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GMAT Club World Cup 2026 (Day 4): A company is assigning 6 interns

1 2 3 4 5

alamin8

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09 Jul 2026, 09:35

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Bram is older than Daria, meaning Bram is in Group 1.
Daria is the orlder between the 3 siblings, therefore, she can go in Group 1 or Group 2, not in group 3

Elise is not a sibling means he can go either of the group.
Group 1: Bram, Daria/Elise
Group 2: Daria/Elise, One of Daria's Siblings
Group 3: Daria's Siblings, Elise

So Elise can go any of the group.
If Elise goes to Group 1, Daria has to go to Group 2, but not group 3.

Stiwari4001

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09 Jul 2026, 09:43

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Let's analyse the question thoroughly:
We have 6 interns:
Anya (let age=A)
Bram (let age= B)
Clara (let age= C)
Daria (let age= D)
Elise (let age= E)
Felix (let age= F)

Divided in three groups by age.

Group 1 (G1)- The oldest two
Group 3 (G3)- The youngest two
Group 2 (G2)- Remaining two
Three interns are sibling.

Info given to us:
B>D -----(1)
D is older than the siblings -----(2)
Elise is not one of the siblings -----(3)

Since B is older than D, and D is older than three siblings, B can not be one of the siblings.
Similarly, since E is NOT one of the siblings, the only three possible siblings are: (A, C, F)

Combining (1) & (2), we get:
B > D > ___ > ___ > ___
(Note: For this step we have only accounted for 5 by design)

Now since E is not one of the siblings, the possible places E can be:
E > B > D > ___ > ___ > ___
B > E > D > ___ > ___ > ___
B > D > E > ___ > ___ > ___
B > D > ___ > ___ > ___ > E

All blank space can belong to either of the siblings (A/C/F)

Let's now see possible interns in each group.

G1: E/B/D
G2: D/E/A/C/F
G3: A/C/F/E

Now, let's see what the question wants.
1. Intern that can be part of G2, but definitely not a part of G3.
From our above chart we can see that 'D' is the only one from G2 that can not be in G3.
Therefore, Daria.

2. Intern that can be in ANY group.
The only common intern across all three Groups is 'E'.
Therefore, Elise.

Answer:
Daria | Elise

basicboehly

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09 Jul 2026, 09:44

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Let A, B, C, D, E, F be the intern's ages

B > D > (3 siblings)
E could be of any age

Since B is definitely greater than at least 4 interns, they will be in G1.

D is greater than at least 3 interns so they can't be in G3 so have to be in either G1 or G2 (first selection is D)

E could be the youngest, oldest or in between (second selection is E)

Bunuel

A company is assigning 6 interns, Anya, Bram, Clara, Daria, Elise, and Felix, to 3 orientation groups based on age. The 2 oldest interns will be assigned to Group 1, the 2 youngest interns will be assigned to Group 3, and the remaining 2 interns will be assigned to Group 2. No two interns are the same age. Exactly 3 of the interns are siblings.

The following information is known:

• Bram is older than Daria.
• Daria is older than each of the 3 siblings.
• Elise is not one of the siblings.

Select for Group 2 but not Group 3 an intern who could be in Group 2 but could not be in Group 3, and select for Any Group an intern who could be in any one of the 3 groups. Make only two selections, one in each column.

princesskitt

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09 Jul 2026, 09:57

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3 groups with the constraints:
Group 1 : oldest 2
Group 2 : middle 2
Group 3 : Youngest 2

According to the rules mentioned, Daria is older than each of the 3 siblings and Bram is older than Daria. This implies that Bram is older than the 3 siblings too. It's also stated that Elise is not one of the 3 siblings. Therefore, Anya, Clara and Felix are the three siblings.

Therefore, we can write the order of their ages as:
Bram > Daria > Anya, Clara and Felix

Now, as for Elise's position in this, it has neither been specified directly nor implied. So, Elise can be placed in any position in this order and hence can be part of any of the three groups.

