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haighter
Joined: 05 Sep 2022
Last visit: 23 Apr 2024
Posts: 7
Given Kudos: 12
Location: Canada
Schools: Booth '26 (D) Columbia CBS'26 (D) Darden '26 (A) Duke '20 (WL) Cornell '26 (A$$) Kellogg '26 (A) Stern '26 (A$$$$)
GMAT 1: 740 Q47 V45
GMAT 2: 760 Q47 V48
GPA: 3
WE:Accounting (Accounting)
Schools: Booth '26 (D) Columbia CBS'26 (D) Darden '26 (A) Duke '20 (WL) Cornell '26 (A$$) Kellogg '26 (A) Stern '26 (A$$$$)
GMAT 2: 760 Q47 V48
Posts: 7
19 Dec 2022, 20:46
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johng2016
It should be noted that this problem does not have to be solved all the way through to get to the correct answer.
If 90% of respondents ranked chocolate before vanilla, that means there are only six respondents left who ranked either vanilla before strawberry or strawberry before vanilla. So you're left with either answer A or answer B and it's an educated guess from there!
28 Jul 2023, 04:47
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A useful formula for two overlapping sets:
Total = Group 1 + Group 2 - Both + Neither
The formula above can be applied to this problem as follows:
Total = (number who ranked V before C) + (number who ranked V before S) - (number who ranked V before BOTH C AND S) + (number who ranked V before NEITHER C NOR S)
According to the prompt:
Total = 60
Number who ranked V before C = (1/10)(60) = 6
Number who ranked V before S = (1/3)(60) = 20
Number who ranked V before neither S nor C = number who ranked V last = (3/5)(60) = 36
Plugging these values into the blue equation above, we get:
60 = 6 + 20 - (number who ranked V before both S and C) + 36
60 = 62 - (number who ranked V before both S and C)
Number who ranked V before both S and C = 62-60 = 2
Thus, the number who ranked vanilla first = 2
Total = Group 1 + Group 2 - Both + Neither
johng2016
The formula above can be applied to this problem as follows:
Total = (number who ranked V before C) + (number who ranked V before S) - (number who ranked V before BOTH C AND S) + (number who ranked V before NEITHER C NOR S)
According to the prompt:
Total = 60
Number who ranked V before C = (1/10)(60) = 6
Number who ranked V before S = (1/3)(60) = 20
Number who ranked V before neither S nor C = number who ranked V last = (3/5)(60) = 36
Plugging these values into the blue equation above, we get:
60 = 6 + 20 - (number who ranked V before both S and C) + 36
60 = 62 - (number who ranked V before both S and C)
Number who ranked V before both S and C = 62-60 = 2
Thus, the number who ranked vanilla first = 2
15 Oct 2023, 02:49
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