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Reserving this space to post the official solution. :)
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stonecold
Nice one.
Here is what i did ==>

In 7 years => 200 becomes => 600

So the value becomes thrice of itself in every 7 years.

200-------600------1800------5400------

After 7 years->For an additional $4800 => Value must be 600+4800=> $5400

Hence she must wait an additional 14 years.

Smash that B.



Im not sure how u got 600 because 200 increased by 200% in 7 years when compounded annually will be much higher...

Could u pls explain?

I don't know if I have understood it right..

Thanks in advance..
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Jane's investment of $200 increased by 200% in 7 years when compounded annually. If she wants to earn an additional compound interest of $4800, for how many more years should she keep her money invested?


    A. 7 years
    B. 14 years
    C. 21 years
    D. 24 years
    E. 30 years

We see that the original investment actually triples from $200 to $600 in 7 years . So it will triple again in another 7 years, from $600 to $1800. It will again triple in 7 more years, from $1800 to $5400. At this point, we see that the earning in additional interest is exactly 5400 - 600 = $4800. Therefore, it takes 7 + 7 = 14 additional years to earn $4800 after the investment accumulated to $600.

Answer: B
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200$ became 600$ and we need to make additional 4800$ after 600$ which totals = 5400
now we know 200(1+r/100)^7 = 600
(1+r/100) = 3^1/7

600(1+r/100)^n = 5400
3^n/7 = 3^2
n/7 = 2
n = 14
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Here's an algebraic solution:


\(600 = 200(1+i)^7\); an increase by 200% is a 3x increase
\(3= (1+i)^7\) -- (1)

Now she wants to earn 4800 additional interest. That means she wants to earn 600 + 4800 = 5400 total.

\(5400 = 200*(1+i)^{7+x}\); where x = additional time after 7 years.
\(5400 = 200*(1+i)^7*(1+i)^x\)

Substitute \(3= (1+i)^7\) and simplify

\(9 = (1+i)^x\); now if you square eq (1) on both sides you get \(3^2 = (1+i)^{7*2}\)
Therefore, \(9 = (1+i)^{14}\)

And time after initial 7 years = 14 years
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Jane's investment of $200 increased by 200% in 7 years when compounded annually.

If she wants to earn an additional compound interest of $4800, for how many more years should she keep her money invested?

Let the rate of interest be r per annum

200 + 200%*200 = 600 = 200 (1+r)ˆ7
(1+r)ˆ7 = 3

Let the number of years she should keep the money be n.
For additional compound interest of $4800
600+4800 = 600(1+r)ˆn
(1+r)ˆn = 9 = 3ˆ2 = ((1+r)ˆ7)ˆ2 = (1+r)ˆ14
n = 14

IMO B
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