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GMAT Club World Cup 2026 (Day 1): Along a straight coastal road, four

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ShreyaMittal1609

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06 Jul 2026, 11:51

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Assume distance from H to S as 60. Now we know H to R : R to S is in the ratio of 3:1. (Total length 60 into 3:1) Hence H to R=45 and R to S=15.
Now we further know H to M : M to R is in the ratio of 1:4. (H to R= 45 into 1:4) Hence H to M=9 and M to R=36.
Final- (M to S)/ (H to S)= (36+15)/60= 17/20.

Bunuel

Along a straight coastal road, four stops, Harbor, Maple, Ridge, and Summit, appear in that order. Ridge is 3 times as far from Harbor as it is from Summit. Maple is 4 times as far from Ridge as it is from Harbor. What fraction of the distance from Harbor to Summit is the distance from Maple to Summit?

A. 3/20
B. 1/4
C. 2/5
D. 17/20
E. 20/17

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Bunuel

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Taking the following variables
distance between Harbor and Maple = a
distance between Maple and Ridge = b
distance between Ridge and Summit = c

the conditions given are (i) a + b = 3c and (ii) b = 4a
substituting the values we get c = 5a/3 and

we have to find out the fraction of (b+c) over (a+b+c)

b + c = 4a + 5a/3 = 17a/3
a + b + c = 20a/3

Hence fraction = 17/20

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H M R S
|<--- 3x--->|
|<- x->|
|<4y>|
|< y>|

Question: HS/MS = ?
/////////////////
Sol):
3x=4y+y
=5y
=> x=5y/3

HS/MS = (3x+x) / (4y+x)
=4x / (4y+x)
=[4 * (5y/3)] / [4y+ 5y/3]
=[20y/3] / [12y/3 + 5y/3]
=[20y/3] / [17y/3]
=20/17

∴ Ans is E.

Bunuel

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The answer is 2/5. As, given if R to S is x, then H to R is 3x. Also given is if M to R is y, then H to M is 4y. Using these, we can equate that 4y + y = 3x, thus, y =3x/5. Now, to calculate M to S, we can simply add y + x= 3x/5+5 = 8x/5.

Now to calculate the fraction of the total, 8x/5 is divided by 4x which results in 2/5.

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The distance from H to R is 5y and that is equal to 3x. Therefore, 5y=3x. M to S / H to S = (4y+x)/4x = (17/20)x. Therefore answer is D.

Bunuel

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Given distance from H to R, HR = 3x and distance from R to S, RS = x
distance from M to R = 4y and distance from H to M, HM = y

Now, we have to find the fraction of distance MS/HS:
As we know, HR = HM + MR => 3x = y + 4y => y = 3x/5

Now, HS = HR + RS = 4x and MS = MR + RS = 4y + x
MS = 17x/5
Therefore, MS = 17/20 HS

D is the correct option

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Bunuel

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The stops appear as follows

H <---- y ----> M <---- 4y ---->R<----x-----> S
<------------------3x------------->

Therefore 3x = 4y

y = 3/5x

Question: 4y + x/ 4x = ( 4(3/5x) + x )/ 4x = 17x/20x = 17/20

Option D

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Harbour to summit is y+4y+5/3y.
Maple to summit is 4y+5/3y

Bunuel

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Lets assume there is a linear path from H to S (Taking initials of the stops)

H-------->M---------->R----------->S

Let, H to R be x
R to S be y
M to R be z
and
H to M be k

Now, x=3y

& z=x-k
also, z=4k
hence, 4k=x-k ------.> x=5k
and y= 5/3k

Now, we have values of x, y and z in the form of k.
And we have to find as per the questions

z+y/x+y

= 4k+5/3k / 5k +5/3k

=17k/20k
= 17/20

Hence, answer is 17/20.

