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GMAT Club World Cup 2026 (Day 1): Along a straight coastal road, four

1 2 3 4 5 6 7 8

noerd23

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07 Jul 2026, 03:25

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Let total distance be 20 from Harbor to Summit.
Ridge is 3 times as far from Harbor as from Summit. Ratio would be 3:1. That gives Harbor to ridge=15, Ridge to Summit=5

Maple is 4 times as far from Ridge as far from Habrbor. Giving ratio 1:4. That gives Harbor to Maple=3 and Maple to Ridge=12. SO Maple sits at 3 and Summit at 20. MAple to Summit= 20-3=17. Since total is 20 the answer to the question is 17/20. Option D

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07 Jul 2026, 04:02

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Ans: D (17/20)

Bunuel

Along a straight coastal road, four stops, Harbor, Maple, Ridge, and Summit, appear in that order. Ridge is 3 times as far from Harbor as it is from Summit. Maple is 4 times as far from Ridge as it is from Harbor. What fraction of the distance from Harbor to Summit is the distance from Maple to Summit?

A. 3/20 B. 1/4 C. 2/5 D. 17/20 E. 20/17

Given:
<----y---><----4y-->
H ------- M --------- R ---------- S
<--------3x----------><----x---->

From this, we can write: 5y = 3x or y = 3x/5

We need to find: (M to S)/(H to S)
= 4y+x / 4x
after putting y = 3x/5 we get
=> 17x/20x = 17/20

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07 Jul 2026, 04:55

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H to R = 3R
M to S= R
3R = 5 M
M 3/5 R

HS = 4/5 X 3 R + R
17/5 R
MS = 4 R

17/20

HS : MS

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07 Jul 2026, 05:18

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If we draw the line with H-M-R-S on it (attached), we see that $RS = x$, and $HR = 3x. $
At the same time, $HM = y$ and $MR = 4y.$ This makes it possible for us to scale the distances via X, and then HM is one fifth of HR (or of 3x), while MR is four fifths of the same.

Now we have an updated drawing (attached), and the question reads: $\frac{MS}{HS }= ?$, where $MS = \frac{12}{5}x + x = \frac{17}{5}x$, and $HS = 4x.$
Therefore, $\frac{17}{5}x : 4x= 17/20$, and the answer is D.

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Orig layout.png [ 11.75 KiB | Viewed 193 times ]

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07 Jul 2026, 05:52

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First lets set up a number line with all four stops in order and set Harbor at 0 since it is the first stop.

Ridge is 3 times as farm from Harbor as it is from Summit, so

HR = 3* RS

If we look at the number line, we can see that Harbor to Summit is equal to the distance from Harbor to Ridge plus the distance from Ridge to summit, so:

HS = HR +RS. We can sub HR for 3*RS to get HS = 4*RS

Next, Since Maple is 4 times as far from Ridge as it is from Harbor:

MR = 4*MH

Again if we look at the number line, Maple is between Harbor and Ridge, so the distance from Maple to Ridge is equal to the distance between Harbor and Ridge minus the distance from Harbor to Maple:

MR = HR - MH = 3*RS - MH

When can then sub this information into our MR = 4*MH equation to get

3*RS - MH = 4*MH, so

3*RS = 5*MH or (3/5)*RS = MH

Finally we solve for the distance from Maple to Summit in terms of RS

Look at the number line one more time and we can see Maple is in between Harbor and Summit, so to get Maple to summit, we can subtract MH from HS so:

MS = HS - HM = 4*RS - (3/5)*RS = (17/5)*RS

The distance from Habor to Summit is 4*RS, so we divide MS/HS or ((17/5)*RS)/4*RS which gives you 17/20.

