Last visit was: 31 Aug 2026, 14:14 It is currently 31 Aug 2026, 14:14
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Rishm
Joined: 05 May 2024
Last visit: 30 Aug 2026
Posts: 369
Own Kudos:
Given Kudos: 82
Location: India
GPA: 10
WE:Consulting (Consulting)
Products:
Posts: 369
Kudos: 77
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
Shlok02
Joined: 08 Jan 2024
Last visit: 31 Aug 2026
Posts: 65
Own Kudos:
Given Kudos: 6
Products:
Posts: 65
Kudos: 41
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
Coolguy22
Joined: 06 Jul 2024
Last visit: 31 Aug 2026
Posts: 5
Own Kudos:
7
 [1]
Given Kudos: 15
Location: India
GMAT Focus 1: 675 Q86 V84 DI80
Products:
GMAT Focus 1: 675 Q86 V84 DI80
Posts: 5
Kudos: 7
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
Sajal193
Joined: 06 Jan 2025
Last visit: 30 Aug 2026
Posts: 15
Own Kudos:
Given Kudos: 5
Products:
Posts: 15
Kudos: 2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
1,2,3,44,45,46,47,88,89,90,91. Total 11 nimbers
User avatar
AviNFC
Joined: 31 May 2023
Last visit: 09 Aug 2026
Posts: 365
Own Kudos:
421
 [1]
Given Kudos: 5
Posts: 365
Kudos: 421
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
LCM(4,11)=44
n=44k+r
r can be 0,1,2,3
k=0, r=1,2,3..n=1,2,3
k=1, r=0,1,2,3...n=44,45,46,47
k=2, r=0,1,2,3...n=88,89,90,91

total 11 nos.

Ans D
User avatar
chasing725
Joined: 22 Jun 2025
Last visit: 16 Aug 2026
Posts: 241
Own Kudos:
235
 [1]
Given Kudos: 6
Location: United States (OR)
Schools: Stanford
Schools: Stanford
Posts: 241
Kudos: 235
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
How many positive integers less than 100 have the same remainder upon division by 4 as upon division by 11?

A. 8
B. 9
C. 10
D. 11
E. 12


 


This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

 


⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.

n = 4x + r
n = 11y + r

n = 44z + r

r can be 0, 1, 2, or 3

When r = 0 ; n = 44, 88
r = 1 ; n = 1, 45, 89
r = 2 ; n = 2, 46, 90
r = 3 ; n = 3, 47 , 91

Number of integers = 9 + 2 = 11

Option D
User avatar
Maesha
Joined: 11 Jun 2026
Last visit: 31 Jul 2026
Posts: 29
Own Kudos:
25
 [1]
Given Kudos: 4
Concentration: Leadership, Economics
Schools: HBS '26 (S)
Schools: HBS '26 (S)
Posts: 29
Kudos: 25
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
lets suppose, number of total integer = x
and each time the remainder = y

so, x ( mod 4) = y
x( mod 11) =y

LCM of 4 and 11 is 4, so , x(mod44)=y
if modulo is 4 remainder must be one of 0/1/2/3

so , suppose , x==44a+y where a = 0,1,2,3,4,.............

if a = 0 , x= 0+ ( 0,1,2,3)=(0,1,2,3)
if a = 1 , x= 44 +(0,1,2,3) =( 44,45 ,46 47)
if a = 2 , x= 88+(0,1,2,3)=(88,89,90,91)
if a =3 , x=132+(0,1,2,3)= not valid because , x must be greater than 0 and less than 100

so, possible value = 1,2 ,3 ,44 ,45,46,47,88,89,90,91

total possible value is 11 .
User avatar
ShreyaMittal1609
Joined: 05 Nov 2025
Last visit: 31 Aug 2026
Posts: 82
Own Kudos:
Given Kudos: 208
GMAT Focus 1: 545 Q77 V77 DI77
Products:
GMAT Focus 1: 545 Q77 V77 DI77
Posts: 82
Kudos: 45
Kudos
Add Kudos
Bookmarks
Bookmark this Post
My ans is C) 10

remainder when n is divided by 4 can be 0,1,2,3.

when remainder for both are same-
for n<4, remainder=n. Positive Integers = 1,2,3 will give remainders=integers upon division by both 4 and 11
1)0= 44,11
2)1= 45,89
3)2= 47,79
4)3= 91

Total count= 10. There can be a more efficient way for sure.
Bunuel
How many positive integers less than 100 have the same remainder upon division by 4 as upon division by 11?

