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Bunuel
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I did complete the cube in numerator and simplify the expression a little..
But I am struggling to find an easier method other than brute force..
Can someone help??

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Nielgmat

I think the ratio 63:62 states that the value of a is greater than the value of b, considering the equations are same except for the terms a and b. So, it helps to eliminate the answer choices in which denominator > numerator. So, eliminate (B), (C) and (E).
Therefore, out of the answer choices (A) and (D), (D) has a difference of 1 between the numerator and denominator just like 63 and 62. Hence, the answer is (D).

Used this approach considering the time limitation, there could be other better ways.
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Is my method correct?
a[ a^2+ 3b^2]/ b[ b^2+ 3a^2]= 63/62 which can be written as 3(21)/2(21)
21 gets cancelled and ratio remains 3/2­

My method is wrong sorry I made a mistake 
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Let a/b=k:
applying componendo-dividendo:

\((k^3+3k)/(1+3k^2)=63/62\\
\\
(k+1)^3/(k-1)^3=125/1\\
\\
\\
k+1/k-1=5\\
\\
k/1=6/4­\)­
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