1 + \frac{z}{100})\)

(C) \(0.25(1 - \frac{3z}{100})\)

(D) \(0.75(1 - \frac{z}{100})\)

(E) \(0.75(1 + \frac{3z}{100})\)

Source: Gmat Hacks 1800

can anybody help, are we looking for the percentage decrease or are we looking the amount of decrease ?
Let initial amount be 100 after 25% discount we get 75 then z% discount will give \(\frac{(100-z)}{100}*75\) = \(\frac{100-z}{4}*3\)

So equivalent discount is
100 -\(\frac{300+3z}{4}\)
\(\frac{100+3z}{4}\)

Well as option A after simplification states \(\frac{100+3z}{400}\)

So why this difference ?

( Guaranteed Kudos for anyone who can help with this, thank you)
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megafan
Decreasing the original price of an item by 25% and then decreasing the new price by z% is equivalent to decreasing the original price by

(A) \(0.25(1 + \frac{3z}{100})\)

(B) \(0.25(1 + \frac{z}{100})\)

(C) \(0.25(1 - \frac{3z}{100})\)

(D) \(0.75(1 - \frac{z}{100})\)

(E) \(0.75(1 + \frac{3z}{100})\)

Source: Gmat Hacks 1800

can anybody help, are we looking for the percentage decrease or are we looking the amount of decrease ?
Let initial amount be 100 after 25% discount we get 75 then z% discount will give \(\frac{(100-z)}{100}*75\) = \(\frac{100-z}{4}*3\)

So equivalent discount is
100 -\(\frac{300+3z}{4}\)
\(\frac{100+3z}{4}\)

Well as option A after simplification states \(\frac{100+3z}{400}\)

So why this difference ?

( Guaranteed Kudos for anyone who can help with this, thank you)

Responding to a pm:

You can easily figure this out by taking numbers instead of variables to understand the concept here:

Say there are 2 discounts - 25% and 20%
Question: What is the overall discount? (it will be in percentage terms only since no actual numbers are provided)

If you assume $100 and then arrive at $75 and then at 80/100 * $75 = $60

Then using the logic used by you above, you say this is $100 - $60 = $40

This 40 is your (100 + 3z)/4

But note that the answer cannot be 40. The overall discount will be in terms of percentage. We say that the discount is 40 per cent i.e. 40/100 i.e. 40%.

So it will be (100 + 3z)/400
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megafan
Decreasing the original price of an item by 25% and then decreasing the new price by z% is equivalent to decreasing the original price by

(A) \(0.25(1 + \frac{3z}{100})\)

(B) \(0.25(1 + \frac{z}{100})\)

(C) \(0.25(1 - \frac{3z}{100})\)

(D) \(0.75(1 - \frac{z}{100})\)

(E) \(0.75(1 + \frac{3z}{100})\)

Source: Gmat Hacks 1800

can anybody help, are we looking for the percentage decrease or are we looking the amount of decrease ?
Let initial amount be 100 after 25% discount we get 75 then z% discount will give \(\frac{(100-z)}{100}*75\) = \(\frac{100-z}{4}*3\)

So equivalent discount is
100 -\(\frac{300+3z}{4}\)
\(\frac{100+3z}{4}\)

Well as option A after simplification states \(\frac{100+3z}{400}\)

So why this difference ?

( Guaranteed Kudos for anyone who can help with this, thank you)

Responding to a pm:

You can easily figure this out by taking numbers instead of variables to understand the concept here:

Say there are 2 discounts - 25% and 20%
Question: What is the overall discount? (it will be in percentage terms only since no actual numbers are provided)

If you assume $100 and then arrive at $75 and then at 80/100 * $75 = $60

Then using the logic used by you above, you say this is $100 - $60 = $40

This 40 is your (100 + 3z)/4

But note that the answer cannot be 40. The overall discount will be in terms of percentage. We say that the discount is 40 per cent i.e. 40/100 i.e. 40%.

