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Answer = C) 140

................. VIP ..................... Regular .................. Total

Price ........ 45 ......................... 15 ......................... 7500 (Total Amount)

Quantity ...... x ........................ 320-x ......................... 320 (Total sale)

We require to find 320-x-x = 320 - 2x

45x + 15(320-x) = 7500

x = 90

320 - 2x = 320 - 180 = 140
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My method is a little bit different, but it works fairly fast if you know how to do it.

If all the tickets sold were the $45 tickets, the amount would be $14,400.
If all the tickets sold were the $15 tickets, the amount would be $4,800.

You can then use the ratio trick to determine what the proper ratio should be for the total amount to equal $7,500:

4,800 --- 7,500 --- 14,400

The difference between those numbers and the 7,500 amount is 2,700 (7,500-4,800) and 6,900 (14,400-7,500). That means the ratio of $15 tickets to $45 tickets should be 6900:2700 (you flip the differences).

6900:2700 reduces to 69:27, which reduces to 23:9. To get 320 tickets sold, multiply by 10 to get 230:90. 230-90 = 140, which is the answer.

C
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VIP = V and General =G
Given V + G = 320 ---Eq1
and 45V + 15G = 7500 ---Eq2
Solving Eq1 and Eq2 => V= 90 , G =230 and G-V = 140.

Answer is C
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Bunuel

Tough and Tricky questions: Word Problems.



A snooker tournament charges $45.00 for VIP seats and $15.00 for general admission (“regular” seats). On a certain night, a total of 320 tickets were sold, for a total cost of $7,500. How many fewer tickets were sold that night for VIP seats than for general admission seats?

A) 70
B) 90
C) 140
D) 230
E) 250

Kudos for a correct solution.

Source: Chili Hot GMAT

The correct answer is C.
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