Now, depending on whether Elise is the one of the two oldest in the whole set, Daria could be in Group 2 but definitely not in group 3 since she's older than at least the three siblings. If Elise is the oldest or second oldest in the set, Daria will be in group 2; and if Elise is younger than Daria then Daria will be in Group 1 but never in Group 3.

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09 Jul 2026, 09:59

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Lets first note down the points that we will be using:
6 interns +3 grps
2 oldest -->G1
2 youngest -->G3
remaining 2 -->G2
there are 3 siblings
d is ildeer than all 3 ---> d is not a sibling also e is not a sibling ---> and since b>d, b is also not sibling
hence a,c,f are siblings
now order
the only confirm order we have is : B>D>(A/C/F)
now this means E can be any where and D can never be in youngest category.

nuwaaanda

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09 Jul 2026, 10:00

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Let's call the siblings A, B, C, D, E and F.

We are given that, B is older than D (B>D)
We are also given that D is older than 3 siblings. Since she is older than all 3, she cannot be a part of the Sibling group. So D is not a sibling.
We also are given that E is not the part of the sibling group.

Since B is older than D, and D is older than siblings, B is also not a sibling.
Hence, A, C and F are the 3 siblings

Thus we can deduce:
B>D>(A, C and F, we do not know the order of the siblings). We also don't know anything about E's age. E can be placed anywhere so far.

For B, we know that B is older than atleast 4 people. Hence, B will always be in Group 1.
We also know D is older than atleast 3 people. Hence D can never be a part of Group 3. However, depending upon the age of E, D can be a part of Group 1 or 2. This perfectly fits what we need in column one. Hence D is the first answer

For the second column, we know that A, C and F are atleast younger than 2 people. Hence, they can never be a part of Group 1. Hence we can eliminate them. B will always be a part of Group 1 as established above. So we cannot have B in Group 2 or 3. Hence we eliminate B. We have also established that D can never be a part of Group 3. Hence D is also eliminated.

Hence E is our choice for second column

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09 Jul 2026, 10:02

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Since we know B is older than D and that D is older than A,C,F the order will be:

B
D
A/C/F

E can be anything

We know that D can be part of Group 2 if E is oldest but never part of Group 3.
We know E can be part of any as we do not know the age.

Saurav1408

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09 Jul 2026, 10:07

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In questions like this we need to have specific constraints and given information/relation in our journal -
The interns are - A,B,C,D,E,F

Given info:
2 oldest - Group 1
2 youngest - Group 3
and the middle ones - Group 2
No two interns have same age
Exactly 3 are siblings

- B>D means B is older than D
- D is older than each of the 3 siblings : implies D is NOT among one of the siblings and B is not the sibling too, and definitely B>D>Sibling 1>Sibling 2> Sibling 3. B and D both cannot be in group 3
- Elise is not sibling, so, the siblings could ONLY be among: A, C, F

Now let us check what questions asks - An intern who could be in Group 2 but not in Group 3 - it does not specifically says that the intern could be in group 1 too.

We know there shall be 4 people after B, so B cannot take group 2
And also the 3 siblings can take both Group 2 and group 3
Elise can take any of the 3 groups since it is not in the relation of ages, BD and the 3 siblings are. And our question specifically asks NOT IN GROUP 3
So this leaves only B with us.

And for Any group - the correct choice would be E
As following 3 sequences are valid: EB DC AF, BD EC AF, BD AC FE.

Right answer: 1)DARIA and (2)ELISE

heyaa

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09 Jul 2026, 10:19

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B>D>(A,C,F); E can be anywhere as she has no siblings (she is free).
A, C and F can't be in g1 and can definitely be in g3.
B can only be in g1
D can be either in g1 or g2 but not in 3.
and E can be anywhere(as she is free).
Therefore Answers: D and E.

quosrecusandae

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09 Jul 2026, 10:24

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Consider all size of them as - Anya (A), Bram (B), Clara(C), Daria (D), Elise (E) and Felix (F)

Consider 3 groups in increasing order : _ > _ > (1) > _ > _ > (2) _ > _(3)
We need to fill the above spots given the below constrains.

