Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 2211:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 23
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Nov 2510:00 AM EST
-11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
17 Jan 2021, 11:02
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
25% (02:26) correct
75%
(02:05)
wrong
based on 83
sessions
History
Date
Time
Result
Not Attempted Yet
Two persons agree to meet at between 2 PM to 4 PM, but each of them will wait 30 minutes for the late comer. What is the probability that they will meet ?
A. 7/8
B. 1/2
C. 7/16
D. 3/8
E. 7/32
Are You Up For the Challenge: 700 Level Questions: 700 Level Questions
A. 7/8
B. 1/2
C. 7/16
D. 3/8
E. 7/32
Are You Up For the Challenge: 700 Level Questions: 700 Level Questions
18 Jan 2021, 10:21
Kudos
Bookmarks
Bunuel
We can divide the time period into two parts:-
(1) Dark Red from 2:30 to 3:30 - If A as shown by indigo lines arrives in this period, then B has full 1 hour to come and meet A as shown within the red lines.
Probability of A is 2:30 to 3:30 in 2:00 to 4:00, so 1 hr in 2hr = \(\frac{1}{2}\)
Probability of B is also 1 hr in 2hr = \(\frac{1}{2}\)
Overall probability = \(\frac{1}{2}*\frac{1}{2}=\frac{1}{4}\)
(2) Turquoise/sky blue from 2:00 to 2:30 and 3:30 to 4:00 - If A as shown by indigo lines arrives in this period, then B has an average of 45 minutes to come and meet A as shown within the red lines. The time period moves from 30 minutes(when A comes at 2:00 or 4:00) to 60 minutes(when A comes at 2:30 or 3:30), so an average of 45 minutes.
Probability of A is 1 hr in 2hr = \(\frac{1}{2}\)
Probability of B is 45 minutes in 120 minutes = \(\frac{45}{120}=\frac{3}{8}\)
Overall probability = \(\frac{1}{2}*\frac{3}{8}=\frac{3}{16}\)
Final probability = \(\frac{1}{4}+\frac{3}{16}=\frac{7}{16}\)
C
Attachments
0Untitled.png [ 27.63 KiB | Viewed 8970 times ]
rocky620
Retired Moderator
Joined: 10 Nov 2018
Last visit: 11 May 2023
Posts: 501
Own Kudos:
Given Kudos: 229
Location: India
Concentration: General Management, Strategy
Schools: IIMA PGPX'22 IIMB EPGP'22 IIMC PGPEX'22 ISB'22
GMAT 1: 590 Q49 V22
WE:Other (Retail: E-commerce)
19 Jan 2021, 04:19
Kudos
Bookmarks
Hi chetan2u
I approached it as
Case-1 - Lets say A arrives at anytime between 2:00 - 3:30. With each passing minute B will have 30 minutes to come and they will meet.
So, probability = \(\frac{1.5}{2}\) = \(\frac{3}{4}\)
Case-2 - Lets say A arrives after 3:30. With each passing minute x, B will have (30-x) minutes to come and they will meet.
So, probability = \(\frac{30-x}{30}\)
But the value will depend on x.
I am confused how to proceed further in Case-2
Kindly help.
I approached it as
Case-1 - Lets say A arrives at anytime between 2:00 - 3:30. With each passing minute B will have 30 minutes to come and they will meet.
So, probability = \(\frac{1.5}{2}\) = \(\frac{3}{4}\)
Case-2 - Lets say A arrives after 3:30. With each passing minute x, B will have (30-x) minutes to come and they will meet.
So, probability = \(\frac{30-x}{30}\)
But the value will depend on x.
I am confused how to proceed further in Case-2
Kindly help.
