Vial V is 2/3 full of a certain solution and vial W, which has 50%

let the capacity of V = 6, then the capacity of W = 6+0.5*6=9

the amount of solution in V = (2/3)*6=4 and the half of it is 2 (4/2 )
the amount of solution in W = (3/4)*9=27/4

(half of solution in V + the amount of solution in W )/ capacity of W = (2+27/4)/9 =35/36
_________________

Hello,

Let me try helping you with this one.

It is mentioned in the question that the volume of W is 50% larger than the volume of V. Hence, W=\(\frac{3}{2}\)*V
This implies that V=\(\frac{2}{3}\)*W
Now, V is filled with 2/3 with the solution and W is filled 3/4 with the solution.
Half of the solution in V is filled into W. We need to find the fraction of W that is filled. So, we have to express everything in terms of W.

Half of the solution in V in terms of W is 1/3. When we express that in terms of W, it becomes

half the volume of solution in V=\(\frac{1}{3}\)*\(\frac{2}{3}\)*W
This is added to 3/4 of the volume W.
The total volume is (\(\frac{1}{3}\)*\(\frac{2}{3}\)*W)+(\(\frac{3}{4}\)*W)=\(\frac{35}{36}\)*W

Hence, the answer is E.

Hope this helps! Let me know if I could help you any further.

Similar questions to practice:
equal-amount-of-water-were-poured-into-two-empty-jars-of-98962.html
a-glucose-solution-contains-15-grams-of-glucose-per-140243.html
two-equally-sized-jugs-full-of-water-are-each-emptied-into-t-143944.html

Hope it helps.
_________________

Let capacity be denoted by "C"

V = C ===> currently filled = 2/3 C
Given : Capacity of W is 50% more than V

W = C + 0.5 C = 1.5 C ===> currently filled = 3/4(1.5C)

half of contents of V ==> 2/3C * 1/2 = 2/6C are then poured in W
Required to calculate the fraction to which W will be filled after half of contents of V are filled in W
2/6C +3/4(1.5C)/1.5C
Solving, we get
35/36

Ans:E

...........
just 30 seconds to solve with this techniques:

i worked with 24 and 36, as it seemed easier to work with...
24*2/3 = 16.
36*3/4 = 27

16/2 = 8
8+27 = 35.
we have 35/36

capacity of V = 10
and V is filled with 20/3
capacity of = 15
W is filled with 45/4
now 1/2 v is poured to W ; making capacity of W = 10/3 + 45/4 ; 175/12
making filled capacity of W to be 175/12 * 1/15 ;
\(\frac{35}{36}\)
OPTION E

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________