Quote:

The following information is known:

• Bram is older than Daria.

1. B > D -- (equation 1)

Quote:

• Daria is older than each of the 3 siblings.

2. D > (S1, S2, S3) -- (equation 2)
from equation 1, we can consider

B > D > (S1, S2, S3)

Quote:

• Elise is not one of the siblings.

3. E is not one of the sibling

From the above 2 statements, we can safely conclude that B and D are also not part of the two siblings
Which leaves us with A, C, F to be the three siblings

Final Order:

B > D > (A,C,F), E can be placed anywhere since nothing is known about her.

In group 2 and not group 3: We can have D in group 2 (in condition that E > D), in the opposite case, D will go to group 1, but there is no case where D is in group 3, since D > (A, C, F)

So we can go with D - Daria

In any group :

There is only person who is not fixed in any group - which is Elise, this is pretty straightforward.

Quote:

Select for Group 2 but not Group 3 an intern who could be in Group 2 but could not be in Group 3, and select for Any Group an intern who could be in any one of the 3 groups. Make only two selections, one in each column.

paragw

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09 Jul 2026, 10:29

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Here's my solution for this question

Attachments

Screenshot_2026-07-09-22-58-35-66_8218ad734a8157e87572f0f6e2674adf.jpg [ 205.89 KiB | Viewed 118 times ]

okHedwig

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09 Jul 2026, 11:06

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Let Anya=A, Bram =B, Clara=C, Daria=D, Elise=E, Felix=F
As per Q, Age: B>D & D>siblings, also Elise is not sibling.
Hence Age increasing order will be : (A,C, F - any order), D, B
So for Grp2 but not 3: It should be Daria - Because if E is older than B or older than D, then D will fall in Grp1, but if E is smaller than B & D both, D will fall in Grp2. D can never fall in Group 3
For Any group - It should be Elise - Since we dont know where Elise would be, it could fit in any of the 3 categories depending on age

Bunuel

Vivek1707

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09 Jul 2026, 11:06

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D < B
Three siblings < D
E is not a sibling

So A C F are siblings

Since D is older than the three siblings ---> there is no way that D can be the part of the youngest two

Hence D can be either in 2 or in 1 but not in 3 Hence option D i.e Daria is correct for the first part

Nothing really is mentioned about E except that its not a sibling

It could be the youngest, it could be in the middle or it could be older than B so E could be in either groups

Hence option E i.e Elise for the 2nd part

Bunuel

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09 Jul 2026, 11:12

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Question info:
1. D<B
2. D is older than the three siblings
3. E is not one of the siblings
Inference: Since D is older than all siblings and B is older than D, both B & D are not one of the siblings. Question already gives that E is not one of the siblings. So the three siblings are A, C & F

With this info, there can be three orders of age that can be formed
Order 1 - E<(A|C|F)<D<B
Order 2 - (A|C|F)<E<D<B
Order 3 - (A|C|F)<D<B<E

Q1: Group 2 but not group 3: In each of the above orders, D is either the third oldest or second oldest. Hence, D can be in Group 1 (in case of order 1 & 2) and Group 2 (in case of order 3) but never in Group 3.

Q2; Person who can be in either group: In order 1, E will fall under Group 3, in order 2 E will fall in group 2 and in order 3 E will fall in Group 1. Hence E can be in any of the three groups.

ajain31

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09 Jul 2026, 11:13

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The way I approached this was write down the initials on your scratchpad and assume some ages based on the text:

A - 14 S
B - 18
C - 15 S
D - 17
E - (not a sibling)
F - 16 S
Essentially for age, B > D > C,F, A

So E could be anywhere, so any group easy.
But we dont know about daria, daria has three people below her and one person at least above her, so she could be group 1 or 2 and as the question states that "could be" we can put her in group 2 but not 3.

