Last visit was: 24 Apr 2026, 09:36 It is currently 24 Apr 2026, 09:36
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
mikemcgarry
User avatar
Magoosh GMAT Instructor
Joined: 28 Dec 2011
Last visit: 06 Aug 2018
Posts: 4,474
Own Kudos:
30,882
 [49]
Given Kudos: 130
Expert
Expert reply
Posts: 4,474
Kudos: 30,882
 [49]
1
Kudos
Add Kudos
48
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
sterling19
Joined: 14 Sep 2014
Last visit: 03 Jun 2015
Posts: 97
Own Kudos:
155
 [19]
Given Kudos: 236
Concentration: Technology, Finance
WE:Analyst (Other)
Posts: 97
Kudos: 155
 [19]
10
Kudos
Add Kudos
9
Bookmarks
Bookmark this Post
avatar
PareshGmat
Joined: 27 Dec 2012
Last visit: 10 Jul 2016
Posts: 1,531
Own Kudos:
8,274
 [5]
Given Kudos: 193
Status:The Best Or Nothing
Location: India
Concentration: General Management, Technology
WE:Information Technology (Computer Software)
Posts: 1,531
Kudos: 8,274
 [5]
4
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
General Discussion
User avatar
onamarif
Joined: 03 Feb 2017
Last visit: 25 Sep 2017
Posts: 20
Own Kudos:
46
 [4]
Given Kudos: 29
Posts: 20
Kudos: 46
 [4]
2
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
\(K^\frac{3}{2}\) = \(1.5* K^\frac{5}{4}\)
\(K^\frac{3}{2}/K^\frac{5}{4}\) = \(\frac{3}{2}\)
\(K^\frac{3}{2}-^\frac{5}{4}\) = \(\frac{3}{2}\)
\(K^\frac{1}{4}\) =\(\frac{3}{2}\)
So, K=\(\frac{81}{16}\)
User avatar
ameyaprabhu
Joined: 28 Apr 2016
Last visit: 09 Aug 2017
Posts: 66
Own Kudos:
Given Kudos: 79
Posts: 66
Kudos: 34
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi,

Is it wrong to consider k^5/4 as K^1? (can we do numerator - denominator for the exponents?)
User avatar
mikemcgarry
User avatar
Magoosh GMAT Instructor
Joined: 28 Dec 2011
Last visit: 06 Aug 2018
Posts: 4,474
Own Kudos:
Given Kudos: 130
Expert
Expert reply
Posts: 4,474
Kudos: 30,882
Kudos
Add Kudos
Bookmarks
Bookmark this Post
ameyaprabhu
Hi,

Is it wrong to consider k^5/4 as K^1? (can we do numerator - denominator for the exponents?)
Dear ameyaprabhu,

I'm happy to respond. :-)

My friend, I do not understand your question. Are you asking how to make a fraction appear as an exponent using the LaTex math font? Are you asking what it means to have a fraction in the exponent? I don't know whether you are asking a purely mathematical question or whether you are asking a question about this site. Please clarify.

I will also recommend this blog:
Asking Excellent Questions

Mike :-)
User avatar
TimeTraveller
Joined: 28 Jun 2015
Last visit: 29 Jul 2017
Posts: 237
Own Kudos:
361
 [3]
Given Kudos: 47
Concentration: Finance
GPA: 3.5
Posts: 237
Kudos: 361
 [3]
2
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
mikemcgarry
If \(K^{3/2}\) is 50% bigger than \(K^{5/4}\), what is the value of K?

(A) \(\frac{\sqrt{3}}{\sqrt{2}}\)

(B) \(\frac{3}{2}\)

(C) \(\frac{9}{4}\)

(D) \(\frac{27}{8}\)

(E) \(\frac{81}{16}\)


For a set of challenging problems on exponent, as well as the OA to this particular question, see:
https://magoosh.com/gmat/2014/challengi ... and-roots/

\(k^{3/2} = 1.5(k^{5/4})\)

\(k^{{\frac{3}{2}} - {\frac{5}{4}}} = 1.5\)

\(\frac{3}{2} - \frac{5}{4} = \frac{12-10}{8} = \frac{1}{4}\)

\(k^{1/4} = 1.5\)