A. 8
B. 9
C. 10
D. 11
E. 12


 


This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

 


⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.
User avatar
SmileAndSolve
Joined: 25 Aug 2024
Last visit: 31 Aug 2026
Posts: 80
Own Kudos:
52
 [1]
Given Kudos: 327
Location: India
Concentration: Strategy, Entrepreneurship
GPA: 4
Products:
Posts: 80
Kudos: 52
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Answer:
Attachments

WhatsApp Image 2026-07-14 at 2.13.54 AM.jpeg
WhatsApp Image 2026-07-14 at 2.13.54 AM.jpeg [ 127.48 KiB | Viewed 105 times ]

User avatar
FlushLoop
Joined: 05 Jul 2026
Last visit: 06 Aug 2026
Posts: 62
Own Kudos:
57
 [1]
Posts: 62
Kudos: 57
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
How many positive integers less than 100 have the same remainder upon division by 4 as upon division by 11?

A. 8
B. 9
C. 10
D. 11
E. 12


 


This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

 


⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.
When we divide a number by 4 the remainder can be 0, 1, 2 or 3.

This is because the largest value for the remainder is 3, which's one less than 4.

We can write the number as n = 44k.

The remainder, where 44 is the product of 4 and 11.

To find the values of n we need to look at the valid values of the remainder for numbers that are less, than 100.

If the remainder is 0 the numbers would be 44, 88 which gives us 2 numbers.
If the remainder is 1 the numbers would be 1, 45 89 which gives us 3 numbers.
If the remainder is 2 the numbers would be 2, 46 90 which gives us 3 numbers.
If the remainder is 3 the numbers would be 3, 47, 91 which gives us 3 numbers.

Total 11 numbers

IMO Option D
User avatar
GurpreetMahli
Joined: 06 Aug 2023
Last visit: 31 Aug 2026
Posts: 33
Own Kudos:
12
 [1]
Given Kudos: 115
Location: United States
Products:
Posts: 33
Kudos: 12
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Answer: D = 11

Step 1. LCM of 4 and 11 = 44

Step 2. Possible remainders 0 - 3 as 4 is the limiting integer

Step 3. Remainder (R) = 0

((Highest multiple of 44 - lowest multiple of 44) / 44 ) + 1

((88-44)/44) + 1 >> 2

0 is not included as lowest multiple of 44 since it is neither positive or negative and our set only includes positive integer less than 100

Step 4. R = 1

(( (88+1) - (1)) / 44) +1 >> 3

Step 5. R = 2 and 3

Same pattern holds as the highest multiple doesn't exceed 100, so 3 and 3 respectively

Total: 2(R=0) + 3(R=1) + 3(R=2) + 3(R=3) = 11
Bunuel
How many positive integers less than 100 have the same remainder upon division by 4 as upon division by 11?

A. 8
B. 9
C. 10
D. 11
E. 12


 


This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

 


⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.
User avatar
priyanka06
Joined: 10 Sep 2025
Last visit: 31 Aug 2026
Posts: 60
Own Kudos:
35
 [1]
Given Kudos: 1
Products:
Posts: 60
Kudos: 35
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
4 and 11 have shared remainders=> 0,1,2,3

values for 44x + R, When remainder is 0 => 44, 88
when remainder is 1 => 1, 45, 89
when remainder is 2 => 2,46,90
when remainder is 3=> 3,47,91

total 11 positive integers less than 100.
Bunuel
How many positive integers less than 100 have the same remainder upon division by 4 as upon division by 11?

