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555-605 (Medium)|   Algebra|      
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gorden
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If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A. Updated on: 05 Oct 2013, 05:59
Originally posted by gorden on 11 Nov 2008, 17:28.
Last edited by Bunuel on 05 Oct 2013, 05:59, edited 1 time in total.
Edited the question, added the OA and moved to PS forum.
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72% (01:58) correct 28% (02:19) wrong based on 722 sessions

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If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7=

A. 1/a+ 1/8
B. 1/8 - 1/a
C. 1/8-a
D. 3/7(8 – a)
E. 9/49 (8 – a)
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E
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Bunuel
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If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A. 05 Oct 2013, 06:03
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Mansi12
Hi,

Can anyone help me with this one. I got stuck at -
x=(24-3a)/7
=> x= 3(8-a)/7

how do we get to 3x/7 ?
Show more

If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7=

A. 1/a+ 1/8
B. 1/8 - 1/a
C. 1/8-a
D. 3/7(8 – a)
E. 9/49 (8 – a)

\(\frac{7x}{3} + a = 8\) --> \(\frac{7x}{3}= 8-a\).

Now, multiply both sides by \(\frac{3}{7}*\frac{3}{7}\) in order to get \(\frac{3x}{7}\) on the LHS:

\(\frac{3}{7}*\frac{3}{7}*\frac{7x}{3}=\frac{3}{7}*\frac{3}{7}( 8-a)\).

\(\frac{3}{7}*x=\frac{9}{49}( 8-a)\).

Answer: E.

Hope it helps.
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If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A. 11 Nov 2008, 19:01
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gorden
If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7=

A. 1/a+ 1/8
B. 1/8 - 1/a
C. 1/8-a
D. 3/7(8 – a)
E. 9/49 (8 – a)
Show more

E.
assuming that the original eqn (7x/3) + a = 8

7x + 3a = 24
7x = 24 -3a

x = (24 - 3a )/7 = 3(8 -a)/7

i.e 3x/7 = 9(8-a)/49
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If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A. 05 Oct 2013, 05:29
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Hi,

Can anyone help me with this one. I got stuck at -
x=(24-3a)/7
=> x= 3(8-a)/7

how do we get to 3x/7 ?
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If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A. 30 Nov 2014, 17:15
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Exercise raises 7x/3 + a = 8 and a > 8

And express 3x/7 according to request.

One suggestion is to form 3x/7, from equal 7x/3 + a = 8

In the last ogualdad, clearing 7x/3, is:

7x/3 = 8 - a

Here we can form in the ladi left 3x/7 equality, simply multiply the ogualdad by 9/49, so must

(9/49)(7x/3) = (9/49) (8 - a)

Simplifying on the left side of the equality is:

7x/3 = (9/49) (8 - a)

It is requested.

Answer E

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If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A. 30 Nov 2014, 23:18
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gorden
If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7=

A. 1/a+ 1/8
B. 1/8 - 1/a
C. 1/8-a
D. 3/7(8 – a)
E. 9/49 (8 – a)
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What's the need to specifically say a > 8 ? Would it make any difference?
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If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A. 31 Jan 2015, 00:17
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Bunuel
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Hi,

Can anyone help me with this one. I got stuck at -
x=(24-3a)/7
=> x= 3(8-a)/7

how do we get to 3x/7 ?

If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7=

A. 1/a+ 1/8
B. 1/8 - 1/a
C. 1/8-a
D. 3/7(8 – a)
E. 9/49 (8 – a)

\(\frac{7x}{3} + a = 8\) --> \(\frac{7x}{3}= 8-a\).

Now, multiply both sides by \(\frac{3}{7}*\frac{3}{7}\) in order to get \(\frac{3x}{7}\) on the LHS:

\(\frac{3}{7}*\frac{3}{7}*\frac{7x}{3}=\frac{3}{7}*\frac{3}{7}( 8-a)\).

\(\frac{3}{7}*x=\frac{9}{49}( 8-a)\).

Answer: E.

Hope it helps.
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Hi,

Thank you.

After 7x/3 = 8 - a, why can we not take the reciprocal of both sides?

TO
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If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A. 31 Jan 2015, 05:28
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thorinoakenshield
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Mansi12
Hi,

Can anyone help me with this one. I got stuck at -
x=(24-3a)/7
=> x= 3(8-a)/7

how do we get to 3x/7 ?