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Try to visualise through a line and mark the points:
---H---M---------R---S----
For calculation sake, I didnt use algebra and just used whole numbers.
So let dist b/w H and M = 1
and b/w M and R = 4
So, b/w H and R = 5 (4+1)
and since it is given that R is 3 times from H as to S
So, dist b/w R and S = 5/3
And, b/w MS = 4+ 5/3 =17/3
b/w HS= 5 +5/3 = 20/3

Now,
(M/S) / (H/S) = 17/3 / 20/3 = 17/20

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H ____(d)_____M _______________(4d)______________R_____________S
Also HR = 3x and RS=x
We get HR = 5d = 3x i.e. x = 5d/3
Now HS = 5d +x = 20d/3
and MS = 4d +x = 17d/3
MS = (17/20) HS

D

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HR -> 3x, RS-> x
HM -> y, MR -> 4y
5y= 3x
MS= MR +RS = 4y+x
= 4(3/5x)+ x
=12x/5+x=17x/5

MS/HS = 17x/5/4x= 17/20

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Lets Number Line!

H---M---R---S

Given 1st parameter
HR=3x, RS=x

2nd parameter
HM=d,MR=4d

But wait, HR=3x=5d, therefore 5d/3=x=RS

Hence total will be HM+MR+RS=d+4d+5d/3=20d/3
MS=4d+5d/3=17d/3

Hence, MS/HS=17/20
IMO D

Bunuel

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By given statement : let y be distance between H and M and x be between R and S => H---y---M----4y---R--x--S
similarly, H----3x---R--x--S
so 5y=3x, now calculate 4x(H to S)/4y+x(M to S) => put y=3x/5 and we will get 20/17
so E

Bunuel

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answer : e / simple drawing question. H->M : 3 / M->R : 12 / R->S : 5

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(17x/5) / (4x) = 17/20

Bunuel

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The question says,
|------H---M------------R-----S----|,
--------|-y-|-----4y-----|
--------|---------3x-----|-----x-----|

Means,
H->R=3x, R->S=x
& H->M=y, M->R=4y
.: H->R= H->M +M->R

.: y+4y=3x, 5y=3x

Coming to the distances the question actually asks about,

Distance from H->S= H->R+R->S=3x+x=4x, lets denote this distance as 'a'.
.:a=4x
Distance from M->S=M->R+R->S= 4y+x=12x/5 +x (since, 5y=3x) =17x/5, lets denote this as 'b'.
.:b=17x/5

Now, the question asked what fraction (lets denote this as n) of a is b? .: b=na and we have to find n.
b/a= (17x/5)/4x = 17/20
b=(17/20)a
.: n=17/20
So, the answer is D

Bunuel

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06 Jul 2026, 21:04

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Harbor, Maple, Ridge, Summit

Ridge-Summit = x
Harbor-Ridge = 3x
Maple-Ridge = 4y
Harbor-Maple = y

Harbor-Ridge = 3x = 4y+y = 5y -> y = 3x/5

Maple-Summit = 4y+x = 4*3x/5 + x = 17x/5
Harbor-Summit = 3x+x = 4x

Maple-Summit/Harbor-Summit = (17x/5) / 4x = 17/20

IMO D

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This is my answer
(1st equation) H ____ (x) ___ M ________ (4x) _______ R ________S
(2nd equation) H________________(3x) _____________R ___(x)___S

From the answer choice, I use 20 as the total distance from H to S.
Then from the second equation, 4x = 20, x = 5, therefore, RS = 5 (remain same for 1st equation)
x = 5; 3x = 15, therefore, HR = 15
For the 1st equation, RS = 5, remaining is 15
x + 4x = 15
5x = 15; x = 3, therefore, HM = 3
MR = 15 - 3 = 12
Fraction will be = MS/HS = MR+RS/HS = 12+5/20 = 17/20 (D)

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distance R-S = a
distance H-R = 3a
distance H-M = b
distance M-R = 3a

distance H-R = 3a = 5b
a=5b/3

distance M-S / distance H-S = (a+4b)/4a = (17b/3)/(20b/3) = 17/20

Answer D