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From the absolute value concept, p ranges from -7<p<7, therefore consider -7 and 7 as the boundary values. Put in the boundary values of p in x=4p+10 and the boundary values of x will come out as -18 and 38.
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To solve this, we just need to open the modulus for P:
\(|p| < 7\), which means \(-7 < p < 7\)

Now, the limiting values of the original expression will be:
  • \(4p + 10 = 4*(-7) + 10 = \)\(-18\)
  • \(4p + 10 = 4*(7) + 10 = \)\(38\)

And as P is strictly less, not equal to |7|, then X will never actually equal to those values, it will always remain in between:
\(-18 < x < 38\)

Therefore, the answer is E.
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Given \(|p| < 7\)
i.e \(-7<p<7\)
\(-7*4<4p<7*4\) ( Multiplying by 4 )
\(-28<4p<28\)

\(-28+10<4p+10<28+10\) (Adding 10 )

\(-18<4p+10<38\)

Given \(x = 4p + 10 \)

=>\( -18<x<38\)

Answer - E. -18 < x < 38
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