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Train X and Train Y, traveling at their respective constant rates, are

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Sajjad1994
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Train X and Train Y, traveling at their respective constant rates, are [#permalink] New post   18 Jan 2021, 03:00
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Train X and Train Y, traveling at their respective constant rates, are moving in the same direction along parallel tracks. Initially, Train X is behind Train Y by 18 kilometers, but after 4 hours, Train X is 6 kilometers ahead of Train Y.

Using the information given, identify an answer that could be the speed of Train X and an answer that could be the speed of Train Y, both in kilometers per hour (k/h). Make only two selections, one in each column.
Train X's
Speed 		Train Y's
Speed 		Value (k/h)
44
48
49
54
57
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Train X's
Speed: 54 Train Y's
Speed: 48
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Re: Train X and Train Y, traveling at their respective constant rates, are [#permalink] New post   18 Jan 2021, 06:06
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Let the speed of train X = a
Let the speed of train Y = b

Initially Train X is 18km behind, but after 4 hours it is 6km ahead.

So, in 4 hours it covered 24kms more than Train Y. Hence we can conclude that Train X's speed is 6km more than that of Train Y.

a-b = 6

Only 54 & 48 satisfy this condition.

Speed of train X = 54
Speed of train Y = 48
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Re: Train X and Train Y, traveling at their respective constant rates, are [#permalink] New post   23 Aug 2023, 04:12
in 4 hours X covers 24 km. So n 1 hr it covers 6km. Find out option that gives 6 difference between values. Only 54 for X and 48 for Y satisfies.
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Re: Train X and Train Y, traveling at their respective constant rates, are [#permalink] New post   27 Aug 2023, 08:24
X= (a+24)/4= (a/4) + 6
Y= (a/4)

So speed of X and Y have diff of 6, the only pair to satisfy this condition is 48 and 54.

Posted from my mobile device
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Re: Train X and Train Y, traveling at their respective constant rates, are [#permalink] New post   14 Mar 2024, 01:15
 
Sajjad1994 wrote:
Train X and Train Y, traveling at their respective constant rates, are moving in the same direction along parallel tracks. Initially, Train X is behind Train Y by 18 kilometers, but after 4 hours, Train X is 6 kilometers ahead of Train Y.

Using the information given, identify an answer that could be the speed of Train X and an answer that could be the speed of Train Y, both in kilometers per hour (k/h). Make only two selections, one in each column.

Key Formula ----> 

Distance = Speed * Time

­ Train X : 

Let Speed = Sx , Time = Tx , Distance = Dx ;   Dx = Sx * Tx

Train Y :

Let Speed = Sy , Time = Ty , Distance = Dy ; Dy = Sy * Ty

Now translate the lines one by one.

Initially, Train X is behind Train Y by 18 kilometers :

So, Dx = Dy - 18. ....(eqn. 1)

but after 4 hours, Train X is 6 kilometers ahead of Train Y :  

After 4 hours means : Time will be added by 4 

[Sx * (Tx + 4)] = [Sy * (Ty + 4)] + 6

[Sx * Tx] + 4Sx = [Sy * Ty] + 4Sy + 6

4Sx - 4Sy - 6 = [Sy * Ty] - [Sx * Tx] 

4Sx - 4Sy - 6 = 18 (From equation 1)

4Sx - 4Sy = 24 (Divide this complete euation by 4)

Sx - Sy = 6

From answer choices : Sx = 54 and Sy = 48
Satisfies it. 

Hope it helps.
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Re: Train X and Train Y, traveling at their respective constant rates, are [#permalink] New post   22 Mar 2024, 00:36
 
Sajjad1994 wrote:
Train X and Train Y, traveling at their respective constant rates, are moving in the same direction along parallel tracks. Initially, Train X is behind Train Y by 18 kilometers, but after 4 hours, Train X is 6 kilometers ahead of Train Y.

Using the information given, identify an answer that could be the speed of Train X and an answer that could be the speed of Train Y, both in kilometers per hour (k/h). Make only two selections, one in each column.

­Very easy question

Train X covers a distance of 24 kilometers in 4 hours which means = relative speed of x wrt y is 6 greater.

Vx-Vy=6 

Only 54 and 48 combination works. So thats the answer.

Honestly dont think a question like this could appear in the exam
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Re: Train X and Train Y, traveling at their respective constant rates, are [#permalink] New post   16 Apr 2024, 02:33
Train X moved faster than Train Y
=> X> Y

­In 4 hours, the difference between Train X and Y's travel is 18 + 6 = 24km
=> Difference in speed per hour: \(24 \div 4 = 6\)
=> X - Y = 6

=> X = 54; Y = 48
 ­
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Re: Train X and Train Y, traveling at their respective constant rates, are [#permalink]
16 Apr 2024, 02:33
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