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07 Jul 2026, 05:53

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The answer is D as per my understanding

Bunuel

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07 Jul 2026, 06:11

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Completely off on this one, didn't have a method, got lost trying to transcribe the distance in terms of a(R to s) and b (H to M)

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07 Jul 2026, 06:36

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IMO : option E
ATQ: H---M---R---S in this order
Now using the information from the question lets put them in comparision equations :

1. H to R = 3x when R to S = x
2. M to R = 4b when H to M = b
Therefore, using both the equation we can see that H to R = 3x =5b
therefore, b = 3x/5----> equation 3
Now to find the desired ratio of HS/ MS , lets get the distance in terms of x ==> As we already have HS = 4x
MS = 4b +x --> substitute the value of b from equation 3 in this
i.e. MS = 4(3x/5) +x
on solving this we get , (12x+5x)/ 5 =17x/5

now the ratio HS/MS = 4x *5 /17x = 20/17

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07 Jul 2026, 06:38

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We know that there are 4 stops which in a straight line and in the order given
Harbor(H) -> Maple(M) -> Ridge(R) -> Summit(S)
H -> M -> R -> S

We also know that, Ridge is 3 times as far as from Harbor as it is from Summit -- (1)
and Maple is 4 times as far from Ridge as it is from Harbor --- (2)

Let the starting position of Harbor be 0 and the distance between Summit and Ridge be x
=> RS = x
=> HR = 3x. (From (1))

=> Total distance = x + 3x = 4x

Let the distance between Harbor and Maple be y (HM)
=> Distance between Maple and Ridge = 4y (From 2)

=> Distance of HR = y+4y = 5y
Also, 3x = 5y => y = 3x/5

Distance HS = 4x
Distance MR = 4y = 4*3x/5 = 12x/5
Distance RS = x
=> Distance MS = 12x/5 + x = 17x/5

We need,
MS/HS = (17x/5)/4x = 17/20

D.17/20

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07 Jul 2026, 06:50

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Let distance b/w Harbor & Maple be y. Then distance b/w Maple & Ridge be 4y.
Also, let distance b/w Ridge & Summit be x. Then, distance b/w Harbor & Ridge be 3x.

H---y----M----4y---R---x---S
---------3x----------

From question we get 5y = 3x. Hence, y = 3x/5
Now, H-S/M-S = 4x/(4y+x) => 20/17.

Bunuel

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07 Jul 2026, 06:59

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HMRS
H-R=3x
R-S=x
H-M=y
M-R=4y

Reqd = 4y+x /4x = 17/20

Ans D

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Updated on: 07 Jul 2026, 10:13

Originally posted by Tammy01 on 07 Jul 2026, 07:15.
Last edited by Tammy01 on 07 Jul 2026, 10:13, edited 1 time in total.

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h m r s

h->m = y
m->r = 4y

h->r = 3x
r->s = x

For h->r,
h->m + m->r = 5y
h->r = 3x

=> 3x = 5y
=> y = 3x/5

Now,
m->s / h->s

=> (m->r + r->s) / (h->r + r->s )
=> (4y + x) / (3x+x)
=> (12x/5 +x) / 4x
=> (17x/5) / 4x
=> 17/20

Bunuel

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07 Jul 2026, 07:16

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Assume Ridge to Summit to be X distance. Therefore Harbour to Ridge = 3X. Similarly, if Harbour to Maple is Y distance, then, Maple to Ridge = 4Y.

Harbor to Ridge = 3X = 4Y + Y = 5Y, Solve for Y = 3X/5

We know that Harbor, Maple, Ridge and Summit are lined up in that order, so the total distance from Harbor to Summit = 3X + X = 4X.

To calculate the fraction of the total distance that is Maple to Summit (4Y + X), we assume another variable to represent the fraction, say F.

Therefore, F * Total distance from Harbor to Summit = 4Y + X
i.e. F * 4X = 4Y + X
substitute Y = 3X/5
which gives us: F * 4X = 12X/5 + X
Solving for F gives us 17/20

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07 Jul 2026, 07:37

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I was not able to attach my photo to give more clarity but I have drawn a line to get all the ratio like 3x & x and then 4y & y to get some reference and then 3x =5y and 4y = 12x/5 and then lastly 4x*5/17x so ans is 20/17 option E thanks.

