WarriorWithin
Two typists undertake to do a job. The second typist begin working one hour after the first. Three hours after the first typist has begun working, there is still (9/20) of the work to be done. When the assignment is completed, it turns out that each typist has done half the work. How many hours would it take each one to do the whole job individually?
A. 12 hours and 8 hours
B. 8 hours and 5.6 hours
C. 10 hours and 8 hours
D. 5 hours and 4 hours
E. 4 hours and 8 hours
Let the 1st Typist (A) take x hours and the second typist (B) take y hours.
Work done in 1 hour by A = \(\frac{1}{x}\) and work done in 1 hour by B = \(\frac{1}{y}\)
Now after 3 hours, A has worked for 3 hours and B has worked for 2 hours (starts 1 hour later)
The fraction of work completed by A in 3 hours = \(\frac{3}{x}\) and by B in 2 hours = \(\frac{2}{y}\)
The amount of work completed = \(1 - \frac{9}{20} = \frac{11}{20}\)
So, \(\frac{3}{x} + \frac{2}{y} = \frac{11}{20}\)
At this point, we can use the options to get our answer
Option A: \(\frac{3}{12} + \frac{2}{8} = \frac{1}{4} + \frac{1}{4} = \frac{1}{2}\)
Option B: \(\frac{3}{8} + \frac{2}{5.6} = \frac{3}{8} + \frac{5}{14} = \frac{41}{56}\)
Option C: \(\frac{3}{10} + \frac{2}{8} = \frac{3}{10} + \frac{1}{4} = \frac{11}{20}\)
Option CArun Kumar