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relative speeds: \(\frac{350}{70}=5\) and \(\frac{350}{10}=35\)

\(a+b=35\), \(a-b=5\)

20m/s and 15m/s
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Hello,

Though the explanation to the given problem is simple, could someone explain with example, as I still find it difficult to intrepret, which train is 100m and which one is 250 m long?

Thnx in advance.
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priyalr
Hello,

Though the explanation to the given problem is simple, could someone explain with example, as I still find it difficult to intrepret, which train is 100m and which one is 250 m long?

Thnx in advance.

We can not deduce whether 100m train or 250m train is faster, we just know that the rate of a faster train, whichever it is, is 20 m/s and and the rate of a slower train is 15 m/s.

So, as you can see we can answer the question even not knowing whether 100m train or 250m train is faster. Refer to ANY solution above (they are basically all the same) to see how it can be done.

Hope it helps.
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Two trains of length 100m and 250m run on parallel lines. when they run in the same direction it will take 70 sec to cross each other and when they run in opposite direction, they take 10 sec to cross each other. find the speed of faster train.

We have

(a-b)(70) = (a+b)(10)

3a = 4b

We also know that (a-b)(70) = 350m
a-b =5

So a=20, b=15

The speed of the faster train is 20m/sec

Hope it helps
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J :)
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I thought too much, and figured out it be only 150 m to cross the other train in the same direction, if they start at the same time and if the longer train is faster


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I thought too much, and figured out it be only 150 m to cross the other train in the same direction, if they start at the same time and if the longer train is faster


Sent from my iPhone using GMAT Club Forum mobile app

I have the same question like yours. if they start at the same time, we have to assume that the shorter train is the faster one and the shorter need to cover only 150 m in order to catch up with the longer one.
Bunuel can you please clarify this for me?
Thank you in advance!
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I believe that, although the question isn’t entirely clear at first, when they go in the same direction, one train starts immediately behind the other train (don’t think it matters which train). Now the faster train has to make up the entire distance of the other train, plus get itself completely ahead of the other train in order to “cross”.

If the 100 meter train starts immediately behind the 250 meter train (and assuming the 100 meter train is faster), it must catch up through the 250 meter length of the other train. And also put its 150 meter length in front of the other train.

Am I correct in the way I’m interpreting the question?

It could also be the other way around, in which the 250 meter train is faster and starts out immediately behind the slower 100 meter train. Still going to be 350 meters until the entire train “crosses” the other train.

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Typo. “And also put its 100 meter length...”

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manojgmat
Two trains of length 100m and 250m run on parallel lines. when they run in the same direction it will take 70 sec to cross each other and when they run in opposite direction, they take 10 sec to cross each other. Find the speed of faster train.

A. 10 m/s
B. 15 m/s
C. 20 m/s
D. 25 m/s
E. 30 m/s

For the case - trains running in same direction, we need to specify the condition that the faster train is behind the slower train, otherwise they would never cross.
Can we edit question to make it more clear, otherwise we get two answers if we assume that both the trains are starting from same point when running in same direction.

cc: Bunuel
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