Bunuel

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07 Jul 2026, 07:40

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Order: Harbor- Maple- Ridge- Summit
harbor to maple distance is 3
Maple to ridge - 4*3 = 12 ("Maple is 4 times as far from ridge as from Harbour")
so harbor to ridge is 3+12 = 15

Ridge to summit distance is = 15/3 = 5

Now total
Harbor to summit = 15+5 = 20
Maple to summit = 12+5 =17

so : 17/20

Bunuel

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07 Jul 2026, 07:42

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Let the path be HMRS in a straight line.

As per the question: HR = 3RS and MR = 4HM

Lets assume RS = x and HM = y
Therefore: HR = 3x and MR = 4y

=> HR = 3x = 5y
=> y = 3x/5

Now the question as asked, what is MS/HS

Now; MS/HS = (MR + RS)/(HM+MR+RS) = (4y + x)/(y+4y+x)
Substituting y = 3x/5 we get MS/HS = 17/20

Bunuel

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07 Jul 2026, 07:57

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H_____M_____R_____S

Let
Distance from H-M = x, M-R = y, R-S = z

To find = Distance from M to S / Distance from H to S = (y+z) / (x+y+z) -------------------(1)

Ridge is 3 times as far from Harbor as it is from Summit: Distance from R to H = 3(Distance from R to S): x+y = 3z -----(2)
Maple is 4 times as far from Ridge as it is from Harbor: Distance from M to R = 4(Distance from M to H): y = 4x ----------(3)

I felt it intuitive to convert the whole eq1 in terms of z
So, x+y = 3z -> x + 4x (from eq 2) = 3z -> 5x = 3z -> x = 3z/5

y = 4x -> y = 4(3z/5) = 12z/5 -----------------(4)

Finally, replacing everything in eq 1
(y+z) / (x+y+z) = (12z/5)+z / (3z)+z = (17z/5) / (4z/1) = 17z/(5z*4) = 17/20 (Final ans)

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07 Jul 2026, 08:01

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Bunuel

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the visualisation of this questions comes like this-

<------ 3x -------><-- x ---> ......(From 1st condition)
H------>M------->R-------->S
<-- y --><--4y--> ....................(From 2nd condition)

therefore we get 5y = 3x or x= 5y/3

The question is Maple to Summit / Harbour to Summit i.e. (4y+x)/4x or (4y + 5y/3)/4*5y/3 which comes to 17/20 which is option D

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07 Jul 2026, 08:14

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I am confused by the terminology “what fraction is the distance” and hence got the answer exact reverse

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07 Jul 2026, 09:25

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but aren't we looking for HS/MS? wouldn't it be 20/17 instead? Please help me figure out how to translate the final question statement better

Bunuel

GMAT Club Official Solution:

Along a straight coastal road, four stops, Harbor, Maple, Ridge, and Summit, appear in that order. Ridge is 3 times as far from Harbor as it is from Summit. Maple is 4 times as far from Ridge as it is from Harbor. What fraction of the distance from Harbor to Summit is the distance from Maple to Summit?

A. 3/20
B. 1/4
C. 2/5
D. 17/20
E. 20/17

The stops are in this order:

H --- M ------------ R ----- S

H = Harbor, M = Maple, R = Ridge, S = Summit

Since Ridge is 3 times as far from Harbor as it is from Summit:

HR : RS = 3 : 1

So HR = 3/4 of HS.

Since Maple is 4 times as far from Ridge as it is from Harbor:

MR : HM = 4 : 1

So HM = 1/5 of HR.

Choose HS = 20, since 20 is the least common multiple of 4 and 5.

Then:

HR = 3/4 * 20 = 15

RS = 5

And:

HM = 1/5 * 15 = 3

MR = 12

So the diagram is:

H -(3)-- M ------(12)------ R --(5)--- S

The distance from Maple to Summit is:

MS = MR + RS = 12 + 5 = 17

The full distance from Harbor to Summit is:

HS = 20

Therefore, the required fraction is:

17/20

Answer: D.