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Assume ven diagram of Smoker and drinkers
a is only smoker
c as both smoker plus drinker
b only drinker
d neither of both

we got 40% of 250 i.e. 75 as both
so C = 75

now 40%(a+c) = a
so 2c = 3a
a = 50

now given (b+c) 0.25 = b
c = 3b
b = 25

and
a+b+c+d = 250
therefore d = 100

We need
d/(b+d) * 100
that is 80%

Hence E answer
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Total = 250
S&D = 30% of 250 = 75

40% of smokers do not drink hence 60% of smokers drink
=> 60% of S = 75
=> S = 75*100/60 = 125

25% of drinkers do not smoke hence 75% of drinkers smoke
=> 75% of D = 75
=> D = 100

Total = Smokers + Drinkers - Both + Neither
=> 250 = 125 + 100 - 75 + N
=> 25 + 75 = N
=> N = 100

Non-smokers = Total - Smokers = 250 - 125 = 125
We need the percentage of Neither/Non-smokers = 100*100/125 = 80%

Option E

Bunuel
In a group of 250 people, 30% are both smokers and drinkers. If 40% of the smokers do not drink, and 25% of the drinkers do not smoke, what percentage of non-smokers do not drink?

A. 20%
B. 40%
C. 50%
D. 60%
E. 80%

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Bunuel
In a group of 250 people, 30% are both smokers and drinkers. If 40% of the smokers do not drink, and 25% of the drinkers do not smoke, what percentage of non-smokers do not drink?

A. 20%
B. 40%
C. 50%
D. 60%
E. 80%

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SS'T
D7525100
D'50100150
T75/0.6 = 125125250

(100/125)*100 = 80%
Correct Answer: E
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s: number of smokers
d: number of drinkers

both smokers and drinkers: 30% of 250

both = 0.3*250=75

40% of smokers do not drink means 60% of smokers do drink
0.6s=75 -> s=125

25% of drinkers do not smoke means 75% of drinkers do smoke
0.75d=75 -> d=100

only smokers = s-both = 125-75=50
only drinkers = d-both = 100-75=25

non-smokers = 250 - s = 250-125 = 125

250 = 125 + 100 - both + neither = 225 - 75 + neither = 150 + neither
neither = 100

neither/non-smokers = 100/125 = 0.8 -> 80%

IMO E
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Total = 250
S and D both = 0.3*250 = 75.
0.4S do not drink hence 0.6S = 75 -> 0.4S = 0.4*(75/0.6) = 50 who are S only
similarly 0.25D do not smoke hence 0.75S = 75 -> 0.25D = 0.25*(75/0.75) = 25 who are D only
so none = 250 - (50+75+25) = 100
% of non-smokers = 250-125 = 125 and who do not drink of 125 = 100 hence 100/125*100 = 80%
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250 people
S = smokers
D = drinkers

30% of 250 = 75 are S and D

40% of S do not drink -> 60% of S are S and D
60% of S = 75 -> S = 125
125 - 75 = 50 are S and do not drink

25% of D do not smoke -> 75% of D are S and D
75% of D = 75 -> D = 100
100 - 75 = 25 are D and do not smoke

250 - 75 - 50 -25 = 100 do not drink and do not smoke
25 + 100 = 125 do not smoke

100/125 = 0.8 = 80%

Answer E
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s = smokers
ns = non-smokers
d = drinkers
nd = non-drinkers

s and d = 0.3*250 = 75

40% of s are nd means 60% of s and d.
0.6s = 75, so s = 125
s and nd = 125 - 75 = 50

25% of d are ns means 75% of d and s.
0.75d = 75, so d = 100
d and ns = 100 - 75 = 25

ns = 250 - s = 250 - 125 = 125
ns and nd = 125 - 25 = 100

percentage = 100/125 = 80%

The answer is E
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Let total people = 250

Both smoke & drink 30% of 250 = 75

Lets say total smokers = S
Total drinkers = D
Given: 40% of smokers do not drink
=> 60% smoke & drink
0.6S = 75
=>S = 125

25% of drinkers do not smoke
=> 75% drink & smoke 0.75D = 75
=> D = 100

Finding non-smokers who do not drink =>
Non-smokers = 250−125=125
Drinkers who don’t smoke = 25% of 100 = 25
So, Non-smokers who don’t drink = 125 − 25 = 100
Non-smokers who don’t drink=125−25=100

Percentage 100/125 = 0.8 = 80%

Answer should be E.
Bunuel
In a group of 250 people, 30% are both smokers and drinkers. If 40% of the smokers do not drink, and 25% of the drinkers do not smoke, what percentage of non-smokers do not drink?