If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7=

A. 1/a+ 1/8
B. 1/8 - 1/a
C. 1/8-a
D. 3/7(8 – a)
E. 9/49 (8 – a)

\(\frac{7x}{3} + a = 8\) --> \(\frac{7x}{3}= 8-a\).

Now, multiply both sides by \(\frac{3}{7}*\frac{3}{7}\) in order to get \(\frac{3x}{7}\) on the LHS:

\(\frac{3}{7}*\frac{3}{7}*\frac{7x}{3}=\frac{3}{7}*\frac{3}{7}( 8-a)\).

\(\frac{3}{7}*x=\frac{9}{49}( 8-a)\).

Answer: E.

Hope it helps.

Hi,

Thank you.

After 7x/3 = 8 - a, why can we not take the reciprocal of both sides?

TO
Show more

You mean why don't we write 3/(7x) = 1/(8-a) ? What does it give?
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If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A. 31 Jan 2015, 14:01
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Hi All,

This question can be solved by TESTing VALUES, although it does come with a "twist" that will require that you think about which type of values would make the math easy to deal with.

We're told that 7X/3 + A = 8 and that A > 8. We're asked for the value of 3X/7.

Since A > 8......7X/3 will have to be NEGATIVE.

To eliminate the fraction, I'm going to TEST...
X = -3

7(-3)/3 = -7
-7 + A = 8
A = 15

So, with X = -3 and A = 15, the answer to the question is 3(-3)/7 = -9/7

Answer A: 1/15 + 1/8 is positive. NOT a match
Answer B: 1/8 - 1/15 is positive. NOT a match
Answer C: 1/8 - 15 is TOO negative. NOT a match
Answer D: (3/7)(8-15) = (3/7)(-7) = -3 NOT a match
Answer E: (9/49)(8-15) = (9/49)(-7) = -9/7 This IS a MATCH

Final Answer:
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E

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If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A. 31 Jan 2015, 16:47
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Hi,

Thank you.

After 7x/3 = 8 - a, why can we not take the reciprocal of both sides?

TO

Bunuel: You mean why don't we write 3/(7x) = 1/(8-a) ? What does it give?

Yes. Will this be mathematically illegal? I am sorry if the question sounds very basic.

TO
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If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A. 01 Feb 2015, 04:17
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thorinoakenshield
Hi,

Thank you.

After 7x/3 = 8 - a, why can we not take the reciprocal of both sides?

TO

Bunuel: You mean why don't we write 3/(7x) = 1/(8-a) ? What does it give?

Yes. Will this be mathematically illegal? I am sorry if the question sounds very basic.

TO

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The question asks to find the value of 3x/7 in terms of a, not the value of 3/(7x). You should read questions more carefully. Also, I think you need to brush up fundamentals and only then to attempt questions. Here are the books you might find helpful: best-gmat-math-prep-books-reviews-recommendations-77291.html
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If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A. 15 Nov 2017, 11:54
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Please spend some time to write the answer choices correctly.

9/49 (8 – a) can be misread as \(\frac{9}{49(8-a)}\) and is not the same as \(\frac{9}{49} * (8-a)\).
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If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A. 10 Feb 2019, 10:26
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gorden
If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7=

A. 1/a+ 1/8
B. 1/8 - 1/a
C. 1/8-a
D. 3/7(8 – a)
E. 9/49 (8 – a)
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7x/3 + a = 8
7x + 3a = 24

a > 8, a = 9

7x = -3
x = -3/7

3x/7 = -9/49 -> target value

We can get this from only E
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If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A. 08 Jan 2023, 23:30
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If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7=

A. 1/a+ 1/8
B. 1/8 - 1/a
C. 1/8-a
D. 3/7(8 – a)
E. 9/49 (8 – a)

Stem : 7x/3 + A = 8 AND A>8
Let X = -3 So\( 7X/3 \)=\( 7*(-3)/3 \)+ A = 8 = -7 + A = 8, A = 15 satisfies condition A>9
\(3X/7\) = \(3*(-3)/7\) = \(-9/7\)
(E) \(9/49\)(8 - 15) = 9 * \(-7/49\) = \(-63/49\) = \(-9/7\)
E
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If 7x/3 + a = 8 and a > 8, then, in terms of a, 3x/7= A. 11 Dec 2025, 07:38
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