A. 8
B. 9
C. 10
D. 11
E. 12


 


This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

 


⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.
User avatar
alamin8
Joined: 24 May 2025
Last visit: 29 Aug 2026
Posts: 181
Own Kudos:
79
 [1]
Given Kudos: 32
Location: Bangladesh
Concentration: Accounting, Technology
GPA: 3.89
Posts: 181
Kudos: 79
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
When we divide anything by 4, the reminder will be 0, 1, 2, 3
Therefore, when we divide anything by 11, the reminder must be 0, 1, 2, 3

Before finding the list, lets do an LCM of 4 and 11. It will be 44. Then, there will be no reminder.
Here is the list of positive integers less than 100
Reminder 0: 44, 88 (88/4 = 11) = 2
Reminder 1: 1, 45, 89 (11*4, reminder 1, 11*8, and 4*22, reminder 2) = 3
Reminder 2: 2, 46, 90 [11*4, reminder 2, 11*8, and 4*22, reminder 2] = 3
Reminder 3: 3, 47, 91 (11*4, reminder 3, 11*8, and 4*22, reminder 3) = 3

Total reminders =2+3+3+3 = 11

Answer: D
User avatar
harshitaa45
Joined: 20 Feb 2021
Last visit: 29 Aug 2026
Posts: 49
Own Kudos:
30
 [1]
Given Kudos: 8
Products:
Posts: 49
Kudos: 30
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
By brute force pattern
Any number less than both 4 and 11 will leave the same reminder:1,2 and 3
A number which is factor of both 4 and 11 will leave the same reminder:0: Possible nums:44,88
And when we add the first set of numbers to the multiples of 4 and 11 then also the same remainders are left:
SO the possible set of numbers:1,2,3,44,45,46,47,88,89,90,91=>11 nums possible
User avatar
rockstar09rulez
Joined: 30 Sep 2023
Last visit: 26 Aug 2026
Posts: 43
Own Kudos:
25
 [1]
Given Kudos: 74
Location: United States (CA)
Concentration: Technology, Finance
Products:
Posts: 43
Kudos: 25
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
N = 4a+r
N = 11b+r
equating we get a/b = 11/4;
Assume a = 11k, b = 4k
SO we get N = 44k + r
Now r can be 0,1,2,3 since it is has to leave same remainder as that when divided by 11
If r = 0
N = 44k so N can be 44,88
If r = 1
N = 44k+1 so N can be 1, 45, 89
similarly r=2 and r=3 give. 3 values each
So total values = 2+3+3+3 = 11 -> D
User avatar
sunshineeee
Joined: 17 May 2020
Last visit: 30 Aug 2026
Posts: 174
Own Kudos:
52
 [1]
Given Kudos: 266
Location: Indonesia
Products:
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Question asked: positive integers < 100 have the SAME REMAINDER upon division 4 and 11

1. Upon Division 4 and 11 under 100 with remainder 0 -> 4x11 = 44, 88 (2)
2. with remainder 1: 1, 45, 89 (3)
3. with remainder 2: 2, 46, 90 (3)
4. with remainder 3: 3, 47, 91 (3)

1,2,3 are included since if divided by 4, will have reminder as above as well.

So, total 2+3+3+3 = 11 (Answer D).
Bunuel
How many positive integers less than 100 have the same remainder upon division by 4 as upon division by 11?

A. 8
B. 9
C. 10
D. 11
E. 12


 


This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

 


⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.
User avatar
kalkurd
Joined: 31 Oct 2025
Last visit: 25 Jul 2026
Posts: 28
Own Kudos:
26
 [1]
Given Kudos: 1
Posts: 28
Kudos: 26
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
D 11.

