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ans C..
let the smaller be y , higher will be y+37... so y+y+37=x or y=(x-37)/2..
now z is added on y...therefore height will be y+z or (x-37)/2+z
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Lets assume taller h1 and the shorter high is h2:

As problem says h1+h2=x & h1=h2+37,

We replace these two relations in the equation and we have h2+h2+37=x OR : 2h2+37=x and after adding z to the x , we have 2h2+37=x

Or : 2h2= x-37 and finally we get :h2= (x-37)/2+z

so the shorter h2 is (x-37)/2 +z answer c :lol: :lol: :lol:
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Bunuel
The sum of the heights of two high-rises is x feet. If the first high rise is 37 feet taller than the second, how tall will the second high rise be after they add an antenna with a height of z feet to the top?

A. (x+z)/2 + 37
B. 2x−(37+z)
C. (x−37)/2 + z
D. x/2 - 37 + z
E. (2x−37)/z


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The OA will be revealed on Sunday

call height_1 H, call height_2 K.

H+K=x ---> 2K+37=x ---> K=x-37/2 add the antenna and you get answer C
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Bunuel
The sum of the heights of two high-rises is x feet. If the first high rise is 37 feet taller than the second, how tall will the second high rise be after they add an antenna with a height of z feet to the top?

A. (x+z)/2 + 37
B. 2x−(37+z)
C. (x−37)/2 + z
D. x/2 - 37 + z
E. (2x−37)/z


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let b+z=height of second building with antenna
x=2b+37➡
2b=x-37➡
b=(x-37)/2
b+z=(x-37)/2+z
C
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The sum of the heights of two high-rises is x feet. If the first high rise is 37 feet taller than the second, how tall will the second high rise be after they add an antenna with a height of z feet to the top?

Let the height of 2nd high rise = h
Therefore, the height of 1st high rise = h + 37
=> h + h + 37 = x
=> 2h + 37 = x
=> h= (x-37)/2

The height of 2nd high rise after adding antenna = h + z = (x-37)/2 + z

Hence C
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