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Updated on: 01 Nov 2012, 15:33
Originally posted by mikemcgarry on 01 Nov 2012, 15:30.
Last edited by Bunuel on 01 Nov 2012, 15:33, edited 1 time in total.
Last edited by Bunuel on 01 Nov 2012, 15:33, edited 1 time in total.
Renamed the topic.
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
85% (02:22) correct
15%
(02:28)
wrong
based on 303
sessions
History
Date
Time
Result
Not Attempted Yet
Trapezoid JKLM in the x-y plane has coordinates J = (–2, –4), K = (–2, 1), L = (6, 7), and M = (6, –4). What is its perimeter?
(A) 34
(B) 36
(C) 38
(D) 40
(F) 42
For a discussion of how to handle with elegance both this question and distance in the x-y plane in general see this post. Other experts, feel free to share any other insights about elegance in x-y plane problems.
(A) 34
(B) 36
(C) 38
(D) 40
(F) 42
For a discussion of how to handle with elegance both this question and distance in the x-y plane in general see this post. Other experts, feel free to share any other insights about elegance in x-y plane problems.
Archit143
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Schools: Cox '16 (S) AGSM '16 Tulane '16 (S) McCombs '16 (S) Neeley '16 (S) Jones '16 (S) ISB '15 (D) MIT-LGO '16 (M)
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01 Nov 2012, 16:47
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i guess it fairly simple and straight fwd use of distance formula and intercept
JK = 5
LM = 11
KL =using distance formula 10
JM = using distance formula 8
Sum of all is 34
JK = 5
LM = 11
KL =using distance formula 10
JM = using distance formula 8
Sum of all is 34
abhinav11
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26 Oct 2013, 04:54
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mikemcgarry
Is there any shortcut to these type of questions than just calculating distance between two points and then adding all of them, that seems bit of time killer for me. But if we dont have any alternative we have to follow the approach.
Regards,
Abhinav