Need n mod 4 = n mod 11 = r. Since r must be a valid mod-4 remainder, r is 0, 1, 2, or 3. Then n minus r is divisble by both 4 and 11, so by 44. Thus n = 44k + r

List 1 to 99

k = 0, 1, 2, 3 (drop 0, it's not positive) -> three
k = 1: 44, 45, 46, 47 -> four
k = 2: 88, 89, 90, 91 -> four

total 11.

Wrong ones
E - 12: Counted k=0, as four, forgetting that it's not positive
C - 10: Dropped a boundary value either 88 or 91, both under 100
B - 9: Kept the two full blocks, but missed the small three (1, 2, 3)
A - 8: Undercounted repeats across blocks.
User avatar
SRIVISHUDDHA22
Joined: 08 Jan 2025
Last visit: 19 Aug 2026
Posts: 120
Own Kudos:
80
 [1]
Given Kudos: 371
Location: India
Schools: ISB '26
GPA: 9
Products:
Schools: ISB '26
Posts: 120
Kudos: 80
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Lets check small numbers like 1,2 and 3 (less than 4) when 1 is divided by 4 or 11 reminder is 1 , same is the case with 2 and 3 when divided by 11 or 4 leaves a reminder 2, 3
now if we check for larger number like 32 we see the reminder is 0 when divided by 11 the reminder is 10 so for 2 digit numbers less than 100 we need to find first the common multiples of 4 and 11
44, and 88 are the only common multiples .
Check
44 when divided by 4 / 11 leaves a reminder 0
44+1=45 when divided by 4/11 reminder is 1
44+2 =46 when divided by 4/11 reminder is 2
44+3 =47 when divided by 4/11 reminder is 3
44+4 =48 when divided by 4 leaves reminder 0 when divided by 11 leaves reminder 4 . STOP. So - 1,2,3 ,44,45,46 .47 when divided by 4 or 11 leaves same reminder

No check for 88

88 when divided by 4/11 leaves reminder 0
88+1=89 when divided by 4/11 leaves reminder 1
88+2=90 when divided by 4/11 leaves reminder 2
88+3 =91 when divided by 4/11 leaves reminder 3
88+4 =92 when divided by 4/11 leaves reminder 0 for 4 and reminder 4 for 11 . STOP!

So 1,2,3,44,45,46,47 ,88,89,90,91 leaves same reminder for 4 and 11
no of terms = 11
Bunuel
How many positive integers less than 100 have the same remainder upon division by 4 as upon division by 11?

A. 8
B. 9
C. 10
D. 11
E. 12


 


This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

 


⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.
User avatar
Aarushi100
Joined: 17 Jul 2024
Last visit: 28 Aug 2026
Posts: 70
Own Kudos:
Given Kudos: 98
Posts: 70
Kudos: 57
Kudos
Add Kudos
Bookmarks
Bookmark this Post
For 4 we can only have these remainders: 0,1,2,3
Let us consider the numbers when Remainder will be 0 : 44, 11
Remainder 1: 45,85
Remainder 2: 46, 86
Remainder 3: 47, 87

Apart from these 8 numbers, all other numbers have different remainders.
Eg: consider 34 => Remainder for 11 = 1
Remainder for 4 = 2.

ANSWER A
User avatar
GreenPill
Joined: 13 Jun 2026
Last visit: 31 Aug 2026
Posts: 37
Own Kudos:
25
 [1]
Products:
Posts: 37
Kudos: 25
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
How many positive integers less than 100 have the same remainder upon division by 4 as upon division by 11?

A. 8
B. 9
C. 10
D. 11
E. 12


 


This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

 


⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.
OPTION D. 4 and 11 are co prime. from trial and error we know 22 gives remainder 0 with 11 and 2 with 4. for 33 its 0 and 1. then 44, both gives 0, as for 4 only 1,2,3 are possible remainders. 44,45,46,47 are nos. similarly 88,89,90,91. therefore 4+4 + 3(initial numbers 1,2,3) = 11
   1   2   3   4   5   
Moderator:
Math Expert
113035 posts