\(k = (1.5)^4 = (\frac{3}{2})^4 = \frac{81}{16}\). Ans - E.
User avatar
ameyaprabhu
Joined: 28 Apr 2016
Last visit: 09 Aug 2017
Posts: 66
Own Kudos:
Given Kudos: 79
Posts: 66
Kudos: 34
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi Mike,

While I know K^m/n = nth root of k raised to m, my doubt was more fundamental, in that, I was wondering whether we can simplify the expression do K^(m-n). eg. k^5/4 simply becomes K (but doing so doesn't seem to work for this problem and hence I was questioning my basics)
User avatar
TimeTraveller
Joined: 28 Jun 2015
Last visit: 29 Jul 2017
Posts: 237
Own Kudos:
361
 [1]
Given Kudos: 47
Concentration: Finance
GPA: 3.5
Posts: 237
Kudos: 361
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
ameyaprabhu
Hi Mike,

While I know K^m/n = nth root of k raised to m, my doubt was more fundamental, in that, I was wondering whether we can simplify the expression do K^(m-n). eg. k^5/4 simply becomes K (but doing so doesn't seem to work for this problem and hence I was questioning my basics)

Hi,

Remember the fraction rule: \(\frac{a^{m}}{a^{n}} = a^{m-n}\).

Here we have \(k^{m}/k^{n}\), where \(m = 3/2\), and \(n = 5/4\), so we get \(k^{m-n} = k^{3/2 - 5/4} = k^{1/4}\). If it was \(k^5/k^4\), that would be equal to \(k^{5-4} = k^1\). Hope you see the difference.
User avatar
mrinal0308
Joined: 12 Feb 2015
Last visit: 02 Oct 2018
Posts: 93
Own Kudos:
Given Kudos: 9
Location: India
Concentration: Technology, Operations
GMAT 1: 680 Q50 V31
GPA: 3.9
WE:Information Technology (Computer Software)
GMAT 1: 680 Q50 V31
Posts: 93
Kudos: 186
Kudos
Add Kudos
Bookmarks
Bookmark this Post
mikemcgarry
If \(K^{3/2}\) is 50% bigger than \(K^{5/4}\), what is the value of K?

(A) \(\frac{\sqrt{3}}{\sqrt{2}}\)

(B) \(\frac{3}{2}\)

(C) \(\frac{9}{4}\)

(D) \(\frac{27}{8}\)

(E) \(\frac{81}{16}\)


For a set of challenging problems on exponent, as well as the OA to this particular question, see:
https://magoosh.com/gmat/2014/challengi ... and-roots/

The expression is:

K^(3/2)=1.5xK^(5/4)

Squaring both sides, we get:
K^3=(1.5)^2 x K^(5/2)

Squaring again,

K^6=(1.5)^4 x K^5

Simplifying the powers of K,

K= (1.5)^4

that gives, K=81/16 on expanding above as fraction.

Answer: E

============ Pls Hit +1 KUDOS if you liked my reply =================================
Kudos
Add Kudos
Bookmarks
Bookmark this Post
E.
As k^3/2=1.5*k^5/4
k^6/4-5/4=1.5
k^1/4=1.5 i.e. 3/2
k= 81/16
User avatar
ScottTargetTestPrep
User avatar
Target Test Prep Representative
Joined: 14 Oct 2015
Last visit: 24 Apr 2026
Posts: 22,283
Own Kudos:
26,534
 [1]
Given Kudos: 302
Status:Founder & CEO
Affiliations: Target Test Prep
Location: United States (CA)
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 22,283
Kudos: 26,534
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
mikemcgarry
If \(K^{3/2}\) is 50% bigger than \(K^{5/4}\), what is the value of K?

(A) \(\frac{\sqrt{3}}{\sqrt{2}}\)

(B) \(\frac{3}{2}\)

(C) \(\frac{9}{4}\)

(D) \(\frac{27}{8}\)

(E) \(\frac{81}{16}\)


Solution:

We can create the equation:

K^(3/2) = 1.5K^(5/4)

Multiplying both sides by 2, we have:

2K^(3/2) = 3K^(5/4)

Raising both sides to the 4th power, we have:

16K^6 = 81K^5

K^6/K^5 = 81/16

K = 81/16

Answer: E
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,973
Own Kudos:
Posts: 38,973
Kudos: 1,117
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
Moderators:
Math Expert
109814 posts
Tuck School Moderator
853 posts