A. 20%
B. 40%
C. 50%
D. 60%
E. 80%

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Both = 30% of 250 = 75

40% of smokers do not drink, which means 60% of smokers do both

60% of S = 75
S = 125

Similarly, 75% of D = 75
D = 100

Based on above, people who not do both = 250 - (125+100-75) =250 - 150 = 100


Non S = 125
%Non S who do not D = 100/125 =80%
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smokers that drink or drinkers that smoke are 30% of 250 = 75

40% of the smokers do not drink, 100%-40% = 60% of smokers drink = 75
smokers = 75/60 * 100 = 125

smokers = 125, smokers that drink = 75, smokers that do not drink = 50

25% of the drinkers do not smoke, 100%-25% = 75% of drinkers smoke = 75
drinkers = 75/75 * 100 = 100

drinkers = 100, drinkers that smoke = 75, drinkers that do not smoke = 25

non-smokers = total - smokers = 250 - 125 = 125
non-snokers and non-drinkers = non-smokers - drinkers that do not smoke = 125 - 25 = 100

percentage of non-smokers that do not drink = 100/125 * 100 = 80%

The correct answer is E
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Bunuel
In a group of 250 people, 30% are both smokers and drinkers. If 40% of the smokers do not drink, and 25% of the drinkers do not smoke, what percentage of non-smokers do not drink?

A. 20%
B. 40%
C. 50%
D. 60%
E. 80%

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smokers=s
deinkers-=d
non smokers= ns
non drinkers= nd
both s& d=0.3x250=75
40% of smokers donot drink
60 percent of smokers drink
0.6 s = 75
s= 125
40% of smokers donot drink= 0.4 x125= 50
25% of drinkers do not smoke
75% of drinkers do smoke
0.75 xd = 75
d=100
drinkers who donot smoke= 0.25 x100= 25
non- smokers=250-125=125
non- drinkers=250-100=150
people who drink but dont smoke=25
non smokers who donot drink= 125-25=100
percentage= (100/250) x100=80%
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Total = 250
Both Smoker (s) and Drinker (d) = 30%*250 = 75

Since 40% of smokers do not drink, it means 60% of smokers drink
0.6s = 75, s=125

Also,25% of drinkers do not smoke, so 75% of drinkers smoke:
0.75d = 75, d= 100

Use table:
d Nd Total
s 75 50 125
ns 25 ?(100) ?(125)
T: 100 ? 250

Nd and ns = 100/250 = 0.4 = 40%

Option B
Bunuel
In a group of 250 people, 30% are both smokers and drinkers. If 40% of the smokers do not drink, and 25% of the drinkers do not smoke, what percentage of non-smokers do not drink?

A. 20%
B. 40%
C. 50%
D. 60%
E. 80%

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Smokers & Drinkers (S&D) = 30%

We are given that 40% smokers do not Drink, which means 60% smokers do Drink
Hence, 6/10 x S = 3/10 (given overlap)
Smokers = 1/2 = 50%

We are also given that 25% of drinkers do not smoke, which means 75% of drinkers do smoke
75/100 x D = 3/10 (overlap)
Drinkers = 40%

Therefore, Non-smokers who drink = 40%-30% = 10%
And, Non-smokers who do not drink = 50%-10% = 40%

So, % of non-smokers who do not drink = 40/50 = 80%
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30% = 75 in this case
40% of smokers dont drink therefore 60% of SMOKERS DO DRINK

this 60% of x = 75

on solving x = 125

Remaining all are non smokers = 250-125 = 125

We have to find how many ppl of this category of 125 do no drink as well

We see that 25% of drinkers dont smoke

Similar to previous steps 75% of DRINKERS DO SMOKE = 75 (30% doing both)

Therefore 75% of y = 75
y=100

Now we have 100+125-75 = 150 as the total number drinkers,smokers or both
Therefore remaining 100 do NOT smoke or drink

We have 100 not doing anything at all and 125 total non smokers
So we have 125-100 = 25 who are drinking and not smoking

non smokers who do not drink is therefore 125-25/125*100 = 80%

There could be a few steps that are redundant but this approach is very intuitive and very little ways to go wrong although a longer route. Your answer will be accurate.

Hope this helps!
Bunuel
In a group of 250 people, 30% are both smokers and drinkers. If 40% of the smokers do not drink, and 25% of the drinkers do not smoke, what percentage of non-smokers do not drink?

A. 20%
B. 40%
C. 50%
D. 60%
E. 80%

M46-25

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