So it will be (100 + 3z)/400

Thank you , for clearing this up, Karishma. Without your guidance it would really have been difficult to understand this. Your awesomeness simply dazzles!
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megafan
Decreasing the original price of an item by 25% and then decreasing the new price by z% is equivalent to decreasing the original price by

(A) \(0.25(1 + \frac{3z}{100})\)

(B) \(0.25(1 + \frac{z}{100})\)

(C) \(0.25(1 - \frac{3z}{100})\)

(D) \(0.75(1 - \frac{z}{100})\)

(E) \(0.75(1 + \frac{3z}{100})\)

We can let the original price be 100 and z be 20. Thus the final price is:

100(75/100)(1 - 20/100) = 75(80/100) = 60

We see that the price has reduced by 40%.

Now let’s analyze the answer choices:

A) 0.25(1 + 3z/100)

0.25(1 + 3(20)/100) = 0.25(1.6) = 0.4 = 40%

We see that choice A could be the correct answer. We also see that in choices B, C and E couldn’t possibly be the correct answer. Let’s see if choice D also yield 40% (if it doesn’t, then choice A MUST be the correct answer; if it does, then we have to use another number for z).

D) 0.75(1 - z/100)

0.75(1 - 20/100) = 0.75(0.8) = 0.6 ≠ 40%

Answer: A
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megafan
Decreasing the original price of an item by 25% and then decreasing the new price by z% is equivalent to decreasing the original price by

(A) \(0.25(1 + \frac{3z}{100})\)

(B) \(0.25(1 + \frac{z}{100})\)

(C) \(0.25(1 - \frac{3z}{100})\)

(D) \(0.75(1 - \frac{z}{100})\)

(E) \(0.75(1 + \frac{3z}{100})\)

Source: Gmat Hacks 1800

One simple approach is to use the formula of equivalent percentage.
If one discount is A% and subsequent discount is B%, then equivalent discount is
\(Eq. Dis. percent= A+B -\frac{AB}{100}\)
So, \(Eq. dis. percent= 25+z-\frac{25z}{100}\)
\( =25+\frac{75z}{100}\)
\( =25(1+\frac{3z}{100})\)
Since the question is asking final value then,
\(Final value =\frac{25}{100}(1+\frac{3z}{100})\)
\(Final value =0.25(1+\frac{3z}{100})\)............ hence (A)
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megafan
Decreasing the original price of an item by 25% and then decreasing the new price by z% is equivalent to decreasing the original price by

(A) \(0.25(1 + \frac{3z}{100})\)

(B) \(0.25(1 + \frac{z}{100})\)

(C) \(0.25(1 - \frac{3z}{100})\)

(D) \(0.75(1 - \frac{z}{100})\)

(E) \(0.75(1 + \frac{3z}{100})\)

Source: Gmat Hacks 1800
­I believe, that assuming an initial selling price and a value of z will help to find the answer faster. I was thinking of an alternate approach by using the consecutive discount method, and this seems easier. I assumed the selling price as 100 and z as 100, and found a value there. Then put the same in options and (A) was a match.­ However, if we use the later method then overall discount becomes 25+z -25z/100 = 25(1+3z/100). So overall decrease will be by 25/100 * (1+3z/100) = 0.25(1+3z/100). Option (A) is correct.
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megafan
Asked: Decreasing the original price of an item by 25% and then decreasing the new price by z% is equivalent to decreasing the original price by
Let the original price of an item be x.
Decreasing the original price of an item by 25% results in price = .75x
Then decreasing the new price by z% results in price = .75x(1-z/100)

Let the price be decreased by y in total
\(.75x(1-\frac{z}{100}) = x(1 - y)\)
\(1-y = .75(1-\frac{z}{100})\)
\(y = 1 - .75(1-\frac{z}{100}) = .25 + \frac{.75z}{100} = .25(1+\frac{3z}{100})\)

IMO A
­
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