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Sub 505 (Easy)|   Algebra|                           
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Bunuel
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Bunuel
If (1 – 1.25)N = 1, then N =

(A) −400
(B) −140
(C) −4
(D) 4
(E) 400

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(1 – 1.25)N = 1
Simplify to get: -0.25N = 1
Rewrite as (-1/4)N = 1
Multiply both sides by -4 to get: N = -4

Answer: C

Cheers,
Brent
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Bunuel
If (1 – 1.25)N = 1, then N =

(A) −400
(B) −140
(C) −4
(D) 4
(E) 400

Kudos for a correct solution.
\((1 – 1.25)N = 1\) --> \((-0.25)N = 1\) --> \(N = \frac{1}{-0.25}\) --> \(N = \frac{1}{-1/4}\) --> \(N = -4\)
Answer choice C.
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Bunuel
If (1 – 1.25)N = 1, then N =

(A) −400
(B) −140
(C) −4
(D) 4
(E) 400

Kudos for a correct solution.

We need to determine the value of N in the equation (1 – 1.25)N = 1.

(1 – 1.25)N = 1

(-0.25)N = 1

(-1/4)N = 1

N = -4

Answer: C
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Bunuel
If (1 – 1.25)N = 1, then N =

(A) −400
(B) −140
(C) −4
(D) 4
(E) 400

Kudos for a correct solution.

(1 – 1.25)N = 1

Or (\(1\) – \(\frac{5}{4}\))N = \(1\)

Or \(\frac{-1}{4}\)N = \(1\)

So, N = - 4

Hence answer will definitely be (C)
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Bunuel
If (1 – 1.25)N = 1, then N =

(A) −400
(B) −140
(C) −4
(D) 4
(E) 400

Kudos for a correct solution.

\(1 -\) \(\frac{125}{100}\) \(*N\) = 1

\(-\)\(\frac{25}{100}\) \(*N\) = 1

\(N =\) \(-\)\(\frac{100}{25}\)
\(N =\) \(- 4\)
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1-1.25 = -.25
n/-4 = 1
cross multiply and you get n = -4
C
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Bunuel
If (1 – 1.25)N = 1, then N =

(A) −400
(B) −140
(C) −4
(D) 4
(E) 400

Kudos for a correct solution.


As we are deducting 1.25 from 1, ultimate result will be negative. Eliminate D and E. -0..25 is equivalent to 1/4. so ultimate result will be -4.

Thus the best answer is Option C.
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Bunuel
If (1 – 1.25)N = 1, then N =

(A) −400
(B) −140
(C) −4
(D) 4
(E) 400

Kudos for a correct solution.
In this case we have 1-(1.25 is 5/4), so that's going to be -1/4.

the correct answer choice is C.
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Bunuel
If (1 – 1.25)N = 1, then N =

(A) −400
(B) −140
(C) −4
(D) 4
(E) 400

Kudos for a correct solution.

-.25N=1
N=-4

IMO C

Posted from my mobile device
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Bunuel
If (1 – 1.25)N = 1, then N =

(A) −400
(B) −140
(C) −4
(D) 4
(E) 400

Answer: Option C

Video solution by GMATinsight

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