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01 Dec 2014, 05:32
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C
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Tough and Tricky questions: Word Problems.
A snooker tournament charges $45.00 for VIP seats and $15.00 for general admission (“regular” seats). On a certain night, a total of 320 tickets were sold, for a total cost of $7,500. How many fewer tickets were sold that night for VIP seats than for general admission seats?
A) 70
B) 90
C) 140
D) 230
E) 250
Kudos for a correct solution.
Source: Chili Hot GMAT
01 Dec 2014, 05:59
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let x be the number of VIP seats tickets sold and y be the number of general seats tickets sold.
x+y=320 ....... 1
45x+15y=7500 ......... 2
Divide eq 2 by 15
3x+y=500 ......... 3
eq3- eq1
2x=180
x=90
therefore, y=320-90
y=230
y-x= 230-90=140
Ans - C
x+y=320 ....... 1
45x+15y=7500 ......... 2
Divide eq 2 by 15
3x+y=500 ......... 3
eq3- eq1
2x=180
x=90
therefore, y=320-90
y=230
y-x= 230-90=140
Ans - C
intheend14
01 Dec 2014, 18:11
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This was a simultaneous equations question for me. Let v = VIP tickets and g = general admission.
We know that v + g = 320 (320 total tickets sold) and 45v + 15g = 7500 (total cost of all the tickets. Now, lets reduce this second equation to make things easier by dividing it by 15: 3v + g = 500.
Let's do equation 2 - equation 1 to get (3v-v) + (g-g) = 500-320, this yields 2v = 180 or v = 90 (90 VIP tickets sold), which means that 320-90=g=230 general admission tickets sold. The difference is 140, which is Choice C.
We know that v + g = 320 (320 total tickets sold) and 45v + 15g = 7500 (total cost of all the tickets. Now, lets reduce this second equation to make things easier by dividing it by 15: 3v + g = 500.
Let's do equation 2 - equation 1 to get (3v-v) + (g-g) = 500-320, this yields 2v = 180 or v = 90 (90 VIP tickets sold), which means that 320-90=g=230 general admission tickets sold. The difference is 140, which is Choice C.
