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The question asks for the least value that satisfies the inequality 9/x > 2

The quickest method is to test the answers

A. 9/0 = 0 but 0 is <2 not greater than 2...Incorrect
B. 9/1 = 9 9>2 this works.
C 9/4 =2.25 although 2.25 is greater than 2, 4 is not the least value for x that would make the inequality work

For this reason B is correct.
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dcummins
The question asks for the least value that satisfies the inequality 9/x > 2

The quickest method is to test the answers

A. 9/0 = 0 but 0 is <2 not greater than 2...Incorrect
B. 9/1 = 9 9>2 this works.
C 9/4 =2.25 although 2.25 is greater than 2, 4 is not the least value for x that would make the inequality work

For this reason B is correct.

IMHO, regarding option A, we can just say that the denominator cannot be 0 at all! So there's actually no need to do any kind of calculation.
:)
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gmatt1476
If there is a least integer that satisfies the inequality 9/x ≥ 2, what is that least integer?

A. 0
B. 1
C. 4
D. 5
E. There is not a least integer that satisfies the inequality.


PS41471.01

Start with the least number...

option A :- 9 / 0 = undefined So option A is discarded.

Option B :- Put x = 1 and check .
9 / 1 >= 2 ...So option B satisfies the inequality.
B is the answer.

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Guys is there a way to solve this using algebra and not by plugging in?

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Bunuel integer x is not specified to be either positive or negative.

Hence if x was negative the expression would become \(x>=9/2\) --> least integer 4.

However, if we consider x being positive, the expression gives x=1 as least integer.

I think the question stem shoud specify that x is positive.
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Hi All,

We're given the inequality 9/X ≥ 2. We're asked for the LEAST integer that satisfies the inequality. While this question is relatively straight-forward, it's written in such a way that you might lose track of what you're ultimately solving for. To reiterate, we want the SMALLEST INTEGER that "fits" the inequality.

We need 9/X to be greater than or equal to 2, so we need X to be POSITIVE. We are NOT asked to make 9/X as small as possible.

Thus, the smallest positive integer that 'fits' the inequality is 1.

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gmatt1476
If there is a least integer that satisfies the inequality 9/x ≥ 2, what is that least integer?

A. 0
B. 1
C. 4
D. 5
E. There is not a least integer that satisfies the inequality.


PS41471.01

If 9/x is greater than 2, we know that x is POSITIVE

Since x is POSITIVE, we can eliminate answer choice A.
At this point, we can test values, starting with the smallest possible value.

B) 1
If x = 1, our inequality becomes 9/1 ≥ 2, which is TRUE
Done!

Answer: B

Cheers,
Brent
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gmatt1476
If there is a least integer that satisfies the inequality 9/x ≥ 2, what is that least integer?

A. 0
B. 1
C. 4
D. 5
E. There is not a least integer that satisfies the inequality.


PS41471.01


We see that x can’t be 0 or negative (otherwise, 9/x will be undefined or negative, respectively). So x must be positive, and if x = 1, we have 9/x = 9/1 = 9 ≥ 2.

Answer: B
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dcummins
The question asks for the least value that satisfies the inequality 9/x > 2

The quickest method is to test the answers

A. 9/0 = 0 but 0 is <2 not greater than 2...Incorrect
B. 9/1 = 9 9>2 this works.
C 9/4 =2.25 although 2.25 is greater than 2, 4 is not the least value for x that would make the inequality work

For this reason B is correct.

if the question asked for greatest integer then would 4 be the answer then ?
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Hi mockingjay,

YES - if the question was changed and we were asked for the largest integer-value of X, then the answer would be 4.

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Unbelievable, do you really think 9/0 undefined? It’s infinite and infinity is definitely greater than 2. If this is an official question, I question the test are we to understand that the test limits it’s understanding to algebra and so those of us who have a calculus background are at a disadvantage? Too bad. Bad question

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Dear IanStewart,

Technically, if X were 0 (9/X would be infinity), then the equality is also satisfied right?

A bit confused on the concept. Please help sir :)
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varotkorn

Technically, if X were 0 (9/X would be infinity), then the equality is also satisfied right?

A bit confused on the concept. Please help sir :)

9/0 is not equal to "infinity". 9/0 is "undefined"; it is not a number at all.

To see why it does not make sense to think of 9/0 as being "infinity", you can borrow from calculus the concept of a 'limit' (which of course, is not something explicitly tested on the GMAT, though certain estimation questions allude to limits in a simple enough way that you don't need to know about them to get an answer). If you think of the expression 9/x, and start with x = 1 and then imagine making x smaller and smaller so it gets closer and closer to zero, the value of 9/x gets bigger and bigger. So you might say, because of that, that "9/0 is infinity". But then imagine starting with x = -1, and making x bigger and bigger so it gets closer to zero. Then 9/x gets more and more negative -- it gets smaller and smaller. So you might then think that "9/0 is negative infinity". Those two interpretations are clearly contradictory, which is why it doesn't make sense to think that 9/0 has any single "value" at all, and is one reason that 9/0 is simply undefined (the other reason being that infinity is not a number in the first place).
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This is how I approached the question

I simplified the inequality first,

9/x >= 2

multiply by 1/9

1/x >= 2/9

flip both sides, inequality also flips

x <= 9/2
x<= 4.5

Hence I selected E as the minimum value can be minus infinity. Please someone tell me why this approach is incorrect
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hk111
This is how I approached the question

I simplified the inequality first,

9/x >= 2

multiply by 1/9

1/x >= 2/9

flip both sides, inequality also flips

x <= 9/2
x<= 4.5

Hence I selected E as the minimum value can be minus infinity. Please someone tell me why this approach is incorrect

Hi hk111,

We're given the inequality 9/X ≥ 2. We're asked for the LEAST integer that satisfies the inequality. This means that we want the SMALLEST INTEGER that "fits" the inequality.

We need 9/X to be greater than or equal to 2, so we need X to be POSITIVE. Re-writing the inequality in the way that you did was fine, BUT you lost track of what the question was asking for. We were NOT asked to make 9/X as small as possible. We were essentially asked for the smallest positive integer that 'fits' the inequality - and that is 1.

GMAT assassins aren't born, they're made,
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the question is saying find the least integer which is equal to or greater than two , while there are integers that will satisfy the greater than term but none of the integer will satisfy that equal to term. can someone please clear my doubt?
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Devoshish
the question is saying find the least integer which is equal to or greater than two , while there are integers that will satisfy the greater than term but none of the integer will satisfy that equal to term. can someone please clear my doubt?


Hi Devoshish,

The prompt actually asks us to find the least INTEGER value (for X) that satisfies the given inequality 9/X ≥ 2. While this question is relatively straight-forward, it's written in such a way that you might lose track of what you're ultimately solving for.

We need 9/X to be greater than or equal to 2, so we need X to be POSITIVE. We are NOT asked to make 9/X as small as possible; we are asked for the smallest integer value that X could be and still satisfy the inequality.

Thus, the smallest positive integer that 'fits' the inequality is 1.

GMAT assassins aren't born, they're made,
Rich

Contact Rich at: [email protected]
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