Vial V is 2/3 full of a certain solution and vial W, which has 50%

Question

Vial V is  \frac{2}{3}  full of a certain solution and vial W, which has 50% more capacity than vial V, is  \frac{3}{4}  full of the same solution. If half of the solution in vial V is poured into vial W, vial W will be filled to what fraction of its capacity?

(A)  \frac{27}{36}

(B)  \frac{10}{11}

(C)  \frac{11}{12}

(D)  \frac{23}{24}

(E)  \frac{35}{36}

I was able to solve it in under 2 mins, but curious to know if there is a 10-sec approach?

LalaB · Accepted Answer

let the capacity of V = 6, then the capacity of W = 6+0.5*6=9 the amount of solution in V = (2/3)*6=4 and the half of it is 2 (4/2

) the amount of solution in W = (3/4)*9=27/4 (half of solution in V + the amount of solution in W )/ capacity of W = (2+27/4)/9 =35/36

Kris01 · Answer

Hello,

Let me try helping you with this one.

It is mentioned in the question that the volume of W is 50% larger than the volume of V. Hence, W= \frac{3}{2} *V
This implies that V= \frac{2}{3} *W
Now, V is filled with 2/3 with the solution and W is filled 3/4 with the solution.
Half of the solution in V is filled into W. We need to find the fraction of W that is filled. So, we have to express everything in terms of W.

Half of the solution in V in terms of W is 1/3. When we express that in terms of W, it becomes

half the volume of solution in V= \frac{1}{3} * \frac{2}{3} *W
This is added to 3/4 of the volume W. 
The total volume is ( \frac{1}{3} * \frac{2}{3} *W)+( \frac{3}{4} *W)= \frac{35}{36} *W

Hence, the answer is E.

Hope this helps! Let me know if I could help you any further.

Bunuel · Answer

Similar questions to practice: equal-amount-of-water-were-poured-into-two-empty-jars-of-98962.html a-glucose-solution-contains-15-grams-of-glucose-per-140243.html two-equally-sized-jugs-full-of-water-are-each-emptied-into-t-143944.html Hope it helps.

GMAT40 · Answer

Let capacity be denoted by "C"

V = C ===> currently filled = 2/3 C
Given : Capacity of W is 50% more than V

W = C + 0.5 C = 1.5 C ===> currently filled = 3/4(1.5C)

half of contents of V ==> 2/3C * 1/2 = 2/6C are then poured in W
Required to calculate the fraction to which W will be filled after half of contents of V are filled in W
2/6C +3/4(1.5C)/1.5C
Solving, we get
35/36

Ans:E

Asifpirlo · Answer

...........
just 30 seconds to solve with this techniques:

mvictor · Answer

i worked with 24 and 36, as it seemed easier to work with...
24*2/3 = 16.
36*3/4 = 27

16/2 = 8
8+27 = 35.
we have 35/36

Archit3110 · Answer

capacity of V = 10
and V is filled with 20/3
capacity of = 15
 W is filled with 45/4
now 1/2 v is poured to W ; making capacity of W = 10/3 + 45/4 ; 175/12
making filled capacity of W to be 175/12 * 1/15 ; 
  \frac{35}{36} 
OPTION E

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Vial V is 2/3 full of a certain solution and vial W, which has 50%

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Vial V is 2/3 full of a certain solution and vial W, which has 50%

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