GulfTube

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09 Jul 2026, 11:38

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B is older than D
D is older than 3 siblings
E is not the sibling

So B is also older than 3 siblings. Siblings are A, C,F
B will always be in G1 even if E is older than it.
E could be of any age, we do not have any information besides it not being the sibling.
D cannot be in G3 since there are atleast 3 siblings, if not E, which will be in G3.
if E is younger than D, then D is in G1. If E is elder than D , then D is in G2.

Any Group: E
G2 but not G3: D

ShreyaMittal1609

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09 Jul 2026, 12:04

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Group 1- 2 oldest interns
Group 2- 2 remaining interns
Group 3- 2 youngest interns

Bram>Daria>3 siblings.
Means, Bram is older than 4 interns. Hence Bram is part of Group 1 for sure.
Daria is older than 3 interns- Hence could be part of Group 1 (if Daria is older than Elise) or Group 2 (If Elise is older than Daria) but not Group 3 as he is older than 3 interns.
Elise can be part of any group as no relation to others is given.

Ans- Could be in Group 2 but not 3- Daria
Any group- Elise

Bunuel

nikhilphulwari

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09 Jul 2026, 12:09

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given, B>D>(siblings) and E is not one of siblings

therefore, possible cases:
1. E>B>D>(s)
2. B>E>D>(s)
3. B>D>E>(s)
4. B>D>(s)>E or E can be in between siblings

so, we can say D could be in group 2 but cannot be in group 3 in any case
and E could be part of any group.

Correct Answer: Daria and Elise

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09 Jul 2026, 12:32

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Bunuel

6 interns - A, B , C , D, E, F (abbreviations for each)
Groups - G1, G2 and G3
G1 - 2 oldest interns
G2 - 2 middle aged interns
G3 - 2 youngest interns

Also B> D in age
D > Siblings in age
E not in siblings

Let the siblings be S1, S2 and S3 ( S1 being the oldes sibling then S2 and then S3)
We know E is not in the siblings. ALso D and B are older than the siblings.
Hence we can conclude that the siblings are A, C and F

We still do not know relative age of E hence we take multiple cases and note the groups

Case 1 - E is oldest/2nd oldest
Here the group arrangement would be
G1 - E and B
G2 - D and S1
G3 - D and S3

Case 2 - E younger than D but older than all siblings
G1 - B and D
G2 - E and S1
G3 - S2 and S3

Case 3 - E is older than S3 but younger than S1,S2, B,D
G1 - B and D
G2 - S1 and S2
G3 - E and S3

Across all 3 cases, we can observe that
1. E can move in all 3 groups based on age
2. B always stays in G1
3. D can move to G1, G2 but never in G3

Hence asnwers are
1. G2 but not G3 = D = Daria
2. Any group = E = Elise

sonit1987

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09 Jul 2026, 12:34

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given: 2 older in the group 1
next two older in group-2
and 2 youngest in group-3
3 siblings only total exactly

now lets call their names as first alphabet of their names A,B,C,D,E,F

AS PER 3 GIVEN STATEMENTS:--

statement-1 B>D
statement-2 D> 3 SIBLINGS
Statement 3 E IS NOT ONE OF SIBLINGS

IF B>D and D> three siblings so B also can't be sibling as D has to be greater than all three siblings but D already given less than B. and E already given than not a sibling
so out of 6, A,C, F CAN BE SIBLING

BUT E CAN FIT ANYWHERE OLDEST, 2ND OLDEST AND 3RD OLDEST AND 4TH OLDEST BECAUSE D CAN BE BIGGER THAN 3 SIBLINGS AND ONE E AS WELL. ONLY IT CAN'T BE BIGGER THAN B . SO E CAN BE IN 1ST GROUP IF CONSIDERED OLDEST OR SECOND OLDEST, 2ND GROUP IF CONSIDERED 3RD OLDEST AND SO ON. SO IT CAN OCCUPY ALL THE GROUP.

BUT D HAS TO BE GREATER THAN 3 PEOPLE AND LESS THAN 1 SO IT CAN ONLY OCCUPY 2ND OLDEST AND 3RD OLDEST MAKING HIM SUITABLE FOR 2ND GROUP BUT NOT 3RD.

HENCE OUR ANSWERS,